If 3+5+7+........ to n terms/ 5+8+11+.........to …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Harmehar Malhotra 7 years, 2 months ago
- 1 answers
Related Questions
Posted by Narinder Singh 2 days, 20 hours ago
- 0 answers
Posted by Rohini Sharma an hour ago
- 0 answers
Posted by B Vv 4 days, 2 hours ago
- 2 answers
Posted by Vivek Verma 7 minutes ago
- 0 answers
Posted by Shraddha Bhadauriya 1 day, 15 hours ago
- 0 answers
Posted by Rishi Jha 2 days, 17 hours ago
- 0 answers
Posted by Subhalaxmi Panda 2 days ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Bindu Agarwal 7 years, 2 months ago
Both the numerator and denominator are the sums of two series up to 'n' terms:-
Since the sum = (n/2)(2a+(n-1)d)
For series in the numerator :-
a=3, d=2, n=n
Therefore numerator = (n/2)*(6+(n-1)2) = (n/2)*(2n+4)
And for the denominator series:-
a=5, d=3, n=10
Therefore denominator = (10/2)*(10+(10-1)3) = (n/2)*(3n+7) = 185
Therefore Acc. to question:-
(n/2)*(2n+4) / (185) = 7
= n2 +2n- 1295 = 0
= n2 + 37n - 35n - 1295 = 0
=n=35 ( Since ncan not be equal to 37)
2Thank You