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Show that f:A--B defined by f(x)= …

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Show that f:A--B defined by f(x)= x-2/x-3 is bijective where A=R-{3} & B=R-{1}
  • 1 answers

Ashish Kr Pandey 7 years, 10 months ago

F(x1) = F(x2) x1-2/x1-3 = x2-2/x2-3 x1.x2 - 3.x1 - 2.x2+ 6 = x1.x2 - 2.x1 - 3.x2 +6 after solving, x1 = x2 so it is one - one function. Y = x-2/x-3 If you can make the function of x in terms of Y,then you get :- X = 2-3Y/1-Y,whose y is not equals to 1. Therefore codomain = Range So function is onto also. Now you can say that function is bijective. Your questions is solved. Thank you for asking.
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