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{[Cos2π\7. -sin2π\7] \ [sin2π|7. Cos2π\7]}^k =[1\o. …

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{[Cos2π\7. -sin2π\7] \ [sin2π|7. Cos2π\7]}^k =[1\o. 0\1 ] then find value of k?

    • Posted by Lalit Sh 7 years, 10 months ago

    CBSE > Class 12 > Mathematics
    • 0 answers
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