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Differentiate log tan inverse x

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Differentiate log tan inverse x
  • 7 answers

Hitesh Kumar 7 years, 10 months ago

Pata hai mujhe vo maine differentiation nahi dekh tha maine socha integration hai. Qki differentiation to easy hota hai isliye at first maine socha integration karna hoga. But maine baad me dekha differentiation he karna hai??

Aparna Sharma 7 years, 10 months ago

And as it is differentiation not integration so you need not use any ILATE

Aparna Sharma 7 years, 10 months ago

1/((1+x^2)(tan^-1 x))

Hitesh Kumar 7 years, 10 months ago

Sorry sorry??? I didn't saw that sorry
1/(tan-¹x×(1+x²))
Lol differentiate karna hai

Hitesh Kumar 7 years, 10 months ago

∫log(tan−1(x))dx Let tan−1(x)=t⇒1/1+x2dx=dt.....(i) Also x =\tan(t) .......(ii) Therefore ( by using (ii)): ∫log(tan−1(x))dx=∫log(t).(1+tan2(t))dt=∫(log(t)+log(t)tan2(t))dt=∫(log(t)+log(t)sec2(t)−log(t))dt=∫log(t)sec2(t)dt iske baad ILATE ka use karke ans aa jaiga
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