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Integration of cos2x log(sinx) dx

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Integration of cos2x log(sinx) dx

Posted by Suruchi Arora 7 years, 5 months ago

CBSE > Class 12 > Mathematics

1 answers

Deepak Jha 7 years, 5 months ago

(using by part) int.cos2x log(sinx) =logsinx int.cos2x dx-int.(d/dxlogsinx int.cos2x) =logsinx sin2x/2-(cosx/sinx sin2x/2) =logsinx sin2x/2-(cosx/sinx 2sinx cosx/2) =logsinx sin2x/2-(cos squrex) =where cos2x=2cos squrex-1 = cos2x/2+1/2 =logsinx sin2x/2-(sin2x/4+(x/2)+c) Ans??

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