Which term of AP 121,117,113.................is its …
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Naveen Sharma 7 years, 3 months ago
a = 121
d = -4
let an= 0
then
an = a + (n-1)d
=> 0 = 121 + (n-1)(-4)
=> 0 = 121 - 4n + 4
=> 4n = 125
=> n = 125/4
=> n = 31.25
as n must be natural number then n= 32
32nd term is First negative number.
a32 = 121 + (31)-4
= 121 - 124 = -3
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