Factorise 8a3 +√27b3. (The 3 after …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Shitij Vinu 6 years, 3 months ago
- 2 answers
Rajeev Malhotra 6 years, 3 months ago
Your question is wrong. The correct question is 8a3 +27 b3.
8a3 + 27 b3 = (2a)3 + (3b)3 = (2a +3b)(4a2-6ab +9b2)
Related Questions
Posted by Jagannathan Ramesh 2 days, 20 hours ago
- 0 answers
Posted by Gagan Yadav 2 days, 1 hour ago
- 1 answers
Posted by Lucky Pandey Apoorv Pandey 3 days, 4 hours ago
- 2 answers
Posted by Ananya Singh 9 minutes ago
- 0 answers
Posted by Subhash Chand 2 days, 1 hour ago
- 0 answers
Posted by Kulsum Farhan 59 minutes ago
- 2 answers
Posted by Naman Jain 1 day, 22 hours ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Hirtic Selvavinayagam 5 years, 2 months ago
0Thank You