Factorise 8a3 +√27b3. (The 3 after …

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Posted by Shitij Vinu 8 years, 3 months ago
- 2 answers
Rajeev Malhotra 8 years, 3 months ago
Your question is wrong. The correct question is 8a3 +27 b3.
8a3 + 27 b3 = (2a)3 + (3b)3 = (2a +3b)(4a2-6ab +9b2)
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Hirtic Selvavinayagam 7 years, 1 month ago
0Thank You