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Factorise 8a3 +√27b3. (The 3 after …

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Factorise 8a3 +√27b3. (The 3 after a and b are cubes)
  • 2 answers

Hirtic Selvavinayagam 6 years, 9 months ago

u r wrong, it is root 27

Rajeev Malhotra 7 years, 11 months ago

Your question is wrong. The correct question is 8a3 +27 b3.

8a3 + 27 b3 = (2a)3 + (3b)3 = (2a +3b)(4a2-6ab +9b2)

 

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