Why is oxidation no of CO …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Rock Star 8 years, 4 months ago
- 1 answers
Test
Related Questions
Posted by Shikhar Manav 1 year, 6 months ago
- 0 answers
Posted by Priya Dharshini B 1 year, 5 months ago
- 4 answers
Posted by Mahi Sharma 1 year, 6 months ago
- 0 answers
Posted by Kashish Baisla 9 months, 3 weeks ago
- 1 answers
Posted by Prity Rani Mishra 1 year, 6 months ago
- 0 answers
Posted by Bhavishaya 2009 1 year, 6 months ago
- 0 answers
Posted by Karan Kumar Mohanta 1 year, 5 months ago
- 1 answers
Posted by Roshni Gupta 1 year, 6 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Dr. Kamlapati Bhatt 8 years, 4 months ago
Usually , we refer oxidation state of an atom in a molecule . Since CO ( Carbon - mono - oxide ) is a molecule in itself ,therefore applying the IUPAC rule for calculating oxidation number , it has an oxidation state = 0
The zero oxidation state of CO is confirmed mathematically also as per following calculations ,
Since there is no per - oxide ( - O - O - ) linkage in the structure of CO , the oxidation number of O atom in CO is = -2
The oxidation number of C in CO is , therefore , = +2 ,
(because sum of the oxidation number of all the atoms in a molecule = 0 )
Thus , Oxidation number of CO = ( Oxidation number of C + Oxidation number of O )
= [( +2 ) + ( -2 )]
= 0
1Thank You