Since the trigonometric functions are defined …

Since the trigonometric functions are defined in right triangles like(opp side/hypotenuse) How is it possible to find values for trigonometric functions with greater angles like 270,175,etc since in the first case a triangle cant be formed with one of its angle as 270 degrees and in the second case a right triangle cant be formed with one of its angle as 175 degrees. Though trigonometric functions has corresponding values for such angles. Then how is it defined i.e, by what kind of relation is the angle in the domain connected to its corresponding value in the range? Moreover what does the values of angles greater than signify?And what was the reason or motive to expand trigonometry beyond 90 degrees? There should be something right ;) since everything in mathematics was invented out of practical needs

Project on to minimise the cost of the food, meeting the dietary requirements of the staple food of the adolescent students of your school. Task to be done 1. Make a survey of atleast 100 people to find the staple food they consume on daily basis. 2. Select two food items constituting one cereal and one pulse. 3. Find from dietician minimum requirement of protein and carbohydrates for an andolescent and also find the content of protein and carbohydrates in 1 Kg of selected cereal and pulse from the market. 4. Find the minimum cost of the selected cereal and pulse from market. 5. formulate the corresponding linear programming problem. 6. solve the problem graphically. 7. Interpret the result.

Find all vectors of magnitude 10√3 that are perpendicular to the plane of i+2j+k and -i+3j+4k

function f is defined as f(x) = {2x+2, x<2; k, x=2; 3x, x>2} find the value of k for which the function f is continuous at x=2

Find the second order derivatives of the functions x²+3x+2

Y=sin√ax^2+√bx+√c

Y= 1/2 [tan¯¹(2x/1-x²) + 2tan¯¹(1/x)

Three friends Ravi Raju

What is the maximum value of the function sin x + cosx

What is the maximum value of sinx + cos x

Prove that tan–¹ (x+1) + tan–¹(x-1) = tan–¹ 8/31