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Sia ? 6 years, 9 months ago
Using Distance formula, we have
{tex}10 = \sqrt {{{(2 - 10)}^2} + {{( - 3 - y)}^2}} {/tex}
{tex} \Rightarrow 10 = \sqrt {{{( - 8)}^2} + 9 + {y^2} + 6y} {/tex} {tex}{/tex}
{tex} \Rightarrow 10 = \sqrt {64 + 9 + {y^2} + 6y} {/tex}
Squaring both sides, we get
100 = 73 + y2 + 6y
⇒ y2 + 6y - 27 = 0
Solving this Quadratic equation by factorization, we can write
⇒ y2 + 9y − 3y - 27 = 0
⇒ y(y + 9) - 3(y + 9) = 0
⇒ (y + 9)(y − 3) = 0
⇒ y = 3, −9
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