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Using differential find the value of …

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Using differential find the value of (0.009)1/3

    • Posted by Khilesh Kurrey 8 years ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Nancy Jain 8 years ago

    Let us assume f(x)= (x)^1/3 Break 0.009 as x=1 and Δx=-0.991 f'(x) =1/3 (x)^-2/3 Now using differential method, F(x+Δx) = f(x) + Δx. f'(x) = (x) ^1/3 + (-0.991)* 1/3 (x) ^-2/3 = (1)^ 1/3 - 0.991 * 1/3 x^2/3 = 1- 0.991/3*1 = 1-0.33 = 0.67

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