4sin theta =3 cos theta find …
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Sahdev Sharma 7 years, 10 months ago
Given : 4sinθ=3cosθ
=> sinθcosθ=34
=> tanθ=34
To find : 12sinθ−7cosθ8sinθ+3cosθ
Divide numerator and denominator by cosθ, we get
12tanθ−78tanθ+3
= 9−76+3=29
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