4sin theta =3 cos theta find …
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Sahdev Sharma 6 years, 8 months ago
Given : {tex}4 sin \theta = 3 cos \theta {/tex}
=> {tex}{sin\theta\over cos\theta }= {3\over 4}{/tex}
=> {tex}tan \theta = {3\over 4}{/tex}
To find : {tex}{12sin\theta - 7cos \theta\over 8 sin \theta+ 3 cos\theta}{/tex}
Divide numerator and denominator by {tex}cos \theta {/tex}, we get
{tex}12 tan\theta - 7\over 8 tan \theta + 3{/tex}
= {tex}{9-7\over 6+3}={ 2\over 9}{/tex}
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