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If tan inverse (x^2-y^2)/(x^2+y^2)=alpha prove that …

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If tan inverse (x^2-y^2)/(x^2+y^2)=alpha prove that dy/dx=x (1-tan alpha)/y (1+tan alpha)
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Taking both side tangent Then apply commonendo and dividendo After solving or arrangment ....differentiate wrt x
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