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# NCERT Solutions for Class 8 Maths Exercise 3.2

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NCERT solutions for Class 8 Maths Understanding Quadrilaterals

## NCERT Solutions for Class 8 Maths Understanding Quadrilaterals

###### 1. Find  in the following figures:

Ans. (a) Here,

[Linear pair]

And

[Linear pair]

{tex}\because {/tex} Exterior angle

= Sum of opposite interior angles

{tex}\therefore {/tex}

(b) Sum of angles of a pentagon

=

=

=

By linear pairs of angles,

……….(i)

……….(ii)

……….(iii)

……….(iv)

……….(v)

Adding eq. (i), (ii), (iii), (iv) and (v),

NCERT Solutions for Class 8 Maths Exercise 3.2

###### 2. Find the measure of each exterior angle of a regular polygon of:

(a) 9 sides

(b) 15 sides

Ans. (i) Sum of angles of a regular polygon =

=

Each interior angle =

Each exterior angle =

(ii) Sum of exterior angles of a regular polygon =

Each interior angle =

###### 3. How many sides does a regular polygon have, if the measure of an exterior angle is

Ans. Let number of sides be

Sum of exterior angles of a regular polygon =

Number of sides =

Hence, the regular polygon has 15 sides.

NCERT Solutions for Class 8 Maths Exercise 3.2

###### 4. How many sides does a regular polygon have if each of its interior angles is

Ans. Let number of sides be

Exterior angle =

Sum of exterior angles of a regular polygon =

Number of sides =

Hence, the regular polygon has 24 sides.

###### 5. (a) Is it possible to have a regular polygon with of each exterior angle as

(b) Can it be an interior angle of a regular polygon? Why?

Ans. (a) No. (Since 22 is not a divisor of )

(b) No, (Because each exterior angle is  which is not a divisor of )

NCERT Solutions for Class 8 Maths Exercise 3.2

###### 6. (a) What is the minimum interior angle possible for a regular polygon? Why?

(b) What is the maximum exterior angle possible for a regular polygon?

Ans. (a) The equilateral triangle being a regular polygon of 3 sides has the least measure of an

interior angle of {tex}{{60}^{\circ }}.{/tex}

{tex}\because {/tex} Sum of all the angles of a triangle

= {tex}180{}^\circ {/tex}

{tex}\therefore {/tex}

(b) By (a), we can observe that the greatest exterior angle is

.

## NCERT Solutions for Class 8 Maths Exercise 3.2

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