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**NCERT solutions for Class 8 Maths Comparing Quantities Download as PDF**

## NCERT Solutions for Class 8 Maths Comparing Quantities

**Class –VIII Mathematics (Ex. 8.2)**

**NCERT SOLUTION**

**1. A man got 10% increase in his salary. If his new salary is Rs.1,54,000, find his original salary.**

**Ans. **Let original salary be Rs.100.

Therefore New salary i.e., 10% increase

= 100 + 10 = Rs.110

New salary is Rs.110, when original salary = Rs.100

New salary is Rs.1, when original salary =

New salary is Rs.1,54,000, when original salary = = Rs.1,40,000

Hence original salary is Rs. 1,40,000.

NCERT Solutions for Class 8 Maths Exercise 8.2

**2. On Sunday 845 people went to the Zoo. On Monday only 169 people went. What is the percent decrease in the people visiting the Zoo on Monday?**

**Ans. **On Sunday, people went to the Zoo

= 845

On Monday, people went to the Zoo = 169

Number of decrease in the people

= 845 – 169 = 676

Decrease percent = = 80%

Hence decrease in the people visiting the Zoo is 80%.

**3. A shopkeeper buys 80 articles for Rs.2,400 and sells them for a profit of 16%. Find the selling price of one article.**

**Ans. **No. of articles = 80

Cost Price of articles = Rs. 2,400And Profit

= 16%

Cost price of articles is Rs.100, then selling price = 100 + 16 = Rs.116

Cost price of articles is Rs.1, then selling price =

Cost price of articles is Rs.2400, then selling price = = Rs.2784

Hence, Selling Price of 80 articles = Rs.2784

Therefore Selling Price of 1 article

= = Rs.34.80

**4. The cost of an article was Rs.15,500, Rs.450 were spent on its repairs. If it sold for a profit of 15%, find the selling price of the article.**

**Ans. **Here, C.P. = Rs.15,500 and Repair cost = Rs.450

Therefore Total Cost Price = 15500 + 450 = Rs.15,950

Let C.P be Rs.100, then S.P. = 100 + 15

= Rs.115

When C.P. is Rs.100, then S.P. = Rs.115

When C.P. is Rs.1, then S.P. =

When C.P. is Rs.15950, then S.P.

= = Rs.18,342.50

NCERT Solutions for Class 8 Maths Exercise 8.2

**5. A VCR and TV were bought for Rs.8,000 each. The shopkeeper made a loss of 4% on the VCR and a profit of 8% on the TV. Find the gain or loss percent on the whole transaction.**

**Ans. **Cost price of VCR = Rs.8000 and Cost price of TV = Rs.8000

Total Cost Price of both articles

= Rs.8000 + Rs.8000 = Rs. 16,000

Now VCR is sold at 4% loss.

Let C.P. of each article be Rs.100, then S.P. of VCR = 100 – 4 = Rs.96

When C.P. is Rs.100, then S.P. = Rs.96

When C.P. is Rs.1, then S.P. =

When C.P. is Rs.8000, then S.P.

= = Rs.7,680

And TV is sold at 8% profit, then S.P. of TV = 100 + 8 = Rs.108

When C.P. is Rs.100, then S.P. = Rs.108

When C.P. is Rs.1, then S.P. =

When C.P. is Rs.8000, then S.P.

= = Rs.8,640

Then, Total S.P.

= Rs.7,680 + Rs.8,640 = Rs. 16,320

Since S.P. >C.P.,

Therefore Profit = S.P. – C.P.

= 16320 – 16000 = Rs.320

And Profit% =

== 2%

NCERT Solutions for Class 8 Maths Exercise 8.2

**6. During a sale, a shop offered a discount of 10% on the marked prices of all the items. What would a customer have to pay for a pair of jeans marked at Rs.1450and two shirts marked at Rs.850 each?**

**Ans. **Rate of discount on all items = 10%

Marked Price of a pair of jeans = Rs.1450 and Marked Price of a shirt = Rs.850

Discount on a pair of jeans

= = Rs.145

S.P. of a pair of jeans = Rs.1450 – Rs.145

= Rs.1305

Marked Price of two shirts =

= Rs.1700

Discount on two shirts =

= Rs.170

S.P. of two shirts = Rs.1700 – Rs.170

= Rs.1530

Therefore the customer had to pay

= 1305 + 1530

= Discount on a pair of jeans

=

= Rs.145

S.P. of a pair of jeans

= Rs.1450 – Rs.145 = Rs.2,835

NCERT Solutions for Class 8 Maths Exercise 8.2

**37. A milkman sold two of his buffaloes for Rs.20,000 each. On one he made a gain of 5% and on the other a loss of 10%. Find his overall gain or loss. (Hint: Find CP of each)**

**Ans. **S.P. of each buffalo = Rs.20,000

S.P. of two buffaloes =

= Rs.40,000

One buffalo is sold at 5% gain.

Let C.P. be Rs.100, then S.P. = 100 + 5

= Rs.105

When S.P. is Rs.105, then C.P. = Rs.100

When S.P. is Rs.1, then C.P. =

When S.P. is Rs.20,000, then C.P.

= = Rs.19,047.62

Another buffalo is sold at 10% loss.

Let C.P. be Rs.100, then S.P. = 100 – 10

= Rs.90

When S.P. is Rs.90, then C.P. = Rs.100

When S.P. is Rs.1, then C.P. =

When S.P. is Rs.20,000, then C.P.

= = Rs.22,222.22

Total C.P. = Rs.19,047.62 + Rs.22,222.22

= Rs.41,269.84

Since C.P. >S.P.

Therefore here it is loss.

Loss = C.P. – S.P.

= Rs.41,269.84 – Rs. 40,000.00 = Rs.1,269.84

NCERT Solutions for Class 8 Maths Exercise 8.2

**8. The price of a TV is Rs.13,000. The sales tax charged on it is at the rate of 12%. Find the amount that Vinod will have to pay if he buys it.**

**Ans. **C.P. = Rs.13,000 and S.T. rate = 12%

Let C.P. be Rs.100, then S.P. for purchaser

= 100 + 12 = Rs.112

When C.P. is Rs.100, then S.P. = Rs.112

When C.P. is Rs.1, then S.P. =

When C.P. is Rs.13,000, then S.P.

= = Rs.14,560

NCERT Solutions for Class 8 Maths Exercise 8.2

**9. Arun bought a pair of skates at a sale where the discount given was 20%. If the amount he pays is Rs.1,600, find the marked price.**

**Ans. **S.P. = Rs.1,600 and Rate of discount

= 20%

Let M.P. be Rs.100, then S.P. for customer

= 100 – 20 = Rs.80

When S.P. is Rs.80, then M.P. = Rs.100

When S.P. is Rs.1, then M.P. =

When S.P. is Rs.1600, then M.P.

= = Rs.2,000

NCERT Solutions for Class 8 Maths Exercise 8.2

**10. I purchased a hair-dryer for Rs.5,400 including 8% VAT. Find the price before VAT was added.**

**Ans. **C.P. = Rs.5,400 and Rate of VAT = 8%

Let C.P. without VAT is Rs. 100, then price including VAT = 100 + 8 = Rs.108

When price including VAT is Rs.108, then original price = Rs.100

When price including VAT is Rs.1, then original price =

When price including VAT is Rs.5400, then original price = = Rs.5000

## NCERT Solutions for Class 8 Maths Exercise 8.2

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