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NCERT Solutions for Class 8 Maths Exercise 16.1

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NCERT Solutions for Class 8 Maths Exercise 16.1 Class 8 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 8 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free

NCERT solutions for Class 8 Maths Playing with Numbers Download as PDF

NCERT Solutions for Class 8 Maths Exercise 16.1

NCERT Solutions for Class 8 Maths Playing with Numbers

Class –VIII Mathematics (Ex. 16.1)
NCERT SOLUTION
Find the values of the letters in each of the following and give reasons for the steps involved.

1.

Ans. On putting A = 1, 2, 3, 4, 5, 6, 7 and so on and we get, 7 + 5 = 12 in which ones place is 2.

A = 7

And putting 2 and carry over 1, we get

B = 6

Hence A = 7 and B = 6


2.

Ans. On putting A = 1, 2, 3, 4, 5, 6, 7 and so on and we get,8 + 5 = 13 in which ones place is 3.

 A = 5

And putting 3 and carry over 1, we get

B = 4 and C = 1

Hence A = 5, B = 4 and C = 1


NCERT Solutions for Class 8 Maths Exercise 16.1

3.

Ans.  On putting A = 1, 2, 3, 4, 5, 6, 7 and so on and we get, A x A = 6 x 6 = 36 in which ones place is 6.

 A = 6

Hence A = 6


NCERT Solutions for Class 8 Maths Exercise 16.1

4.

Ans. Here, we observe that B = 5

so that 7 + 5 = 12.

Putting 2 at ones place and carry over 1 and A = 2, we get

2 + 3 + 1 = 6

Hence A = 2 and B = 5


5.

Ans. Here on putting B = 0,

we get 0  3 = 0.

And A = 5, then 5 3 = 15

 A = 5 and C = 1

Hence A = 5, B = 0 and C = 1


NCERT Solutions for Class 8 Maths Exercise 16.1

6.

Ans. On putting B = 0, we get 0 , 5 = 0 and A = 5, then 5 5 = 25

 A = 5, C = 2

Hence A = 5, B = 0 and C = 2


NCERT Solutions for Class 8 Maths Exercise 16.1

7.

Ans.  Here product of B and 6 must be same as ones place digit as B.

6  1 = 6, 6  2 = 12, 6  3 = 18,

6  4 = 24

On putting B = 4, we get the ones digit 4 and remaining two B’s value should be 44.

 For 6  7 = 42 + 2 = 44

Hence A = 7 and B = 4


8.

Ans. On putting B = 9, we get 9 + 1 = 10

Putting 0 at ones place and carry over 1, we get

For A = 7  7 + 1 + 1 = 9

Hence A = 7 and B = 9


NCERT Solutions for Class 8 Maths Exercise 16.1

9.

Ans. On putting B = 7,

 7 + 1 = 8

Now A = 4, then 4 + 7 = 11

Putting 1 at tens place and carry over 1, we get

2 + 4 + 1 = 7

Hence A = 4 and B = 7


NCERT Solutions for Class 8 Maths Exercise 16.1

10.

Ans. Putting A = 8 and B = 1, we get

8 + 1 = 9

Now again we add 2 + 8 = 10

Tens place digit is ‘0’ and carry over 1.

Now 1 + 6 + 1 = 8 = A

Hence A = 8 and B = 1

NCERT Solutions for Class 8 Maths Exercise 16.1

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