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NCERT Solutions for Class 8 Maths Exercise 11.1 Class 8 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 8 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.

**NCERT solutions for Class 8 Maths Mensuration Download as PDF**

## NCERT Solutions for Class 8 Maths Mensuration

**Class –VIII Mathematics (Ex. 11.1)**

**NCERT SOLUTION**

**1. A square and a rectangular field with measurements as given in the figure have the same perimeter. **

**Which field has a larger area?**

**Ans.** Given: The side of a square = 60 m

And the length of rectangular field = 80 m

According to question,

Perimeter of rectangular field

= Perimeter of square field

= 4 side

m

Now Area of Square field

=

= = 3600 m^{2}

And Area of Rectangular field

= length breadth = 80 40

= 3200

Hence, area of square field is larger.

NCERT Solutions for Class 8 Maths Exercise 11.1

**2. Mrs. Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of ` 55 **

**per m ^{2}.**

**Ans.** Side of a square plot = 25 m

Area of square plot =

= = 625 m^{2}

Length of the house = 20 m and

Breadth of the house = 15 m

Area of the house = length breadth

= 20 15 = 300 m^{2}

Area of garden = Area of square plot

– Area of house

= 625 – 300 = 325 m^{2}

Cost of developing the garden per sq. m = ` 55

Cost of developing the garden 325 sq. m = ` 55 325

= ` 17,875

Hence total cost of developing a garden around is ` 17,875.

NCERT Solutions for Class 8 Maths Exercise 11.1

**3. The shape of a garden is rectangular in the middle and semi-circular at the ends as shown in the diagram. Find the area and the perimeter of this garden [Length of rectangle is 20 – (3.5 + 3.5 meters]**

**Ans.** Given: Total length = 20 m

Diameter of semi circle = 7 m

Radius of semi circle = = 3.5 m

Length of rectangular field

= 20 – (3.5 + 3.5) = 20 – 7 = 13 m

Breadth of the rectangular field = 7 m

Area of rectangular field =

= 13 7 = 91

Area of two semi circles =

= = 38.5 m^{2}

Area of garden = 91 + 38.5 = 129.5 m^{2}

Now Perimeter of two semi circles = = 22 m

And Perimeter of garden

= 22 + 13 + 13

= 48 m

NCERT Solutions for Class 8 Maths Exercise 11.1

**4. A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080? [If required you can split the tiles in whatever way you want to fill up the corners]**

**Ans.** Given: Base of flooring tile = 24 cm

= 0.24 m

Corresponding height of a flooring tile

= 10 cm = 0.10 m

Now Area of flooring tile

= Base Altitude

= 0.24 0.10

= 0.024 m^{2}

Number of tiles required to cover the floor

=

=

= 45000 tiles

Hence 45000 tiles are required to cover the floor.

NCERT Solutions for Class 8 Maths Exercise 11.1

**5. An ant is moving around a few food pieces of different shapes scattered on the floor. For which food-piece would the ant have to take a longer round? Remember, circumference of a circle can be obtained by using the expression ****where is the radius of the circle.**

**Ans.** **(a)** Radius =

= 1.4 cm

Circumference of semi circle =

= = 4.4 cm

Total distance covered by the ant

= Circumference of semi circle + Diameter

= 4.4 + 2.8 = 7.2 cm

**(b)** Diameter of semi circle = 2.8 cm

Radius = = 1.4 cm

Circumference of semi circle =

= = 4.4 cm

Total distance covered by the ant

= 1.5 + 2.8 + 1.5 + 4.4 = 10.2 cm

**(c)** Diameter of semi circle = 2.8 cm

Radius =

= 1.4 cm

Circumference of semi circle =

= = 4.4 cm

Total distance covered by the ant

= 2 + 2 + 4.4 = 8.4 cm

Hence for figure (b) food piece, the ant would take a longer round.

## NCERT Solutions for Class 8 Maths Exercise 11.1

NCERT Solutions Class 8 Mathematics PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 8 Mathematics includes text book solutions from Class 8 Maths Book . NCERT Solutions for CBSE Class 8 Maths have total 16 chapters. 8 Maths NCERT Solutions in PDF for free Download on our website. Ncert class 8 solutions PDF and Maths ncert class 8 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

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