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Define electrostatic potential difference between two points in an electric field .ls it scalar or vector quantity.

Posted by Rajiv Singh 5 years, 3 months ago

1 answers

The potential difference is expressed in volt (V). The potential difference between two points is said to be 1 volt if the work is done in moving 1-coulomb charge from one point to other is 1 joule. It is scalar quantity....

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Find electric field intensity due to plane charged surface

Posted by Manojkumar Samal 5 years, 3 months ago

CBSE > Class 12 > Physics

1 answers

Khushi....? ??‍? 5 years, 3 months ago

E= (sigma ×l)/2€°

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Testing app mycbseguide

Posted by Kavita Rawat 5 years, 3 months ago

CBSE > Class 12 > Physics

1 answers

Khushi....? ??‍? 5 years, 3 months ago

What do you mean to say

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Vsisnukswmdbisnabgs

Posted by Kavita Rawat 5 years, 3 months ago

CBSE > Class 12 > Physics

0 answers

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A potential difference V is applied across the ends of copper wire of length l and diameter d.What is effect on drift velocity if 1)V is halved 2)I is doubled

Posted by Sai Mohan 5 years, 3 months ago

CBSE > Class 12 > Physics

1 answers

Mishti ???? 5 years, 3 months ago

Solution~~ Drift velocity = v_drift = I / (neA) = J/(ne) = V/(neA R) = V/(neρl) I = current n = num of electrons per unit volume (constant for copper e = electron charge A = area of cross section = π D²/4 R = resistance of wire ρ = resistivity l = length of wire Thus, i) When V is doubled, drift velocity is doubled. 2) l is doubled then velocity is halved , if V remain same. Regards. ??

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What is net force on o point ∆

Posted by Hani Prajapati 5 years, 3 months ago

CBSE > Class 12 > Physics

1 answers

Mishti ???? 5 years, 3 months ago

O point mean?????

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At a given temprature the pressure of gas

Posted by Ayush Sharma 5 years, 3 months ago

CBSE > Class 12 > Physics

2 answers

Devil ? 5 years, 3 months ago

How ?? Misthi ??

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Mishti ???? 5 years, 3 months ago

Answer~~ At a given temperature, the pressure of a gas reduces to 75 percent of its initial value and the volume increases by 40 percent of its initial value. Regards. ??

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Two parallel uniformly charged infinite plane sheets l 'and' 2 'have charge densities to and -20 respectively. Given the magnitude and direction of the net electric field at a point (i) between the two sheets and (ii) the sheet '1' outside.

Posted by Sai Koushik 5 years, 3 months ago

CBSE > Class 12 > Physics

0 answers

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An electric dipole is placed at an angle of 60° with an electric field of magnitude 4×10'5N/C.it experience a torque of 8√3 Nm.if the length of dipole is 2cm determine thr magnitude of either charge of dipole

Posted by Prajakta Shinde 5 years, 3 months ago

CBSE > Class 12 > Physics

2 answers

Gaurav Seth 5 years, 3 months ago

Electric field strength = E = [τ/(P sin θ)]

where P is dipole moment

∴ 10⁵ = [(8√3)/(P sin 60)]

∴ P = [(8√3)/{(√3/2) × 10⁵}] = 16 × 10^–5c–m

as P = q ∙ (2ℓ)

here 2ℓ = length of dipole = 2 × 10^–2 m

∴ q = (P/2ℓ) = [(16 × 10^–5)/(2 × 10^–2)] = 8 × 10⁻³c

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Khushi....? ??‍? 5 years, 3 months ago

2×10^-3 c

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Find the current I2 in the circuit shown below

Posted by Vaishu Dutt 5 years, 3 months ago

CBSE > Class 12 > Physics

3 answers

Bhargav Rajput? 5 years, 3 months ago

without circuit ... dis que. Is meaning less

2Thank You

Khushi....? ??‍? 5 years, 3 months ago

What is the circuit

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Devil ? 5 years, 3 months ago

Where is the circuit ???

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No work is done in moving a charge over equipotential surface. True or false? Why?

Posted by Vimal Sharma 5 years, 3 months ago

CBSE > Class 12 > Physics

3 answers

Khushi....? ??‍? 5 years, 3 months ago

When a charge is moved from one point to another along some equipotential surface, it is true that the work done on the charge by the electric field is 0. If we move an object between two points where the potential is the same it means we have not done any net work related to the partical's position in the field.

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Khushi....? ??‍? 5 years, 3 months ago

True...

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Devil ? 5 years, 3 months ago

True

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Bharat

Posted by Bharat Kumar 5 years, 3 months ago

CBSE > Class 12 > Physics

2 answers

Mishti ???? 5 years, 3 months ago

Hmm Fir kya kra batao??

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Khushi....? ??‍? 5 years, 3 months ago

What do yuo mean Bharat

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Charge Q flowing through a resistance R, varies with time t as Q=at-bt^2. Total heat produced in R is...... #iit/jee....

Posted by Khushi....? ??‍? 5 years, 3 months ago

CBSE > Class 12 > Physics

5 answers

Ayush Vishwakarma?? 5 years, 2 months ago

Sorry khushi hm bahut dar jaye the apne padhai se kaise hoga issleye bahut tension me thee. Ye sach hai ki hm kuch din se busy thee pr utna bhi ni ki iss app par na aa paye ...agar aapko bura laga ho to sorry ??.keep learning you are the best. Iss bar tum top kro accha no.lana and not forget ...

1Thank You

Bhargav Rajput? 5 years, 3 months ago

Aree.. its ok?

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Khushi....? ??‍? 5 years, 3 months ago

Yes Bhargav you are right....thanks...

2Thank You

Bhargav Rajput? 5 years, 3 months ago

By doing whole cal...(mainly Integration)to cal. Heat produced w.r.t. time its ans is likely to be.[ H=a^3R/6b]??

1Thank You

Mishti ???? 5 years, 3 months ago

Solution- Current I =dQ/dt Therefore if Q=at-bt^2 I = a-2bt Power produced is I^2 × R P = a^2+4b^2 t^2 -4abt If you want to calculate total energy or heat produced you have to integrate P with respect to time t applying the limits from 0 to t. Total energy = a^2×t +4(b^2)(t^3/3)-2ab(t^2)

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Consider three charges q1 , q2 , q3 each equal to q at the vertices of an equilateral triangle of side l . What is the force on Q ( with the same sign as q) placed at the centroid of the trianle .

Posted by Rupam Kakati 5 years, 3 months ago

CBSE > Class 12 > Physics

3 answers

Bhargav Rajput? 5 years, 3 months ago

Yup... At centre of triangle net forces due to eq. Charges is zero...

1Thank You

Khushi....? ??‍? 5 years, 3 months ago

At centroid of the triangle the net forces due to equal charges is 0

1Thank You

Ayush Vishwakarma?? 5 years, 3 months ago

Force on Q which is placed at centroid of the triangle is 0( zero).

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Is syallbus not reducing???

Posted by Kanika Yadav 5 years, 3 months ago

CBSE > Class 12 > Physics

5 answers

Kanika Yadav 5 years, 1 month ago

Hlo, can anyone tell me how to join online quiz in this aapp. Plz

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Mishti ???? 5 years, 3 months ago

Dear it is probable that 30% of syllabous will reduce In month of midjuly we got the changes Regards.??

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Bhargav Rajput? 5 years, 3 months ago

Its already reduces in some sub.like English ??

1Thank You

Khushi....? ??‍? 5 years, 3 months ago

Yes shayad kiya jae....

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Shivendra Singh Yadav 5 years, 3 months ago

Jab school khulinge tab syllabus reduce kiya jayega---- by cbse

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A parallel plate capacitors having plates of area S and plate seperation d, has capacitance C1 in air. When 2 dielectrics of diff. Relative permittivies (£1=2 and£2=4) are introduced bet. the two plates ..then capacitance becomes C2.....then ratio C2/C1 is....?

Posted by Bhargav Rajput? 5 years, 3 months ago

CBSE > Class 12 > Physics

2 answers

Bhargav Rajput? 5 years, 3 months ago

No ur ans is wrong..its ok.... Final ans is 7:3 ✓

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Khushi....? ??‍? 5 years, 3 months ago

From my calculations it is 8:1 but if it is wrong then so sorry I don't know...

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A charge of 5 x 10^-5has been distributed between two sphere such that they repel each other with a force of 1N when their centres are at 2m apart find the distribution

Posted by Sonali Kurude 5 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Khushi....? ??‍? 5 years, 2 months ago

q1= 1.15×10^-5 c q2= 3.85×10^-5 c

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A charge of 5c is given a displacement of 0.5 m the work done in the process is 10 j the potenial difference between the two points will be

Posted by Jagrati Dubey 5 years, 3 months ago

CBSE > Class 12 > Physics

1 answers

Mr. Badmash 5 years, 3 months ago

Given :- Wab= 10j , q = 5c As we know that, Va-Vb = Wab/q Va-Vb = 10/5 Va-Vb = 2v

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Hvcsgbubbbbfhgdersfvtbongjvuovrcv

Posted by Bhoomi Modi 5 years, 3 months ago

CBSE > Class 12 > Physics

0 answers

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What is potential differance

Posted by Simran Sandal 5 years, 3 months ago

CBSE > Class 12 > Physics

2 answers

Mishti ???? 5 years, 3 months ago

The amount of work done to carry a unit + charge from 1point to another in the electric field against the F is called Electro potential diffrence

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Khushi....? ??‍? 5 years, 3 months ago

When both the points are within the electrostatic field work done per unit positive charge is called potential difference.When the first point lies at infinity work done per the unit positive charge is called potential at the second point. Mathematically, VY ‒ VX = WXY/qo.

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Deduce the expression for the torque acting on a dipole moment p in the presence of a uniform electric field E

Posted by Khushboo Dhankhar 5 years, 3 months ago

CBSE > Class 12 > Physics

2 answers

Khushi....? ??‍? 5 years, 3 months ago

Torque=PE sin theta

2Thank You

Riya Rana 5 years, 3 months ago

Torque = PEsin●theta

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ANSWER

What is the electric field of dipole at 30°,60°,90°,and 120°???

Posted by Ayush Vishwakarma?? 5 years, 3 months ago

CBSE > Class 12 > Physics

5 answers

Ayush Vishwakarma?? 5 years, 3 months ago

Sm to you

1Thank You

Khushi....? ??‍? 5 years, 3 months ago

Are koi nii yrr....wese congratulations....??????????

1Thank You

Ayush Vishwakarma?? 5 years, 3 months ago

Actually meri sister ka engagement kl hai issley busy hai sorry yaar.?

1Thank You

Khushi....? ??‍? 5 years, 3 months ago

Kya baat h Ayush aaj kal to aap gayab hi rehte ho aapke alawa to sb baat krte h.... bada famous kr diye h aap hume...??

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Khushi....? ??‍? 5 years, 3 months ago

For 30°= kp root 13/2r^3 For 60°= kp root 7/2r^3 For 90°= kp/r^3 For 120°= kp root 7/2r^3...

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Draw a schmathicaly an equivalent surface of uniform electrostatic field x axis àlong

Posted by Manish Kharera 5 years, 3 months ago

CBSE > Class 12 > Physics

0 answers

ANSWER

Guys don't mind but i am going to open a whatsapp group so interested students can pin in my comment section?

Posted by Rahul Yadav 5 years, 3 months ago

CBSE > Class 12 > Physics

0 answers

ANSWER

Properties of Electric field (unique)?

Posted by Ayush Vishwakarma?? 5 years, 3 months ago

CBSE > Class 12 > Physics

5 answers

Khushi....? ??‍? 5 years, 3 months ago

Thanks....?????

2Thank You

Ayush Vishwakarma?? 5 years, 3 months ago

That's unique thing that you give.

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Khushi....? ??‍? 5 years, 3 months ago

Okk Ayush to aaj hum answer dene me late ho gye koi niihum woh answer bta dete h jo kisi ne nii btaya.... The tangent drawn on the electric field lines shows the direction of electric field.... No two tangents can intersect each other because there can't be two ditection at same point.... Electric field lines cannot form closed loops because it travels only from +ve to -ve direction and teverse is not possible...... That's all baki to sabne bta hi diya....??

2Thank You

Mishti ???? 5 years, 3 months ago

The following are the properties of an electric field. Field lines never intersect each other. They are perpendicular to the surface charge. The field is strong when the lines are close together, and it is weak when the field lines move apart from each other. The number of field lines is directly proportional to the magnitude of the charge. The electric field line starts from the positive charge and ends from negative charge. If the charge is single, then they start or end at infinity. The line curves are continuous in a charge-free region. Regards. ??✍✍

1Thank You

Yogita Ingle 5 years, 3 months ago

The field lines never intersect each other.
The field lines are perpendicular to the surface of the charge.
The magnitude of charge and the number of field lines, both are proportional to each other.
The start point of the field lines is at the positive charge and end at the negative charge.
For the field lines to either start or end at infinity, a single charge must be used.

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A 100 turns coil kept in a magnetic field B=0.05T, carries a current of 1A, as shown in figure. Find the torque acting on the coil?

Posted by Ayushi Bhaskar 5 years, 3 months ago

CBSE > Class 12 > Physics

0 answers

ANSWER

Can we go to saturn

Posted by Aman Singh 5 years, 3 months ago

CBSE > Class 12 > Physics

3 answers

Khushi....? ??‍? 5 years, 3 months ago

Yes obviously we can and there are some technologies also which defined and prooved it. Its an extract from google..... It took these two spacecraft about 3 years and 2 months to reach the ringed planet of Saturn. ... At a speed of 17 km/sec (such as what the Voyager 1 spacecraft currently has), it would take about 75,000 years to reach Proxima Centauri. This may explain why we are not planning any trips there at present!

1Thank You

Sarvjeet Mahadik 5 years, 3 months ago

Yes we can go but we need the advance technology to reach at that approach but there is no use because it is a gas giant so it is difficult to land on it

1Thank You

Ayush Vishwakarma?? 5 years, 3 months ago

Yes we can go but crush on the surface of saturn.

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Yes...How did the point where E=0 is 2L can you explain me...

Posted by Khushi....? ??‍? 5 years, 3 months ago

CBSE > Class 12 > Physics

5 answers

Khushi....? ??‍? 5 years, 3 months ago

Samajh gue Ayuah thanks.....??

2Thank You

Ayush Vishwakarma?? 5 years, 3 months ago

[-2q]-----------L------------[8q]----x---------P. Keep a test charge in point p. And the force act by 8q = k8q/x^2 and force acted by (-2q) = k2q/(L+x)^2. Then the Enet=E1-E2. And it is given that E=0 then 0=E1-E2.then E1=E2. K8q/x^2= k2q/(x+l)^2. Then solve don't open bracket. It will be soved by square term. And come -2L. Because dirn is negative to positive . Positive has more magnitude and negative has low magnitude. So positve charge is able to apply the force on that point. Agar abhi bhi ni samajh me aaye toh bolna aur accha se samjha denge.

2Thank You

Khushi....? ??‍? 5 years, 3 months ago

Yes Ayush I got that thanks.....

2Thank You

Khushi....? ??‍? 5 years, 3 months ago

Samajh gye Aakash thanku so much......Or lgta h aap naraj ho gye agar haa to I am so sorry....mujhe bs samajh nii aaya tha isiliye puch liye.....?

2Thank You

Aakash Kumar 5 years, 3 months ago

8q<———L ——>(-2q)<------L------->P Put a charge Q at point P Force on Q due to - 2q= - 2kqQ/L² Force due to 8q= 8kqQ/(2L)²=2kqQ/L² Net force on charge Q at P=a big zero and nothing else than that E at P=0 can be concluded. If you don't understand by this method, go to a physics lab and verify it.

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Vector form of coulomb law

Posted by Diksha Negi 5 years, 3 months ago

CBSE > Class 12 > Physics