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  • 3 answers

Khushi....? ??‍? 5 years, 3 months ago

William Gilbert

Abhishek Sahu???? 5 years, 3 months ago

William Gilbert

Harsh Israni 5 years, 3 months ago

I am , my son's name is magnetic
  • 5 answers

Bv Sriram Sai Kumar 5 years, 3 months ago

900

Ankita ?? Arpita☺️ 5 years, 3 months ago

90

Devil ? 5 years, 3 months ago

90 degree

Khushi....? ??‍? 5 years, 3 months ago

90°

Gaurav Seth 5 years, 3 months ago

The angle between Electric field and an equi-potential surface is always 900. This is because,when the potential becomes constant,the negative potential gradient also becomes zero,hence necessitating the need for Electric field to be always normal with surface.

  • 1 answers

Gaurav Seth 5 years, 3 months ago

Given :

 

  • Raise in boiling point = 1ºC
  • Kb for benzene = 2.53 km⁻¹
  • <font size="2"><font style="user-select: initial !important;">Mass of solute (WB) = 10g</font></font>
  • <font size="2"><font style="user-select: initial !important;">Mass of solvent (WA) = 100g</font></font>
<div style="margin:0px; padding:0px"><font size="2"><font style="user-select: initial !important;">∆Tb = kb x m = kb </font></font></div> <div style="margin:0px; padding:0px"> </div> <div style="margin:0px; padding:0px"><font size="2"><font style="user-select: initial !important;">M= kb </font></font></div>
  • 2 answers

Ankita ?? Arpita☺️ 5 years, 3 months ago

Ye kya he?

Harsh Israni 5 years, 3 months ago

Kya h samasya
  • 5 answers

Ayush Vishwakarma?? 5 years, 3 months ago

Yes kosis kr rhe hai thik hone ka don't worry.

Khushi....? ??‍? 5 years, 3 months ago

Its ok Ayush take care of yourself don't worry about it....everything would be fine....

Ayush Vishwakarma?? 5 years, 3 months ago

29 july se 2 july tk ni soye hai.. head pain bahut jayada jo rha hai. Medicine liye hai 1week me thik ho gayenge. Aur idher padhai ka bhi stress bahut jayada hai ghab raa jate hai kaise complete hoga chem. Aur ni bta skte hai iss par ni toh sb majak udaenge.....take care by. I m Coming soon khushi

Khushi....? ??‍? 5 years, 3 months ago

Aayush aapko koi problem h aaj kal aap bde chup chup rehte ho......any problem....

Khushi....? ??‍? 5 years, 3 months ago

For an infinite sheet of charge, the electric field will be perpendicular to the surface. Therefore only the ends of a cylindrical Gaussian surface will contribute to the electric flux . ... The resulting field is half that of a conductor at equilibrium with this surface charge density. Formula is E=sigma/2€°
  • 2 answers

Khushi....? ??‍? 5 years, 3 months ago

Dielectric Strength is simply the maximum electric field that a material can withstand without experiencing failure of its insulating properties. It's measured in megavolts per meter (MV/m). The higher the Dielectric Strength, the better a material is to prevent electrical conductivity.

Gaurav Seth 5 years, 3 months ago

The maximum electric field that can exist in a dielectric without causing the breakdown of its insulating property is called dielectric strength of the material.

Maximum electric field which a dielectric medium can withstand without breakdown and prevent leaking of charge is called dielectric strength. Air dielectric strength is 3 x 10Vm-1.

  • 2 answers

Devil ? 5 years, 3 months ago

Btw direction of current carryingloop is determined by right hand thumb rule or by palm rule

Devil ? 5 years, 3 months ago

Complete h y ??
  • 0 answers
  • 1 answers

Yogita Ingle 5 years, 3 months ago

According to Kirchhoff’s Current Law (KCL), The total current entering a junction or a node is equal to the charge leaving the node as no charge is lost.

According to Kirchhoff’s Voltage Law (KVL), The voltage around a loop equals to the sum of every voltage drop in the same loop for any closed network and also equals to zero.

  • 2 answers

Khushi....? ??‍? 5 years, 3 months ago

Kirchhoff's circuit laws are two equalities that deal with the current and potential difference in the lumped element model of electrical circuits. They were first described in 1845 by German physicist Gustav Kirchhoff. This generalized the work of Georg Ohm and preceded the work of James Clerk Maxwell.

Yogita Ingle 5 years, 3 months ago

Kirchhoff’s First law: Junction law

  • Junction Law is also known as Kirchhoff’s First Law.
  • It states that at the junction,sum of current entering the junction is equal to the sum of current leaving the junction.
  • Junction is any point in the circuit.
  • Consider a case where I1 and I2are the currententering the junction and,currentI4 and I5 are exiting out of the junction.
  • According to Kirchhoff’s law; I1+ I2 =I3+ I4+ I5
  • 2 answers

Devil ? 5 years, 3 months ago

??

Khushi....? ??‍? 5 years, 3 months ago

Don't ask personal questions plzz...
  • 1 answers

Khushi....? ??‍? 5 years, 3 months ago

n=8 on comparing with its original formula for hemisphere is.... E=sigma /4 epsilon not hence n=8.....
  • 2 answers

Khushi....? ??‍? 5 years, 3 months ago

Electric potential...it is scalar quantity.....

Gaurav Seth 5 years, 3 months ago

Poetential is defined as work done per unit charge.
                   
This implies, Joule per Coulomb is the SI unit of electric potential.

Electric potential is a scalar quantity.

  • 2 answers

Ankita ?? Arpita☺️ 5 years, 3 months ago

Vector

Khushi....? ??‍? 5 years, 3 months ago

The magnetic dipole moment is a vector quantity with direction perpendicular to the current loop in the right-hand-rule direction.
  • 2 answers

Yogita Ingle 5 years, 3 months ago

Magnetic dipole moments have dimensions of current times area or energy divided by magnetic flux density. The unit for dipole moment in metre–kilogram– second–ampere is ampere-square metre. The unit in centimetre–gram–second electromagnetic system, is the erg (unit of energy) per gauss (unit of magnetic flux density). One thousand ergs per gauss equal one ampere-square metre.

Khushi....? ??‍? 5 years, 3 months ago

Perpendicular to the current loop.....
  • 1 answers

Khushi....? ??‍? 5 years, 3 months ago

The magnetic moment is the magnetic strength and orientation of a magnet or other object that produces a magnetic field. Examples of objects that have magnetic moments include: loops of electric current, permanent magnets, moving elementary particles, various molecules, and many astronomical objects. Its SI unit is Am^2...
  • 2 answers

Gaurav Seth 5 years, 3 months ago

The magnetic field of a bar magnet is strongest at either pole of the magnet. It is equally strong at the north pole when compared with the south pole. The force is weaker in the middle of the magnet and halfway between the pole and the center.

If you were to sprinkle iron filings on a piece of paper and place the magnet beneath it, you could see the path of the magnetic field lines. The field lines are closely packed at either pole of the magnet, widening as they get farther from the pole and connecting to the opposite pole of the magnet. The magnetic field lines emerge from the north pole and enter the south pole. The magnetic field gets weaker the farther you get from either pole, so a bar magnet is only useful for picking up small items over short distances.

Raju Raju 5 years, 3 months ago

Yes
  • 1 answers

Khushi....? ??‍? 5 years, 3 months ago

What do you want to say...
  • 3 answers

Vaishnavi Singh 5 years, 3 months ago

Such type of substance whoose aqueous solution conduct electricity.

Mishti ???? 5 years, 3 months ago

Answer~~ An electrolyte is a substance that produces an electrically conducting solution when dissolved in a polar solvent, such as water. The dissolved electrolyte separates into cations and anions, which disperse uniformly through the solvent. Electrically, such a solution is neutral. Regards. ??

Ankita ?? Arpita☺️ 5 years, 3 months ago

A substance that dissociate into ions in solution and acquire the capacity to conduct electricity
  • 4 answers

Karan Pal 5 years, 3 months ago

Karan pal

Bhargav Rajput? 5 years, 3 months ago

N v sir..

Ankita ?? Arpita☺️ 5 years, 3 months ago

Alakh pandey
Alakh pandey sir
  • 3 answers

Mishti ???? 5 years, 3 months ago

It is dimensionless dear ??

Khushi....? ??‍? 5 years, 3 months ago

Since it is a constant hence it is dimensionless....

Yogita Ingle 5 years, 3 months ago

The dimensional formula dielectric constant is given by,

[M0 L0 IT0]

Where,

  • M = Mass
  • L = Length
  • T = Time
  • 1 answers

Mishti ???? 5 years, 3 months ago

Answer~~ Cyclotron can be defined as a type of particle accelerator in which charged particles accelerate outwards from the centre along a spiral path. These particles are held to a spiral trajectory by a static magnetic field and accelerated by a rapidly varying electric field. Working Principle of Cyclotron A cyclotron accelerates a charged particle beam using a high frequency alternating voltage which is applied between two hollow “D”-shaped sheet metal electrodes known as the “dees” inside a vacuum chamber. The dees are placed face to face with a narrow gap between them, creating a cylindrical space within them for particles to move. Particles are injected into the center of this space. Dees are located between the poles of electromagnet which applies a static magnetic field B perpendicular to the electrode plane. The magnetic field causes the path of the particle to bend in a circle due to the Lorentz force perpendicular to their direction of motion. An alternating voltage of several thousand volts are applied between the dees. The voltage creates an oscillating electric field in the gap between the dees that accelerates the particles. The frequency of the voltage is set so that particles make one circuit during a single cycle of the voltage. To achieve this condition, the frequency must be set to particle’s cyclotron frequency. Expression for Cyclotron Frequency f=qB2πm where, B is the magnetic field strength Q is the electric charge of the particle m is the relativistic mass of the charged particle Expression for Particle Energy The energy of the particles depends on the strength of the magnetic field and the diameter of the dees. The centripetal force required to keep the particles in a curved path is given by the formula: Fc=mv2r The force is provided by the Lorentz’s force FB on the magnetic field B FB=qvB Equating these equations, we get mv2R=qvB v=qBRm Hence, the output energy of the particles is given by the expression E=q2B2R22m Uses of Cyclotron For several decades, these were the best sources of high-energy beams for nuclear physics experiments. However, these are still in use for this type of research. Treatment of cancer: Cyclotrons can be used in particle therapy to treat cancer, using the ion beams from cyclotrons can be used to penetrate the body and kill tumours by radiation damage. What are the Limitations of Cyclotron? Cyclotron cannot accelerate electrons because electrons are of very small mass. A cyclotron cannot be used to accelerate neutral particles. It cannot accelerate positively charged particles with large mass due to the relativistic effect. Regards. ??
  • 4 answers

Bhargav Rajput? 5 years, 3 months ago

If u r capable... then find it out..

Khushi....? ??‍? 5 years, 3 months ago

As possible but also think so that there are some mistakes Bhargav....

Bhargav Rajput? 5 years, 3 months ago

Do quickly as possible..

Mishti ???? 5 years, 3 months ago

Okk i will see if any dear??
  • 1 answers

Mishti ???? 5 years, 3 months ago

Solution~~ For a parallel plate capacitor, C = (ε₀ A)/d ∴ A = (C×d)/ε₀ ∴ A = 4πCd/(4πε₀) ∴ A = 4πCdk   (where k = 1/4πε₀) ∴ A = 4×π×2×(0.5×10⁻²)×(9×10⁹) ∴ A = 36π×10⁷ m² ∴ A = 113.097 × 10⁷ m² ∴ A ≈ 1.13×10⁹ m² Regards.??
  • 5 answers

Mishti ???? 5 years, 3 months ago

Thanks shikha✌✌ Its my pleasure dear??

Devil ? 5 years, 3 months ago

Most talented girls in this forum is ...... Khushi and misthi ??? GOOD .. KEEP IT UP FRDS

Devil ? 5 years, 3 months ago

??

Mishti ???? 5 years, 3 months ago

Good night dear??? Sweet dreams?? Bbye.?? ??

Mishti ???? 5 years, 3 months ago

Shayad ham ?? ??
  • 1 answers

Gaurav Seth 5 years, 3 months ago

For points on axial line

The axial line of a dipole is the line passing through the positive and negative charges of the electric dipole.

Consider a system of charges (-q and +q) separated by a distance 2a. Let ‘P’ be any point on an axis where the field intensity is to be determined.
Electric field at P (EB) due to +q

Electric field at P due to -q (EA)

Net field at P is given by

Simplifying, we get

As a special case :

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