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Gaurav Seth 5 years, 3 months ago
Given values :
The function f(x) = x is continuous at x = 0.
To Prove :
That the function f(x)=x is continuous at x=0, but not differentiable at
x = 0.
Solution :
First of all prove :
We know that :
Note :
If this is required then use!
Then,
So,
Now,
To Represent :
So,
Did you observe?
So, You should obesreve! that,
The limit from the right is 1 while the limit from the left is - 1.
Hence,
The two sided limit does not exist.
That is, the derivative does not exist at x = 0
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Meghna Thapar 5 years, 3 months ago
Rolle's theorem states that if a function f is continuous on the closed interval [a, b] and differentiable on the open interval (a, b) such that f(a) = f(b), then f′(x) = 0 for some x with a ≤ x ≤ b.
All 3 conditions of Rolle's theorem are necessary for the theorem to be true:
- f(x) is continuous on the closed interval [a,b];
- f(x) is differentiable on the open interval (a,b);
- f(a)=f(b).
- The conclusion of Rolle’s theorem is that if the curve is continuous between two points x = a and x = b, a tangent can be drawn at each and every point between x = a and x = b and functional values at x =a and x = b are equal, then there must be atleast one point between the two points x = a and x = b at which the tangent to the curve is parallel to the x-axis.
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Pooja ... 5 years, 3 months ago
1Thank You