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Gaurav Seth 5 years, 2 months ago
f(x) = sin 3x - cos 3x , 0 < x < π,
or f'(x) = 3 cos 3x + 3 sin 3x
= 3(cos 3x + sin 3x)
Put f'(x) = 0
or cos 3x + sin 3x = 0
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Gaurav Seth 5 years, 2 months ago
2cos2x-cos4x
=2 cos2x -2cos22x +1
=-2(cos2x-1/2)2 +3/2
minimum value occur when cos2x-1/2 will be maximum
=-2(-1-1/2)2 +3/2
=-3
and minimum value is 3/2
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