CBSE > Class 12 > Mathematics | CBSE Board | Homework Help

Probability of getting an odd number in a single throw of a die = 3/6 = 1/2
Similarly, probability of getting an even number = 3/6 = 1/2
Probability of getting an even number three times =1/2 ×1/2 × 1/2 = 1/8
Therefore, probability of getting an odd number at least once
=1− Probability of getting an odd number in none of the throws
=1− Probability of getting an even number thrice
=1−1/8
= 7/8 =0.88

1Thank You

Gaurav Seth 4 years, 4 months ago

A die is tossed thrice.

Outcomes $=\left \{ 1,2,3,4,5,6 \right \}$

Odd numbers $=\left \{ 1,3,5 \right \}$

The probability of getting an odd number at first throw

$=\frac{3}{6}=\frac{1}{2}$

The probability of getting an even number

$=\frac{3}{6}=\frac{1}{2}$

Probability of getting even number three times

$=\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}=\frac{1}{8}$

The probability of getting an odd number at least once = 1 - the probability of getting an odd number in none of throw

= 1 - probability of getting even number three times

$=1-\frac{1}{8}$

$=\frac{7}{8}$

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