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  • 1 answers

Gaurav Seth 4 years, 6 months ago

1. Understand the contents and weightage of the syllabus

2. Preparation from NCERT textbooks is the most important part

Though supplementary books may be used as references, the NCERT textbooks offer an exhaustive range of exercise questions and solved examples on every topic, which is more than enough to do well in your board examinations.

3. Strategize and THEN prepare!

The long form questions (5-6 marks), which are the most feared aspect of a paper, usually come from one of the following sections:

  • Calculus, which carries a whopping 44% weightage, and can be really scoring
  • Differential Equations consisting of the application based difficult questions.
  • Vectors and 3D geometry carry the next highest 17% weightage.

The aforementioned topics are practice-based and the best way to gain perfection in them is to practice and solve more and more problems on them. Then,

  • Probability, Relations and Functions and Algebra have a weightage of 10%, 10% and 13% respectively.
  • Linear Programming: 6%

These topics don’t require additional practice beyond the ones you have covered in your NCERT textbooks.

In linear programming, a 5-mark question comes from this chapter, which can be dealt with through little practice of understanding the questions and writing the linear equations.

4. Practice sample papers and previous years’ papers

5. Say goodbye to rote learning!

6. Presentation is very important

7. Time management

  • 5 answers

Krati Varshney 4 years, 5 months ago

7.7 and 7.8 cut ho gyi h according to cbse deleted syllabus...

Shraddha ✨✰✰ 4 years, 6 months ago

Sab ko pahle to thanks & sorry bcz mene aap logo ko paresan kiya puch k , but me isliye puch kyuki hamare school ka syllabus R.O. pune se decide hota hai. To koi hamare pune reason ka hota to muje syllabus ka completely pata chal jata.

Gursimran Singh 4 years, 5 months ago

Hamare toe pura integral aa raha hai

Mishti ???? 4 years, 5 months ago

It is made separately by schools ... Whatever syllabus u r school is decided to give it will came in u'r exam dear...

Ayush Vishwakarma?? 4 years, 6 months ago

It is based on your school teacher.
  • 1 answers

Sweety Kadyan 4 years, 5 months ago

Yes, first give priority to NCERT and then prefer extra books .Doing NCERT two times and try to solve last year question and sample paper will help u a lot to score goodmarks in your board exam. All the best dear ..
  • 1 answers

Sweety Kadyan 4 years, 5 months ago

Yes , but also try to do last year question paper that will make u ensure about Ur preparation level and u will get familiar with question paper patter
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Divyansh Gupta 4 years, 5 months ago

׳/4
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Dp Gour 4 years, 5 months ago

AB=I(identity fn.)

Ashish Kumar Tiwari 4 years, 6 months ago

AB = BA =I the relation of an inverse of a matrix is for any two matrices A & B , the inverse is only possible if AB = BA = I so it may apply conversely on your question Hope it may help
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Shraddha ✨✰✰ 4 years, 6 months ago

Sorry ans . adhura chhod diya. Then, dv/dx = 1/√1-(x)².d√x/dx , dv/dx =1/√1-x.1/2√x. , dv/dx = 1/2√x×√1-x. , dv/dx = 1/2√x(1-x). , dv/dx = 1/2√x-x² Then , dy/dx = du/dx + dv/dx , then dy/dx = x^sinx ×(sinx + x cosx .logx )/x + 1/2√x-x² , and first vale ans me jo dy/dx find kiya hai vo du/dx hai. Ok

Shraddha ✨✰✰ 4 years, 6 months ago

dy/dx = du/dx. +. dv/dx then, first we find the du/dx y = x^sinx then , y = e^sinx.logx Differ. W.r.t. x dy/dx = d/dx (e^ sinx.logx) dy/dx =e^sinx.logx .d/ dx(sinx.logx) dy/dx = x^sinx [sinx .d/dx logx + logx.d/dx sinx ] dy/dx = x^sinx (sinx + x cosx.logx )/x then , we find dv/dx dv/dx = d(sin-¹√x)/dx dv/dx = 1/√(1
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Shivam Nosaliya 4 years, 6 months ago

-3 8 -8 5
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Akanksha Kumari 4 years, 6 months ago

Thanks yrr

Unnat Mishra 4 years, 6 months ago

Let the side of cube be x Volume of cube=x^3 V=x^3 Differentiating both side with respect to t dV/dt=3x^2 dx/dt = k Where k=constant dx/dt= k/3x^2 ... (1) Surface area = 6x^2 Differentiating both side dS/dt = 12x dx/dt dS/dt = 12x k/3x^2 (from 1) dS/dt = 4k/x dS/dt is directly proportional to 1/x Thus, the increase in surface area varies inversally as the length of side
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Arjit Arjit 4 years, 6 months ago

Here let infinite be a number and let it be £ Now infinite×infinte gives Square of infinite Which is belongs to infinite Hence our assumption is wrong infinite is not a number Thus infinite×infinite is also infinite

Ayush Mohite 4 years, 6 months ago

You can say infinite square but that will be once more infinite in this case since the answer infinite is greater than the product of two infinites we can get that infinite 1 (the answer) >> infinite 0 (the products)

Arpit Namdev 4 years, 6 months ago

Its an undeterminant form

Chandan Jaiswal 4 years, 6 months ago

You will get infinite.
  • 2 answers

Chandan Jaiswal 4 years, 6 months ago

For 12 elements possible order are 1x12, 12x1, 2x6, 6x2, 3x4,and 4x3 For 7 elements possible order are 7x1, 1x7

Yogita Ingle 4 years, 6 months ago

for 12 elements , possible orders are 1 × 12, 2 × 6, 3 × 4 , 4 × 3 and 12 × 1.
for 7 elts. possible orders are only 1 × 7 and 7 × 1

  • 2 answers

Sojitra Priyanshi 4 years, 6 months ago

For inverse of matrix : A^-1 =(1/det.A)adj.A

Unnat Mishra 4 years, 6 months ago

y = f(x) => f^-1(y) = x
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Chandan Jaiswal 4 years, 6 months ago

co-domain is the range of onto function

Shraddha ✨✰✰ 4 years, 6 months ago

The range of onto function is the co-domain of the function. Means , → range = co-domain

Abhishek Dey 4 years, 6 months ago

9865 - 87544
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Shraddha ✨✰✰ 4 years, 6 months ago

Tq.... so.... much....?? bhaiya.....??

Abhishek Dey 4 years, 6 months ago

0

Gaurav Seth 4 years, 6 months ago

y = Sec ( Tan √x )

dy/dx = Sec ( Tan √x ) Tan ( Tan√x ) Sec² √x ( 1/ 2√x )

[Sec ( Tan √x ) Tan ( Tan√x ) Sec² √x ]/ 2√x

The same result implies for using logarithmic functions on both the sides ,

But it'll increase the payloads , hence , using Chain rule only
 

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Sonal . 4 years, 6 months ago

f'(x)=3 f'(x)>=0 3>=0 So this function is increasing on R.
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Shraddha ✨✰✰ 4 years, 6 months ago

Kya aapko explaination chahiye ? Example 10 ki ??..??
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Abhishek Dey 4 years, 6 months ago

BINOD
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Sonal . 4 years, 6 months ago

Y=x^2+2 dy/dx= 2x

Shraddha ✨✰✰ 4 years, 6 months ago

Y= dx/dt = d/dt x² + 2 = 2(x)²–¹ = 2x ans.

Aman Patel 4 years, 6 months ago

2x
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Ãshïsh Jaíñ 4 years, 6 months ago

Nii abhi nii

Mohit Kashyap 4 years, 6 months ago

Humare to nhi huye ..par hone chahiye

Shraddha ✨✰✰ 4 years, 6 months ago

Aapka school reopen ho gaya ???....

Abhishek Kumar 4 years, 6 months ago

Hlo

Krishna Yadav 4 years, 6 months ago

Nope
  • 4 answers

Arjit Arjit 4 years, 6 months ago

By practice hard

Unnat Mishra 4 years, 6 months ago

Firstly know concept of topics

Ankit Kaushal 4 years, 6 months ago

Start solving r.d sharma under best guidence and after that nceart you will score high

Akanksha Kumari 4 years, 6 months ago

By ncert and lots of hard work
  • 1 answers

Gaurav Seth 4 years, 6 months ago

R = {(a, b) : 2 divides a – b}
where R is in the set Z of integers.
(i)    a – a = 0 = 2 .0
∴ 2 divides a – a ⇒ (a, a) ∈ R ⇒ R is reflexive.
(ii) Let (a, a) ∈ R ∴ 2 divides a – b ⇒ a – b = 2 n for some n ∈ Z ⇒ b – a = 2 (–n)
⇒ 2 divides b – a ⇒ (b. a) ∈ R
(a, ft) G R ⇒ (b, a) ∈ R ∴ R is symmetric.
(iii) Let (a, b) and (b, c) ∈ R
2 divides a – b and b – c both ∴ a – b = 2 n1 and b – c = 2 n2 for some n1, n2 ∈ Z ∴ (a – b) + (b – c)= 2 n1 + 2 n2 ⇒ a – c = 2 (n1 + n2 )
⇒ 2 divides a – c
⇒ (a, c) ∈ R
∴ (a,b), (b,c) ∈ R ⇒ (a, c) ∈ R
∴ R is transitive
From (i), (ii), (iii) it follows that R is an equivalence relation.

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