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  • 2 answers

Krati Varshney 5 years ago

Thnks alot ??
A function is said to be onto , if there exist an x for every y . hence to prove a function to be onto just solve the function for an x . And Mere tarike se yaad rakhane k liye → Range of given function. = co-domain of given function. ??I hope ye apko helpful hoga .????▪▫▫▫▫▫▪▪▪▪▪▪
  • 1 answers
Ans. → 0 =5 (72 - 98) - 7(81 - 133) + 9(126 - 152) = -130 +364 - 234 = 0 .
  • 2 answers
Ans. → = 1/2( x1 ( y2 - y3 ) + x2 ( y3 - y1 ) + x3 ( y1 - y2) = 1/2 [ -3 ( 0 - k ) + 3 ( k - 0 ) + 0 ( 0 - 0 ) = 1/2 [-3(k) + 3k + 0 ] = 1/2 ( 3k + 3k ) .°. 3k = 9 (°.° ar.∆ABC = 9 unit² ) .°. k = 3 ans.

Krati Varshney 5 years ago

Use the formula of area of triangle :- 1/2 (x1(y2-y3)+x2 (y3-y1)+x3 (y1-y2))=0 Put all the given values in this then u will get ur answer urself..??
  • 1 answers

Tanisha Yadav 5 years ago

x/2-1/2log|cosx-sinx|+c
  • 1 answers

Stuti Trivedi 5 years ago

Log lcosec2x-cot2xl +c
  • 1 answers

Mr. Badmash 5 years ago

Write 1/16-9x^2 as 1/(4)^2-(3x)^2 and apply formula from NCERT
  • 3 answers

Arjit Arjit 5 years ago

2logx+logx 3logx Now dy/dx=d/dx (3logx) =3/x

Iqbal Singh 5 years ago

ok thanks mera answer aa geya bro agin thanks????

Mr. Badmash 5 years ago

Firstly write log^2x+logx.,,,,, As (logx)^2+logx and apply log property of power then solve it by itself....??? Agar fir bhi nhi bane to bta dena
  • 1 answers

Sonal . 5 years ago

dy/dx=-2cosec(x^3+1) cot (x^3+1)×3x^2/2√cosec(x^3+1) dy/dx =-3x^2 cosec(x^3+1) cot(x^3+1)/√cosec(x^3+1)
  • 2 answers

Siya Soni 5 years ago

|adj A|=|A|^n-1 n is the order of determinent |A|^3-1=|A|^2......(1) |A|=3 put this value in eq (1) 3^2=9 Hence 9 is the required answer

Tanisha Yadav 5 years ago

9
  • 2 answers

Siya Soni 5 years ago

e^cosx[cosx-sinx] +xcosx^x-1(-sinx)

Riya Sen 5 years ago

e^xcosx(cosx-xsinx)+cosx^x[log(cosx)-xtanx]
  • 2 answers

Prathamesh Ghadage 4 years, 11 months ago

Thanks

Tanisha Yadav 5 years ago

If f′(x) > 0 at each point in an interval I, then the function is said to be increasing on I. f′(x) < 0 at each point in an interval I, then the function is said to be decreasing on I. ... If f′(x) > 0, then f is increasing on the interval, and if f′(x) < 0, then f is decreasing on the interval.
  • 1 answers

Iqbal Singh 5 years ago

Ashish Sir , vedantu , tiwariacademy , achieve it
  • 1 answers

Riya Sen 5 years ago

-π/4
  • 4 answers

Siya Soni 5 years ago

A'=-A

Riya Sen 5 years ago

A skew symmetric matrix is one which satisfy this equation i.e. A' = -A

Rounak Rocks 5 years ago

-1 0 0 1
Matrix A is said to be skew-symmetric if transpose of matrix A is equal to matrix A. Note that all the skew symmetric matric are zero
  • 2 answers

Rounak Rocks 5 years ago

31/10

Iqbal Singh 5 years ago

kya dear 3.1 kaa
  • 1 answers

Iqbal Singh 5 years ago

solve it by formula e^x wala and it's answer is e^x-2(1-0)
  • 5 answers

Iqbal Singh 5 years ago

Akansha I am not bro

Tanisha Yadav 5 years ago

No ,this was not in syllabus

Arif Khan 5 years ago

Not

Akanksha Kumari 5 years ago

Thanks bro?

Iqbal Singh 5 years ago

it is cut from syllabus yaar why you do this ?

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