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  • 2 answers

Mohit Kashyap 4 years, 1 month ago

NCERT and then Rd sharma for maths kyunki NCERT mai practice keliye bohot kam questions hai

Nishant Pandey 4 years, 1 month ago

Obviously, NCERT is sufficient, because it is provided by board. And board advised only & only NCERT to aquire whole syllabus. Jinhe NCERT samajh nhi aati, vo side book ka use kr skte hain. Aur ab suno jaldi ka kaam saitaan? ka.
  • 3 answers

Shanu Sharma 4 years, 1 month ago

fog does not exists as 1/0 is not defined but for approximation we say that 1/0 ----> infinity

Amit Kumar 4 years, 1 month ago

F(0)= infinity

Amit Kumar 4 years, 1 month ago

Does not exist
  • 2 answers

Monica Suresh 4 years, 1 month ago

Consider 1+2x=t Final ans ------> 1/6 ( 1+2x^2)^3/2 + C

Stuti Trivedi 4 years, 1 month ago

1/6 (1+2x^2)^3/2
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  • 1 answers

Stuti Trivedi 4 years, 1 month ago

21/4
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  • 1 answers

Tanisha Yadav 4 years, 1 month ago

1/sin(a-b)log|cos(x-a)/cos(x-b)|+C
  • 1 answers

Gaurav Seth 4 years, 1 month ago

Let r and h be the radius and height of the cone respectively inscribed in a sphere of radius R.

Let V be the volume of the cone.

∴ By second derivative test, the volume of the cone is the maximum when 

  • 1 answers

Gaurav Seth 4 years, 1 month ago

x = a(cost + log tant/2)

differentiate with respect to t,

dx/dt = d{a(cost + logtan t/2)}/dt

= a[d(cost)/dt + d(logtan t/2)/dt]

= a[ -sint + 1/tan t/2 × sec²t/2× 1/2]

= a [ -sint + 1/{2sin t/2.cos t/2} ]

we know, 2sinA.cosA = sin2A , use it here

= a [ -sint + 1/sint]

= a { 1 - sin²t}/sint

= acos²t/sint

= acott. cost .......(1)

again, y = asint

dy/dt = acost .......(2)

now, dy/dx = {dy/dt}/{dx/dt}

= {acost}{acott.cost}

= 1/cott

hence, dy/dx = tan t

  • 1 answers

Sonal . 4 years, 1 month ago

Y=sinx-cos dy/dx=cos+sinx Integration Ans= -cosx-sinx
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Acinta Sofiya 4 years, 1 month ago

d/dx cos (sin^-1x^2) = -2x sin (sin^-1 x^2) / root 1-x^4
  • 2 answers

Kanika Yadav 4 years, 1 month ago

Yahh

Divyanshu Patrewal 4 years, 1 month ago

Me this should be aploaded
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  • 2 answers

Krati Varshney 4 years, 1 month ago

Thnks alot ??

Shraddha ✨✰✰ 4 years, 1 month ago

A function is said to be onto , if there exist an x for every y . hence to prove a function to be onto just solve the function for an x . And Mere tarike se yaad rakhane k liye → Range of given function. = co-domain of given function. ??I hope ye apko helpful hoga .????▪▫▫▫▫▫▪▪▪▪▪▪
  • 1 answers

Shraddha ✨✰✰ 4 years, 1 month ago

Ans. → 0 =5 (72 - 98) - 7(81 - 133) + 9(126 - 152) = -130 +364 - 234 = 0 .
  • 2 answers

Shraddha ✨✰✰ 4 years, 1 month ago

Ans. → = 1/2( x1 ( y2 - y3 ) + x2 ( y3 - y1 ) + x3 ( y1 - y2) = 1/2 [ -3 ( 0 - k ) + 3 ( k - 0 ) + 0 ( 0 - 0 ) = 1/2 [-3(k) + 3k + 0 ] = 1/2 ( 3k + 3k ) .°. 3k = 9 (°.° ar.∆ABC = 9 unit² ) .°. k = 3 ans.

Krati Varshney 4 years, 1 month ago

Use the formula of area of triangle :- 1/2 (x1(y2-y3)+x2 (y3-y1)+x3 (y1-y2))=0 Put all the given values in this then u will get ur answer urself..??
  • 1 answers

Tanisha Yadav 4 years, 1 month ago

x/2-1/2log|cosx-sinx|+c
  • 1 answers

Stuti Trivedi 4 years, 1 month ago

Log lcosec2x-cot2xl +c
  • 1 answers

Mr. Badmash 4 years, 2 months ago

Write 1/16-9x^2 as 1/(4)^2-(3x)^2 and apply formula from NCERT
  • 3 answers

Arjit Arjit 4 years, 1 month ago

2logx+logx 3logx Now dy/dx=d/dx (3logx) =3/x

Iqbal Singh 4 years, 2 months ago

ok thanks mera answer aa geya bro agin thanks????

Mr. Badmash 4 years, 2 months ago

Firstly write log^2x+logx.,,,,, As (logx)^2+logx and apply log property of power then solve it by itself....??? Agar fir bhi nhi bane to bta dena

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