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Gaurav Seth 4 years, 1 month ago
Consider the given events
A = Numbers appearing on two dice are different
B = The sum of the numbers on two dice is 4
Clearly,
A = {(1, 2), (1, 3), (1, 4), (1, 5), (1, 6),
(2, 1), (2, 3), (2, 4), (2, 5), (2, 6),
(3, 1), (3, 2), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 5), (4, 6),
(5, 1), (5, 2), (5, 3), (5, 4), (5, 6),
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5)}
B = {(1, 3), (3, 1) and (2, 2)}
Now ,
A∩B={(1,3) and (3,1)}
∴ Required probability =P(B/A) = n(A∩B) / n(A) = 2 / 30 =1 / 15
Yogita Ingle 4 years, 1 month ago
When two dice are thrown, there are 36 possibilities.
However, we are given, every time both dice contain different numbers means doublet is not a possibility.
As, number of doublets are 6, so, sample space, S=36-6=30
Number of possibilities of the event when sum of dice is 4, (1,3),(3,1).
Here, we won′t take (2,2) as both dice contain different numbers.So,
E=2
So, P(E)=2/30=1/15
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Gaurav Seth 4 years, 1 month ago
Definition | A relation is a relationship between sets of values. Or, it is a subset of the Cartesian product | A function is a relation in which there is only one output for each input. |
Denotation | A relation is denoted by “R” | A function is denoted by “F” or “f”. |
Example | R = {(2, x), (9, y), (2, z)}
** It is not a function, as “2” is input for both x and z. |
F = {(2, x), (9, y), (5, x)} |
Note: | Every relation is not a function. | Every function is a relation |
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Divya Garg 4 years, 1 month ago
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