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Ask QuestionPosted by Thanushetty Shetty 5 years, 4 months ago
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Shraddha ✨✰✰ 5 years, 4 months ago
~@Kanchi Jawla 5 years, 4 months ago
Posted by Anand Kumar Yadav 5 years, 4 months ago
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Posted by Umme Sidhrath 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
Consider the given events
A = Numbers appearing on two dice are different
B = The sum of the numbers on two dice is 4
Clearly,
A = {(1, 2), (1, 3), (1, 4), (1, 5), (1, 6),
(2, 1), (2, 3), (2, 4), (2, 5), (2, 6),
(3, 1), (3, 2), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 5), (4, 6),
(5, 1), (5, 2), (5, 3), (5, 4), (5, 6),
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5)}
B = {(1, 3), (3, 1) and (2, 2)}
Now ,
A∩B={(1,3) and (3,1)}
∴ Required probability =P(B/A) = n(A∩B) / n(A) = 2 / 30 =1 / 15
Yogita Ingle 5 years, 4 months ago
When two dice are thrown, there are 36 possibilities.
However, we are given, every time both dice contain different numbers means doublet is not a possibility.
As, number of doublets are 6, so, sample space, S=36-6=30
Number of possibilities of the event when sum of dice is 4, (1,3),(3,1).
Here, we won′t take (2,2) as both dice contain different numbers.So,
E=2
So, P(E)=2/30=1/15
Posted by Kajal Gupta 5 years, 4 months ago
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Kajal Gupta 5 years, 4 months ago
Shraddha ✨✰✰ 5 years, 4 months ago
Posted by Adarsh Raj 5 years, 4 months ago
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Ghanshyam Deshmukh 5 years, 4 months ago
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Shraddha ✨✰✰ 5 years, 4 months ago
Posted by Radhika Singhania 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
| Definition | A relation is a relationship between sets of values. Or, it is a subset of the Cartesian product | A function is a relation in which there is only one output for each input. |
| Denotation | A relation is denoted by “R” | A function is denoted by “F” or “f”. |
| Example | R = {(2, x), (9, y), (2, z)}
** It is not a function, as “2” is input for both x and z. |
F = {(2, x), (9, y), (5, x)} |
| Note: | Every relation is not a function. | Every function is a relation |
Posted by Sneha Ambhore 5 years, 4 months ago
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Shraddha ✨✰✰ 5 years, 4 months ago
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Shraddha ✨✰✰ 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
1. Understand the contents and weightage of the syllabus
2. Preparation from NCERT textbooks is the most important part
Though supplementary books may be used as references, the NCERT textbooks offer an exhaustive range of exercise questions and solved examples on every topic, which is more than enough to do well in your board examinations.
3. Strategize and THEN prepare!
The long form questions (5-6 marks), which are the most feared aspect of a paper, usually come from one of the following sections:
- Calculus, which carries a whopping 44% weightage, and can be really scoring
- Differential Equations consisting of the application based difficult questions.
- Vectors and 3D geometry carry the next highest 17% weightage.
The aforementioned topics are practice-based and the best way to gain perfection in them is to practice and solve more and more problems on them. Then,
- Probability, Relations and Functions and Algebra have a weightage of 10%, 10% and 13% respectively.
- Linear Programming: 6%
These topics don’t require additional practice beyond the ones you have covered in your NCERT textbooks.
In linear programming, a 5-mark question comes from this chapter, which can be dealt with through little practice of understanding the questions and writing the linear equations.
4. Practice sample papers and previous years’ papers
5. Say goodbye to rote learning!
6. Presentation is very important
7. Time management
Posted by Shraddha ✨✰✰ 5 years, 4 months ago
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Krati Varshney 5 years, 4 months ago
Shraddha ✨✰✰ 5 years, 4 months ago
Mishti ???? 5 years, 4 months ago
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Chandan Jaiswal 5 years, 4 months ago
Yogita Ingle 5 years, 4 months ago
for 12 elements , possible orders are 1 × 12, 2 × 6, 3 × 4 , 4 × 3 and 12 × 1.
for 7 elts. possible orders are only 1 × 7 and 7 × 1

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