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  • 1 answers

Jai Prakash Verma 3 years, 10 months ago

Youtube ya doubtnut mai dekho mil jayega
  • 1 answers

Aroan Nema 3 years, 10 months ago

WHERE? HERE? iON Digital Zone iDZ Village Adampur Raisen Road Headway IT Services, Building No. 7
  • 0 answers
  • 4 answers

Jai Prakash Verma 3 years, 10 months ago

-1/x^2

Kashish Agrawal 3 years, 10 months ago

Log x

Satya Singhaniya 3 years, 10 months ago

Log x

#Srishti ? 3 years, 10 months ago

-1/x^2
  • 1 answers

Aroan Nema 3 years, 10 months ago

a2=[2 -2, -2 2] so k=2
  • 0 answers
  • 1 answers

Sia ? 3 years, 5 months ago

Let x1, x2 ∈ Z
f is one-one or injective
Range of f = {0, ±1, ±8, ±27,…………….. } ≠Z
f is not surjective

  • 0 answers
  • 2 answers

Arpit Singh 3 years, 10 months ago

?

Archana Jedia 3 years, 10 months ago

??
  • 1 answers

Muddabbir Hussain 3 years, 10 months ago

x log x - x + C
  • 1 answers

Mahi Kumari 3 years, 10 months ago

As the problem of Combination(Selection) the general formula for finding it will be:- nCr = n!/r! (n-r)! Similarly, 20c7= 20!/7! (20-7)! 20!/7!×13! Ans..
  • 1 answers

Ronak Mor 3 years, 10 months ago

Yessss
  • 5 answers

Mahi Kumari 3 years, 10 months ago

Wait Mukti, I will again check this question and try to understood it.

Mukti Sourava Mohapatra 3 years, 10 months ago

No sahil kumar question is correct .

Mukti Sourava Mohapatra 3 years, 10 months ago

Write 1+cosx= 2 cos^2(x/2) Then (x+sinx)/(1+cosx )= (1/2)xsec^2(x/2) (apply integration by parts to evaluate) + sinx/2cos^2(x/2)(Apply sinx =2sin(x/2)cos(x/2) to evaluate)

Mahi Kumari 3 years, 10 months ago

I think the question is reversed by mistake and it would be like "integration of function (1+cosx/ x+sinx) w.r.t x from limit 0 to π, so that we can able to substitute t = (x+sinx) and it's differential form would be (1+cosx). Check please.

Prakhar Chouksey 3 years, 10 months ago

Substitute 1+cosx=t
  • 1 answers

Kashish Agrawal 3 years, 10 months ago

What you want
  • 1 answers

Mukti Sourava Mohapatra 3 years, 10 months ago

Check ncert class 12 chp 5 Continuity and differentiability Section 5.4
  • 1 answers

Rohan Chaudhary ??? 3 years, 10 months ago

Janna kya chhati Ho aap
  • 1 answers

Prakhar Chouksey 3 years, 10 months ago

Every modulus function is continuous but non differentiable on its roots
  • 3 answers

Abhishek Jha 3 years, 10 months ago

2x^51÷51 - x

Sashank Dugar 3 years, 10 months ago

answer is wrong

Jay Satrola 3 years, 10 months ago

(2x-1)^51/101
  • 1 answers

Shivansh Kaushik 3 years, 10 months ago

Use chain rule here as: dy/dx=(dy/du)×(du/dx)-----[A] •Differentiate 1st function w.r to u by quotient rule. •Differentiate 2nd function w.r to x also by quotient rule. •Put the values in equation A. •If your answer is in terms of u then put the value of u(in terms of x) at last.
  • 1 answers

Shivansh Kaushik 3 years, 10 months ago

x+ky+3z=0 ..(1) 3x+ky−2z=0 ..(2) 2x+4y−3z=0 ..(3) For non-zero solutions to exist: Find the value of k by determinant method of linear equations. Solving the above determinant equation, we get −3k+8−k(−9+4)+3(12−2k)=0 ⇒k=11 Solving equations (1), (2) and (3), we get 2x=5z & 3x=−(k+4)y ⇒2x=5z&x=−5y Now,  xz/y^2=(x​)(2x/5)/[-x/5]^2=10
  • 2 answers

Jay Satrola 3 years, 10 months ago

Clarify the statement!!!

Harshitha Benaka 3 years, 10 months ago

1

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