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Nirjhara Rai 4 years, 5 months ago
Ash Varshney 4 years, 5 months ago
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Sia ? 4 years ago
We have given
y = x-7/(x-2)(x-3)......(i)
Let (i) cuts the x-axis at (x, 0)
then x-7/(x-2)(x-3) =0 =>x=7
the required point is (7, 0).
Differentiating equation (i) w.r.t. x, we get
Posted by Vinay Chaudhary 4 years, 5 months ago
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Sia ? 4 years ago
Let x1, x2 ∈ Z
f is one-one or injective
Range of f = {0, ±1, ±8, ±27,…………….. } ≠Z
f is not surjective
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