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  • 2 answers

Gourav Chhapola 3 years, 9 months ago

3/√(1-x² ) - 1/√(1-x² ) =2/√(1-x² )

Mansi Maheshwari 3 years, 9 months ago

X=1/root2
  • 4 answers

Twinkle . 3 years, 9 months ago

2/x³

Gurharman Kaur 3 years, 9 months ago

-2/x^3

Gourav Chhapola 3 years, 9 months ago

x+1/x

Mansi Maheshwari 3 years, 9 months ago

2/x3
  • 0 answers
  • 2 answers

Gurharman Kaur 3 years, 9 months ago

Equation show nii ho rhi properly

Guvv Rona 3 years, 9 months ago

Can I delete it
  • 1 answers

Gurharman Kaur 3 years, 9 months ago

Question ch -2 whole de product ch hai
  • 1 answers

Alex Pal 3 years, 9 months ago

The sum of three no is 6 if we multiply third no by three
  • 0 answers
  • 0 answers
  • 2 answers

Shraddha ✨✰✰ 3 years, 9 months ago

For every real number (or) valued function f(x), the values of x which satisfies the equation f¹(x)=0are the point of it's local and global maxima or minima. This occus due to the fact that, at the point of maxima or minima, the curve of the function has a ,zero slope. We have function f(x)=(1​/x)^x We will be using the equation, y=(1/x)^x Taking in both sides we get ln y=−xlnx Differentiating both sides with respect to x. y.dy​/dx = −lnx − 1 dy​/dx=−y (ln x + 1) Equating dy​/dx  to 0, we get −y(ln x + 1)=0 Since y is an exponential function it can never be equal to zero, hence ln x + 1 = 0 ln x = −1 x=e^−1 So, for the maximum value we put x=e^−1 in f(x) to get the value of f(x) at the point. f(e^−1) = e^1/e Hence the maximum value of the function is e^1/e. ∴ So, the answer is option →B. {e^1/e}

बेबि बीच 3 years, 9 months ago

1
  • 0 answers
  • 2 answers

Elina ❤️ 3 years, 9 months ago

Only Practice

Sushant Adhana 3 years, 9 months ago

Firstly read all ncert chapter and then solve last year paper and sample paper
  • 3 answers

Sushant Adhana 3 years, 9 months ago

Calculas

Aruthra A 3 years, 9 months ago

Calculas

Chetna Yadav 3 years, 9 months ago

Calculas unit
  • 1 answers

Swayam Pattanaik 3 years, 9 months ago

Write sin2=1-cos2 Then u will get theta=30
  • 5 answers

Sushant Adhana 3 years, 9 months ago

Ha g

Maithili Baria 3 years, 9 months ago

Yaah

Devansh Tomar 3 years, 9 months ago

Yup

Ronit Sharma Ji 3 years, 9 months ago

Nahi

Nishant Pandey 3 years, 9 months ago

Nhi
  • 3 answers

Mahi Kumari 3 years, 9 months ago

Sin90°+Cos90°

Swayam Pattanaik 3 years, 9 months ago

4-3

Rishita Maheshwari 3 years, 10 months ago

Sin²x + cos²x = 1
  • 1 answers

Arjun Singh 3 years, 10 months ago

dy/dx = x^x - 2cosec^(2)x ×cotx/ x^x+ cosec^(2)x
  • 2 answers

Maithili Baria 3 years, 9 months ago

Root 2 iota

Aditi Mishra 3 years, 10 months ago

Root2
  • 2 answers

Thakur Anubhav Singh 3 years, 10 months ago

✓2=1.41423

Shraddha ✨✰✰ 3 years, 10 months ago

✓2 = 1.414
  • 1 answers

Abhinav Agarwal 3 years, 10 months ago

Distance formula: √[(x2​−x1​)^2+(y2​−y1​)^2] P(a+b,a−b) and Q(a−b,a+b) PQ=√[{(a−b)−(a+b)}^2+{(a+b)−(a−b)}^2​] =√[(2b)^2+(2b)^2] =√[(8b)^2] =2b√2​ units.
  • 1 answers

Tiya Singhal 3 years, 10 months ago

Cos^-1(½) =cos^-1(cosπ/3) =π/3. [Cos^-1(cosx)=x]

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