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  • 2 answers

Megha. B 4 years, 9 months ago

Thanks

Gaurav Seth 4 years, 9 months ago

On July 7, HRD Minister Ramesh Pokhriyal announced a major CBSE syllabus reduction with 30% of the syllabus slashed for the year 2020-21 for classes 9 to 12 because of the reduction in classroom teaching time due to the Covid-19 pandemic and lockdown.

CBSE has rationalized the syllabus with the help of suggestions from NCERT and the same has been notified by a new CBSE notification as well.

Deleted syllabus of CBSE Class 12 Mathematics

 

 

  • 0 answers
  • 1 answers

Himanshu Singla 4 years, 8 months ago

Multiply on both side with A inverse as we know multiplication of A * A inverse is equals to identity matrix so answer will be A square
  • 2 answers

Sahil Kumar 4 years, 9 months ago

It may be this numerical solution not match with your answers of your textbook, but if it will be evaluated further then you can!!

Sahil Kumar 4 years, 9 months ago

(-1/√2)tan^-1(x/√2)+(2/√3)tan^-1(x/√3) + C
  • 3 answers

Tanish Saini 4 years, 9 months ago

2π/3

Harsh M 4 years, 9 months ago

2π/3

Deepdaman Singh 4 years, 9 months ago

2 pie/3
  • 1 answers

Premraj Verma 4 years, 9 months ago

X^4/4 - X^3/3 + X^2/2 - X - log|X|
  • 2 answers

Sahil Kumar 4 years, 9 months ago

{(x³-1)^7/3}/7 + {(x³-1)^4/3}/4 + C

Gaurav Seth 4 years, 9 months ago

given function is ∫(x³ - )^⅓ x^5.dx

let (x³ - 1) = t , and x³ = (1 + t)
⇒3x² = dt/dx
⇒dx = dt/3x²

So, ∫(x³ - 1)^⅓ x^5 * dt/3x²

⇒1/3 ∫t^⅓ (1 + t) *dt

⇒1/3 ∫(t^⅓ + t^{4/3}).dt

⇒1/3 ∫t^{1/3}.dt + 1/3∫t^{4/3}.dt

⇒1/3 + 1/3 + c

put the value of t in the above function,

.
 

  • 0 answers
  • 3 answers

Megha. B 4 years, 9 months ago

Y=cosx dy/dx= -sinx

Vivek Kumar 4 years, 9 months ago

dy/dx= -sinx

Aditya Raj 4 years, 9 months ago

Differentiate in terms of....???
  • 1 answers

Gaurav Seth 4 years, 9 months ago

The region bounded by the parabola y2 = 16x and the line x = 4 is the area OACO

The area OACO is symmetrical about x-axis 

Area of OACO = 2(Area of OAB)

Area of OACO = 

Therefore, the required area is 128/3 sq. units

  • 0 answers
  • 2 answers

Premraj Verma 4 years, 9 months ago

Since n=4 Therefore, no. Of possible reflexive relations= 2^(n(n-1) =2^(4(4-1)=2^12=4096

Simran Simran 4 years, 9 months ago

4 {(a, a), (b, b), (c, c), (d, d) }
  • 1 answers

Premraj Verma 4 years, 9 months ago

Many one Because f(-1)=f(1)=1 Similarly f(-5)=f(5)=25
  • 1 answers

Gaurav Seth 4 years, 9 months ago

Solution:

Let V be the given volume of cone.

V=Volume of cone = 

h = Height of cone = 

C=Curved surface area of cone = , where r is radius and l is slant height of cone.

C= , as l²= r²+ h²

For Maxima and Minima, derivative of C that is curved surface area should be equal to zero.

K=C²= π²r²(r²+h²)

K =

Differentiating both sides with respect to r

K' = 4π²r³ + 

Putting , K'=0

=

h=

Let A be the semi vertical angle of the cone.

Cot A =  

       = 

Cot A= 

A= 

Hence proved.



 

  • 1 answers

Gaurav Seth 4 years, 9 months ago

On July 7, HRD Minister Ramesh Pokhriyal announced a major CBSE syllabus reduction with 30% of the syllabus slashed for the year 2020-21 for classes 9 to 12 because of the reduction in classroom teaching time due to the Covid-19 pandemic and lockdown.

CBSE has rationalized the syllabus with the help of suggestions from NCERT and the same has been notified by a new CBSE notification as well.

Deleted syllabus of CBSE Class 12 Mathematics

 

 

  • 1 answers

Gaurav Seth 4 years, 9 months ago

HRD Minister Ramesh Nishank announced a major CBSE syllabus reduction for the new academic year 2020-21 on July 7 which was soon followed by an official notification by CBSE on the same.

Considering the loss of classroom teaching time due to the Covid-19 pandemic and lockdown, CBSE reduced the syllabus of classes 9 to 12 with the help of suggestions from NCERT.

The CBSE syllabus has been rationalized keeping intact the learning outcomes so that the core concepts of students can be retained.

Deleted syllabus of CBSE Class 12 Mathematics

 

 

 

D

  • 1 answers

Gaurav Seth 4 years, 9 months ago

Considering the loss of classroom teaching time due to the Covid-19 pandemic and lockdown, CBSE reduced the syllabus of classes 9 to 12 with the help of suggestions from NCERT.

The CBSE syllabus has been rationalized keeping intact the learning outcomes so that the core concepts of students can be retained.

CBSE stated in its notification that the deleted portions of the CBSE syllabus should not be considered for internal assessments or for the year-end board exams.

Click on the respective links:

<font color="#FF6600"><font style="box-sizing: border-box;">Revised Curriculum for the Academic Year 2020-21</font></font>

<div class="panel-group" id="accordion" style="margin-bottom:5px; padding:0px"> <div class="panel panel-default" style="border:1px solid #dddddd; margin-bottom:0px; border-radius:4px"> <div class="panel-heading" style="border-bottom:0px #dddddd; padding:10px 15px; border-top-left-radius:3px; border-top-right-radius:3px; border-top-color:#dddddd; border-right-color:#dddddd; border-left-color:#dddddd">

<a data-toggle="collapse" href="http://cbseacademic.nic.in/Revisedcurriculum_2021.html#collapse2" style="box-sizing:border-box; color:inherit; text-decoration:none; display:block; font-weight:bold">Revised Secondary Curriculum (IX-X)</a>

</div> </div> <div class="panel panel-default" style="border:1px solid #dddddd; margin-bottom:0px; border-radius:4px; margin-top:5px"> <div class="panel-heading" style="border-bottom:0px #dddddd; padding:10px 15px; border-top-left-radius:3px; border-top-right-radius:3px; border-top-color:#dddddd; border-right-color:#dddddd; border-left-color:#dddddd">

<a data-toggle="collapse" href="http://cbseacademic.nic.in/Revisedcurriculum_2021.html#collapse1" style="box-sizing:border-box; color:inherit; text-decoration:none; display:block; font-weight:bold">Revised Senior Secondary Curriculum (XI-XII)</a>

</div> </div> </div>
  • 2 answers

Vaibhav Pandey 4 years, 9 months ago

Noo it is not transitive

Sneha Panwar 4 years, 9 months ago

No as {3,4}, {4,5} and {3,5} does not belong to R
  • 3 answers

Akash Kumar 4 years, 8 months ago

Thanks

Pinky Pinky 4 years, 9 months ago

Continuity and differentinability Application of derivative Integrals Application of integrals Differential equations

Gurpreet Kaur 4 years, 9 months ago

Gsueve
  • 2 answers

Vignesh Babu 4 years, 9 months ago

???

Sneha Panwar 4 years, 9 months ago

Yes please tell
  • 2 answers

Pooja Jaat 4 years, 9 months ago

Thanks

Yogita Ingle 4 years, 9 months ago

Reflexive Relation

A relation in a set A is called reflexive relation if (a,a) ∈ R for every element a ∈ A.
Example:.
Let A = {1, 2, 3, 4,5,6,7,8,9,10} and define R = {(a, b) | a divides b}
We saw that R was reflexive since every number divides itself
Let A = {1, 2, 3, 4,5,6,7,8,9,10} and define R ={(1,1),(2,2),(2,3),(3,2),(4,4)}
We saw that R is not reflexive since every number is not present in R

  • 2 answers

Swathi Manogaran 4 years, 9 months ago

Xlog3+ x(logx-1) - xlog(x-1) +x + 1/3 log(3x-1) + c

Aryan Saini 4 years, 9 months ago

1
  • 3 answers

Vignesh Babu 4 years, 9 months ago

Want 12th reduce portion

Vignesh Babu 4 years, 9 months ago

This is 10th

Gaurav Seth 4 years, 9 months ago

HRD Minister Ramesh Nishank announced a major CBSE syllabus reduction for the new academic year 2020-21 on July 7 which was soon followed by an official notification by CBSE on the same.

Considering the loss of classroom teaching time due to the Covid-19 pandemic and lockdown, CBSE reduced the syllabus of classes 9 to 12 with the help of suggestions from NCERT.

Deleted syllabus of CBSE Class 10 Mathematics

 

 

  • 1 answers

Swathi Manogaran 4 years, 9 months ago

Formula Integral e^x[f(x)+f'(x)]dx=e^xf(x)+c Inte^x((1/1+cosx)+(sinx/1+cosx))dx Since (sinx/1+cosx)=f(x) (1/1+cosx)=f'(x) The solution is e^x(sinx/1+cosx)+c

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