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  • 1 answers

Student Of The Year 3 years, 10 months ago

I tried as much as possible and find that the upcoming number is that whose sum is 9, I.e. 333, 513, 72, etc...
  • 5 answers

Krish Phutela 3 years, 10 months ago

20

Pratik Kumar 3 years, 10 months ago

8-10

Nalin Ranjan 3 years, 10 months ago

20

Kartik . 3 years, 10 months ago

20 or16

Zeeshan Younis 3 years, 10 months ago

38
  • 5 answers

Shivani Chaurasiya 3 years, 10 months ago

1. ∫x n = x n+1 /n+1 + C. 2. ∫cos x = sin x + C. 3. ∫sin x = -cos x + C. 4. ∫sec 2 x = tan x + C. 5. ∫cosec 2 x = -cot x + C. 6. ∫sec x tan x = sec x + C. 7. ∫cosec x cot x = -cosec x + C. 8. ∫dx/√ 1- x 2 = sin -1 x + C.

Shivani Chaurasiya 3 years, 10 months ago

Are you from Azamgarh?

Shivani Chaurasiya 3 years, 10 months ago

Integral or integration?

Shivam Yadav 3 years, 10 months ago

What happen

Shivani Chaurasiya 3 years, 10 months ago

??
  • 4 answers

Student Of The Year 3 years, 10 months ago

Yes, 0/0=10/0=1 and here is the solution for that. Solution: Given: 0/00/0 Let,,,0/0=a/b0/0=a/b Where a=(0.5)2−(0.5)2a=(0.5)2−(0.5)2 And b=(0.5–0.5)b=(0.5–0.5) So, 0/0=a/b=>0/0=a/b=>[(0.5)2−(0.5)2]/(0.5−0.5)−−>[(0.5)2−(0.5)2]/(0.5−0.5)−−>(11) Solving ‘a’ It is in a2−b2a2−b2 form so it's value is (a+b)(a−b)(a+b)(a−b) a=[(0.5+0.5)(0.5–0.5)]a=[(0.5+0.5)(0.5–0.5)] Replace value of a in equation (1), 0/0=[(0.5+0.5)(0.5–0.5)]/(0.5–0.5)0/0=[(0.5+0.5)(0.5–0.5)]/(0.5–0.5) 0/0=0.5+0.5=>10/0=0.5+0.5=>1 Hence, 0/0=10/0=1. But on a serious note, this isn't true. Please do not take this seriously. Actually, 0/0 is not defined or infinity. And arithmetic operations do not hold true in case of not defined or infinity. For eg. ∞ + ∞ ≠ 2∞ ∞ + ∞ = ∞

Jyoti Kumari 3 years, 10 months ago

Hfbbkh

Kartar Singh Thukrana 3 years, 10 months ago

It's finite value can be determined by using limits

Kartar Singh Thukrana 3 years, 10 months ago

Undefined
  • 1 answers

Shubham Hatwal 3 years, 7 months ago

Let tan^3x =t then further solve it
  • 2 answers

Apoorva Rengasamy 3 years, 10 months ago

dx /d8=a cos^2 8/sin8 dy/d8= a cos8 So, dy / dx = tan 8

Shivam Yadav 3 years, 10 months ago

Plz write in right way
  • 1 answers

... Mmm ...... 3 years, 10 months ago

Let A vector = i^+j^+k^ and B vector =i^+j^-k^ And |A vector|=under root (1)sq.+(1)sq.+(1)sq. = under root 3 And |B vector|=under root (1)sq +(1)sq +(1)sq.=under root 3 And,so such possible answer are infinite
  • 5 answers

Maxout Khushit 3 years, 10 months ago

10

Shivansh Gupta 3 years, 10 months ago

=10

Suraj Yadav 3 years, 10 months ago

13+40-20-10-10+7-20

Shreya Rani 3 years, 10 months ago

?

Neha Chaurasiya 3 years, 10 months ago

10
  • 1 answers

Shivansh Kaushik 3 years, 10 months ago

Let cosA=x then cos(π−A)=−cosA=−x   Hence, cos−1x=A  cos−1(−x)=π−A  Adding them, cos−1x+cos−1(−x)=A+π−A⇒cos−1x+cos−1(−x)=π⇒cos−1(−x)=π−cos−1(x) This -1 is inverse here. Try to write each step clearly and you will get the answer.
  • 1 answers

Aadharshini Sudha 3 years, 10 months ago

Is this differentiation??
  • 0 answers
  • 2 answers

Shree Ram Faujdar 3 years, 10 months ago

Is this in syllabus?

Gaurav Seth 3 years, 10 months ago

A firm manufactures two types of products A and B and sells them at a profit of Rs.5 per unit of type A and Rs.3 per unit of type B. Each product is processed on two machines M 1 ​ and M 2 ​ . One unit of type A requires one minutes of processing time on M 1 ​ and two minutes of processing time on M 2 ​ , whereas one unit of type B requires one minutes of processing time on M 1 ​ and one minutes on M 2 ​ . Machines M 1 ​ and M 2 ​ are respectively available for at most 5 hours and 6 hours in a day. Find out how many units of each type of product should the firm produce a day in order to maximize the profit. Solve the problem graphically.

Answer:

  • 3 answers

Neha Chaurasiya 3 years, 10 months ago

????

Aadharshini Sudha 3 years, 10 months ago

Is this differentiation or integration?

Zeeshan Younis 3 years, 10 months ago

????
  • 0 answers
  • 2 answers

Megha. B 3 years, 10 months ago

Thanks

Gaurav Seth 3 years, 10 months ago

On July 7, HRD Minister Ramesh Pokhriyal announced a major CBSE syllabus reduction with 30% of the syllabus slashed for the year 2020-21 for classes 9 to 12 because of the reduction in classroom teaching time due to the Covid-19 pandemic and lockdown.

CBSE has rationalized the syllabus with the help of suggestions from NCERT and the same has been notified by a new CBSE notification as well.

Deleted syllabus of CBSE Class 12 Mathematics

 

 

  • 0 answers
  • 1 answers

Himanshu Singla 3 years, 10 months ago

Multiply on both side with A inverse as we know multiplication of A * A inverse is equals to identity matrix so answer will be A square
  • 2 answers

Mahi Kumari 3 years, 11 months ago

It may be this numerical solution not match with your answers of your textbook, but if it will be evaluated further then you can!!

Mahi Kumari 3 years, 11 months ago

(-1/√2)tan^-1(x/√2)+(2/√3)tan^-1(x/√3) + C
  • 3 answers

Tanish Saini 3 years, 11 months ago

2π/3

Harsh M 3 years, 11 months ago

2π/3

Deepdaman Singh 3 years, 11 months ago

2 pie/3
  • 1 answers

Premraj Verma 3 years, 11 months ago

X^4/4 - X^3/3 + X^2/2 - X - log|X|
  • 2 answers

Mahi Kumari 3 years, 11 months ago

{(x³-1)^7/3}/7 + {(x³-1)^4/3}/4 + C

Gaurav Seth 3 years, 11 months ago

given function is ∫(x³ - )^⅓ x^5.dx

let (x³ - 1) = t , and x³ = (1 + t)
⇒3x² = dt/dx
⇒dx = dt/3x²

So, ∫(x³ - 1)^⅓ x^5 * dt/3x²

⇒1/3 ∫t^⅓ (1 + t) *dt

⇒1/3 ∫(t^⅓ + t^{4/3}).dt

⇒1/3 ∫t^{1/3}.dt + 1/3∫t^{4/3}.dt

⇒1/3 + 1/3 + c

put the value of t in the above function,

.
 

  • 0 answers
  • 3 answers

Megha. B 3 years, 10 months ago

Y=cosx dy/dx= -sinx

Vivek Kumar 3 years, 11 months ago

dy/dx= -sinx

Aditya Raj 3 years, 11 months ago

Differentiate in terms of....???
  • 1 answers

Gaurav Seth 3 years, 11 months ago

The region bounded by the parabola y2 = 16x and the line x = 4 is the area OACO

The area OACO is symmetrical about x-axis 

Area of OACO = 2(Area of OAB)

Area of OACO = 

Therefore, the required area is 128/3 sq. units

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