No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 1 answers

Vɪʝɑɣ Gangwar 9 months, 4 weeks ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
  • Don't post personal information, mobile numbers and other details.
  • Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
  • Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
  • Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.
  • 1 answers

Shanika Sharma 10 months ago

Let √5 be a rational number. then it must be in form of p/q where, q≠0 ( p and q are co-prime) √5=p/q √5×q=p Squaring both side 5q²=p² --------------(1) p² is divisible by 5. So, p is divisible by 5. p=5c Squaring both side p²=25c2 -----------(2) Put p² in eqn.(1)
  • 3 answers

Ashutosh Soni Soni 9 months, 3 weeks ago

2.5

Vɪʝɑɣ Gangwar 9 months, 4 weeks ago

11/2
5.5.........
  • 0 answers
  • 1 answers

Prachi Kumari 10 months, 1 week ago

π/2
  • 1 answers

Swapnil Bajpai 10 months, 1 week ago

See you need to do first It is given that tan^-(1/1-x+x²) = tan^-[1/1-x(1-x)] We can write like this As x is taken common Now we can write numerator i.e. 1 as (1-x) + x ... Right? So tan^-[(1-x)+x /1-x(1-x)] We know the formula of Tan^x +tan^y= tan^( x+y/1-xy) On applying on it we get the above result as tan^(1-x) +tan^x Ab iske baad to khud hi kr sakti ho n ?? Ab diffentiate khud hi kr lena answer aa jayega pura solve kr dia hain okk thanks
  • 1 answers

Nobody 🌼🌼🌼 10 months, 2 weeks ago

Please complete the question!!!!!
  • 1 answers

Swapnil Bajpai 10 months, 1 week ago

No these are not equal vector as the condition of equal vector is that it must have same direction and same magnitude...... The above vector has same magnitude but the direction is not same .....thus these are not equal vector.
  • 0 answers
  • 0 answers
  • 3 answers

Devesh Rajput 10 months, 2 weeks ago

y=1/2log|1+x^2|+c

Ankur Jangra 10 months, 3 weeks ago

1/2log |1+x^2|+c

Ankur Jangra 10 months, 3 weeks ago

2log |1+x^2|+c
  • 2 answers

Ankur Jangra 10 months, 3 weeks ago

Log|y|=log|x|+c

Kanhaiya 10 months, 4 weeks ago

Ans: log(x)-log(y) =log c
  • 4 answers

Swati Punetha 10 months, 3 weeks ago

f(x)=log|x| dy/dx = 1/x

Ankur Jangra 10 months, 3 weeks ago

dy/dx =1/x

Rahul Agarwal 11 months ago

1/x

Sourabh Parashar 10 months, 3 weeks ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
  • Don't post personal information, mobile numbers and other details.
  • Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
  • Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
  • Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.
  • 0 answers
  • 1 answers

Kalu Ram 11 months ago

activity 11

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App