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Kumar Pratyush 11 months ago

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Surbhi Dalal 11 months, 2 weeks ago

All formula of vector
  • 3 answers

Account Deleted 11 months, 2 weeks ago

B+A

Sneha Chowdhury 11 months, 4 weeks ago

B+A
B+A
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Krish Agrawal 1 year ago

The integration of cos^3(x) can be solved using a trigonometric identity. Here's the integration step by step: ∫cos^3(x) dx = ∫(cos^2(x) * cos(x)) dx Now, you can use the identity cos^2(x) = 1 - sin^2(x): = ∫(1 - sin^2(x)) * cos(x) dx = ∫cos(x) dx - ∫(sin^2(x) * cos(x)) dx The first integral, ∫cos(x) dx, is straightforward and equals sin(x): = sin(x) - ∫(sin^2(x) * cos(x)) dx Now, for the remaining integral, you can use a u-substitution. Let u = sin(x), so du = cos(x) dx: = sin(x) - ∫(u^2 * du) Now, integrate u^2 with respect to u: = sin(x) - ∫u^2 du = sin(x) - (u^3 / 3) + C Now, replace u with sin(x): = sin(x) - (sin^3(x) / 3) + C So, the integral of cos^3(x) is: ∫cos^3(x) dx = sin(x) - (sin^3(x) / 3) + C, where C is the constant of integration.
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Ankit Singh 1 year ago

dy/dx= cosx +2sinx dy/ dx , dy/ dx ( 1-2sinx ) = cosx , dy / dx = cosx / 1-2 sinx
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Pranav Tyagi 1 year ago

Use by parts

Aman Kumar 1 year ago

syllbus katm ho gaya ka
  • 3 answers

Ankit Singh 1 year ago

22(2x^°-y^°)

Johirul Islam 1 year ago

3+5

Johirul Islam 1 year ago

5+6
  • 2 answers

Aseem Mahajan 1 year ago

write it like this
$$\left[\begin{array}{cc}6 & 5 \\ 1 & -1\end{array}\right]$$

Lavina ..... 1 year ago

[6 5] [-1 1]😂 =[6*-1 + 5*1] = [-6+5] =[-1] answer
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Ankit Singh 1 year, 1 month ago

(2a+3b)^2 -(2c)^2 =(2a+3b+2c) (2a+3b-2c) if it has to factorised
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Ankush Thakur 1 year, 1 month ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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