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  • 1 answers

Shanika Sharma 2 months, 4 weeks ago

Let √5 be a rational number. then it must be in form of p/q where, q≠0 ( p and q are co-prime) √5=p/q √5×q=p Squaring both side 5q²=p² --------------(1) p² is divisible by 5. So, p is divisible by 5. p=5c Squaring both side p²=25c2 -----------(2) Put p² in eqn.(1)
  • 3 answers

Ashutosh Soni Soni 2 months, 3 weeks ago

2.5

Vɪʝɑɣ Gangwar 2 months, 3 weeks ago

11/2

Account Deleted 3 months ago

5.5.........
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Prachi Kumari 3 months, 1 week ago

π/2
  • 1 answers

Swapnil Bajpai 3 months, 1 week ago

See you need to do first It is given that tan^-(1/1-x+x²) = tan^-[1/1-x(1-x)] We can write like this As x is taken common Now we can write numerator i.e. 1 as (1-x) + x ... Right? So tan^-[(1-x)+x /1-x(1-x)] We know the formula of Tan^x +tan^y= tan^( x+y/1-xy) On applying on it we get the above result as tan^(1-x) +tan^x Ab iske baad to khud hi kr sakti ho n ?? Ab diffentiate khud hi kr lena answer aa jayega pura solve kr dia hain okk thanks
  • 1 answers

Account Deleted 3 months, 2 weeks ago

Please complete the question!!!!!
  • 1 answers

Swapnil Bajpai 3 months, 1 week ago

No these are not equal vector as the condition of equal vector is that it must have same direction and same magnitude...... The above vector has same magnitude but the direction is not same .....thus these are not equal vector.
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  • 3 answers

Devesh Rajput 3 months, 2 weeks ago

y=1/2log|1+x^2|+c

Ankur Jangra 3 months, 3 weeks ago

1/2log |1+x^2|+c

Ankur Jangra 3 months, 3 weeks ago

2log |1+x^2|+c
  • 2 answers

Ankur Jangra 3 months, 3 weeks ago

Log|y|=log|x|+c

Kanhaiya 3 months, 4 weeks ago

Ans: log(x)-log(y) =log c
  • 4 answers

Swati Punetha 3 months, 3 weeks ago

f(x)=log|x| dy/dx = 1/x

Ankur Jangra 3 months, 3 weeks ago

dy/dx =1/x

Rahul Agarwal 3 months, 4 weeks ago

1/x

Sourabh Parashar 3 months, 3 weeks ago

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Kalu Ram 3 months, 4 weeks ago

activity 11
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Kumar Pratyush 4 months ago

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