Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Jyoti Singh 3 years, 6 months ago
- 2 answers
Posted by Sharon Jr 3 years, 6 months ago
- 0 answers
Posted by Harpreet Kaur 3 years, 6 months ago
- 0 answers
Posted by Harsh Phadwa 3 years, 6 months ago
- 0 answers
Posted by Tushar Shukla 3 years, 6 months ago
- 4 answers
Mr. Badmash 3 years, 6 months ago
Posted by Aayush Raj 3 years, 6 months ago
- 1 answers
Satyam Suman 3 years, 6 months ago
Posted by Abhishek G M 3 years, 6 months ago
- 1 answers
Shikha Singh 3 years, 6 months ago
Posted by Aman Gautam 3 years, 6 months ago
- 0 answers
Posted by Kajal Kumari 3 years, 6 months ago
- 1 answers
Posted by Prabhat Yadav 3 years, 6 months ago
- 5 answers
Kartik Chhabra 3 years, 6 months ago
Prince Prabhat 3 years, 6 months ago
Posted by Aditi Kawat 3 years, 6 months ago
- 0 answers
Posted by Dharamveer Sain 3 years, 6 months ago
- 2 answers
Posted by Naman Kumawat 3 years, 6 months ago
- 5 answers
Arman Gupta 3 years, 6 months ago
Posted by Ashutosh Tiwari 3 years, 6 months ago
- 5 answers
Mohit Bansal 3 years, 6 months ago
Ankit ?? Kumar 3 years, 6 months ago
Posted by Elavarasan Appu 3 years, 6 months ago
- 0 answers
Posted by Anurag Saral 3 years, 6 months ago
- 4 answers
Arman Gupta 3 years, 6 months ago
Posted by Dhananjay Rajput 3 years, 6 months ago
- 5 answers
Posted by Arnab H. 3 years, 6 months ago
- 2 answers
Arpit Airen 3 years, 6 months ago
Here I will tell you how to find F0g & hope you will find the remaining.
f0g is pronounced as f of g(x)
f0g = f{g(x)} = f {{tex}x \over x^2 +1{/tex}}
We have put the value of g(x) given in question.
Now let us assume that {tex}{x \over x^2 +1} = y{/tex}
Therefore, f {{tex}x \over x^2 +1{/tex}} = f{y}
as f{x} = 3x+2
f{y} = 3y +2
Therefore
f{{tex}{x \over x^2 +1}{/tex}} = 3 * {tex}{x \over x^2 +1}{/tex} + 2
=> f0g = {tex}{3x \over x^2 +1} +2 {/tex}
On Solving
f0g = {tex}{3x + 2x^2 +2\over x^2 +1}{/tex}
Answer.
Posted by Khusbu Pradhan 3 years, 6 months ago
- 3 answers
Posted by Narayan Sirohi 3 years, 6 months ago
- 1 answers
Dhananjay Rajput 3 years, 6 months ago
Posted by Diya Varghese 3 years, 6 months ago
- 0 answers
Posted by Roshni Biswal 3 years, 6 months ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Jyoti Singh 3 years, 5 months ago
0Thank You