Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Ashutosh Tiwari 4 years, 4 months ago
- 5 answers
Mohit Bansal 4 years, 4 months ago
Ankit ?? Kumar 4 years, 5 months ago
Posted by Elavarasan Appu 4 years, 5 months ago
- 0 answers
Posted by Anurag Saral 4 years, 5 months ago
- 4 answers
Arman Gupta 4 years, 5 months ago
Posted by Dhananjay Rajput 4 years, 5 months ago
- 5 answers
Posted by Arnab H. 4 years, 5 months ago
- 2 answers
Account Deleted 4 years, 5 months ago
Here I will tell you how to find F0g & hope you will find the remaining.
f0g is pronounced as f of g(x)
f0g = f{g(x)} = f {{tex}x \over x^2 +1{/tex}}
We have put the value of g(x) given in question.
Now let us assume that {tex}{x \over x^2 +1} = y{/tex}
Therefore, f {{tex}x \over x^2 +1{/tex}} = f{y}
as f{x} = 3x+2
f{y} = 3y +2
Therefore
f{{tex}{x \over x^2 +1}{/tex}} = 3 * {tex}{x \over x^2 +1}{/tex} + 2
=> f0g = {tex}{3x \over x^2 +1} +2 {/tex}
On Solving
f0g = {tex}{3x + 2x^2 +2\over x^2 +1}{/tex}
Answer.
Posted by Khusbu Pradhan 4 years, 5 months ago
- 3 answers
Posted by Narayan Sirohi 4 years, 5 months ago
- 1 answers
Dhananjay Rajput 4 years, 5 months ago
Posted by Diya Varghese 4 years, 5 months ago
- 0 answers
Posted by Roshni Biswal 4 years, 5 months ago
- 1 answers
Posted by Abhishek Parihar 4 years, 5 months ago
- 1 answers
Satyam Suman 4 years, 5 months ago
Posted by Umesh Natekar 4 years, 5 months ago
- 0 answers
Posted by Shashank Agrawal 4 years, 5 months ago
- 5 answers
Posted by Deepanshu Tyagi 4 years, 5 months ago
- 2 answers
Posted by ❤️Ritesh Gupta? 4 years, 5 months ago
- 0 answers
Posted by ❤️Ritesh Gupta? 4 years, 5 months ago
- 5 answers
Posted by Bidisha Halder 4 years, 5 months ago
- 3 answers
Posted by Keep On It 4 years, 5 months ago
- 1 answers
Posted by Neeraj Panchal 4 years, 5 months ago
- 2 answers
Satyam Suman 4 years, 5 months ago
Posted by Tec Om 4 years, 5 months ago
- 4 answers
Posted by Aastha ?✨ 4 years, 5 months ago
- 5 answers
Royal Thakur ? 4 years, 5 months ago
Posted by Neev Garg 4 years, 5 months ago
- 5 answers
Vivek Chaurasia 4 years, 5 months ago
Posted by Aditi Singh 4 years, 5 months ago
- 1 answers
Tec Om 4 years, 5 months ago
Posted by Aishu ? 4 years, 5 months ago
- 1 answers
Vivek Chaurasia 4 years, 5 months ago
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app