No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 0 answers
  • 1 answers

Muskan Khan 6 years, 3 months ago

I'll suggest u to have a look over videos related to this on u tube
  • 1 answers

Sanchit Srivastava 6 years, 3 months ago

Are u sure that your question are appropriate?
  • 6 answers

Vishal Kumar 6 years, 3 months ago

MTG and NCERT EXAMPLER are also better books to score 99%

S.....Sharma☺??? .. 6 years, 3 months ago

Ncert se aapke marks maximum 80 to 85 aa sakte h ya to aap complete ncert + 5 years previous question kare ya fir rd sharma

Nikhil Agarwal 6 years, 3 months ago

Ncert

Bilal Ahmed 6 years, 3 months ago

NCERT only

Ritik Kumar 6 years, 3 months ago

Do all questions of ncert you will get ?

Ansh Gandhi 6 years, 3 months ago

Shiv das
  • 1 answers

Tanuja Varshney 6 years, 3 months ago

Equal ke baad kya likha hai aapne
  • 4 answers

Nisha Pahadwa 6 years, 3 months ago

Cosx - sinx

Nikhil Agarwal 6 years, 3 months ago

Cosx-sinx

Madhu Jangra 6 years, 3 months ago

dy/dx= cos x- sin x....i.e. y' of sin x = cos x and y' of cos x = -sin x

Sneha Bansal 6 years, 3 months ago

dy/ dx = cos x - sin x
  • 1 answers

Sia ? 6 years, 3 months ago

The given inverse trigonometric function is 

tan {tex}\left[ 2 \tan ^ { - 1 } (\frac { 1 } { 5 } )\right]{/tex}

Now, {tex}\tan \left( 2 \tan ^ { - 1 } \frac { 1 } { 5 } \right) = \tan \left[ \tan ^ { - 1 } \left( \frac { 2 \times \frac { 1 } { 5 } } { 1 - \left( \frac { 1 } { 5 } \right) ^ { 2 } } \right) \right]{/tex}
{tex}\left[ \because 2 \tan ^ { - 1 } x = \tan ^ { - 1 } \left( \frac { 2 x } { 1 - x ^ { 2 } } \right) ; - 1 < x < 1 \right]{/tex}
{tex}= \tan \left[ \tan ^ { - 1 } \left( \frac { 2 \times 5 } { 24 } \right) \right] = \tan \left[ \tan ^ { - 1 } \left( \frac { 5 } { 12 } \right) \right] = \frac { 5 } { 12 }{/tex}
{tex}\left[ \because \tan \left( \tan ^ { - 1 } x \right) = x ; \forall x \in R \right]{/tex}

  • 4 answers

Nikhil Agarwal 6 years, 3 months ago

45

Madhu Jangra 6 years, 3 months ago

Total students = 81 girls =4/9 ×81 = 36 boys = total- girls = 81-36 = 45 boys

Muskan Khan 6 years, 3 months ago

45

Naveen Kumar Sharma 6 years, 3 months ago

45 boys
  • 1 answers

Nikhil Agarwal 6 years, 3 months ago

Log (-2x-1)
  • 6 answers

Yasir Khan 6 years, 3 months ago

Solve ncert and then go for at least 5-6 last year papers ....this will most probably get u 100% in maths if u do it the right way.. Hope this helps! ?? All the best!

Preeti Bartwal 6 years, 3 months ago

Ncert best book

???. Pragati 6 years, 3 months ago

Ncert

Rudra Singh 6 years, 3 months ago

RS Aggrwal is the best book

Aniket Sharma 6 years, 3 months ago

Xam idea maths

Nishu Sahu 6 years, 3 months ago

Ncert
  • 2 answers

Shubham Singhal 6 years, 3 months ago

https://drive.google.com/file/d/1wp8h__ibM6y17SAKlP0lQK844oM7X9cw/view?usp=sharing

Rohitas Meena 6 years, 3 months ago

Is countinous at x=0
  • 1 answers

Rohitas Meena 6 years, 3 months ago

{-sinx*sinx}-cosx*(1+cosx)}\sin^2x
  • 1 answers

S.....Sharma☺??? .. 6 years, 3 months ago

First learn or clear all the properties then for solving question first see the ans. Of queation and then try to do yourself maximum 5 qustion solve like that now concept of property slightly clear in your mind now u try to solve question yourself
  • 1 answers

Rohitas Meena 6 years, 3 months ago

(12x^2-1/8√4x^3-1 )-5sin^2(5x+8)
  • 2 answers

Sarita Raj 6 years, 3 months ago

Thnq

Manmeet Kaur 6 years, 3 months ago

It is not available right now. Sample papers will be alloted to class 12 after december
  • 0 answers
  • 5 answers

Amaresh Khened 6 years, 3 months ago

I cannot understand ,nihal ojha answer it by giving space

Nikhil Agarwal 6 years, 3 months ago

a/bsina

Nihal Ojha 6 years, 3 months ago

sinA/cosA = a/b Squaring both sides sin²A/cos²A = a²/b² adding 1 to both sides sin²A+cos²A/cos²A = a²+b²/b² 1/cos²A = a²+b²/b² sec²A = a²+b²/b² secA = (underoot a²+b²) /b

Ashish Singh 6 years, 3 months ago

Bcosx

Akhileshwar Singh 6 years, 3 months ago

SecA=b/underroot a^2+b^2.
  • 1 answers

Ritu R 6 years, 3 months ago

a = 1 and b= 0
  • 0 answers
  • 1 answers

Ajay Rajput 6 years, 3 months ago

-1/√1-x^2
  • 1 answers

Rishabh Rathi 6 years, 3 months ago

It will be the graph of sinx. Cos(x-pi/2)=cos(pi/2-x) since inside cos negative gets diluted.
  • 1 answers

Rishabh Rathi 6 years, 3 months ago

Draw line. Y=2X and shade the region above it since y is greater than 2x.
  • 6 answers

Harshit Raj 6 years, 3 months ago

Problems in mathematics by Dorofeev

Priya Dharshini 6 years, 3 months ago

U can use rs agarwal,rd sharma for boards and cengage for jee

Aditya Dwivedi 6 years, 3 months ago

https://amzn.to/2X8rNzQ use this to buy on amazon

Aditya Dwivedi 6 years, 3 months ago

use cengage good reference book for jee as well as board

Rishabh Rathi 6 years, 3 months ago

R. D and ncert should be enough for boards.

S.....Sharma☺??? .. 6 years, 3 months ago

I think RD sharma is best
  • 2 answers

Rishabh Rathi 6 years, 3 months ago

Its 0.4m/s

Rishabh Rathi 6 years, 3 months ago

0.4 Write constraint equation which will give dy/dt=(h/H-h) dx/dt. Here dy/dt will give speed of shadow and dx/dt is speed of man, h is height of man and H is height of lamp.

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App