Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Neha Yadav 6 years, 3 months ago
- 0 answers
Posted by Pardeep Choudhary 6 years, 3 months ago
- 1 answers
Ritesh Chakraborty 6 years, 3 months ago
Posted by Funny Baba 6 years, 3 months ago
- 1 answers
Becky Shoshannah 6 years, 3 months ago
Posted by Shatakshi Rawat 6 years, 3 months ago
- 4 answers
Prashant Singh 6 years, 3 months ago
Prashant Singh 6 years, 3 months ago
Posted by Shatakshi Rawat 6 years, 3 months ago
- 0 answers
Posted by Abhay Tiwari 6 years, 3 months ago
- 0 answers
Posted by Akshit Kumar 6 years, 3 months ago
- 0 answers
Posted by Kajal Tongbram 6 years, 3 months ago
- 1 answers
Sia ? 6 years, 3 months ago
Check NCERT Solutions here : https://mycbseguide.com/ncert-solutions.html
Posted by Atul Sinha 6 years, 3 months ago
- 1 answers
Posted by Veer Rathi 6 years, 3 months ago
- 2 answers
Posted by Kuljit Singh Chouhan 6 years, 3 months ago
- 4 answers
Posted by Himanshu Prajapati 6 years, 3 months ago
- 2 answers
Santy Baralu 6 years, 3 months ago
Posted by Manish Yadav 6 years, 3 months ago
- 1 answers
Posted by Naren Ranjan Sharma 6 years, 3 months ago
- 1 answers
Sia ? 6 years, 3 months ago
A perfect number is a positive integer that is equal to the sum of its positive divisors, excluding the number itself. For instance, 6 has divisors 1, 2 and 3, and 1 + 2 + 3 = 6, so 6 is a perfect number.
Posted by Techinical Nikhil 6 years, 3 months ago
- 0 answers
Posted by Yug Agarwal 6 years, 3 months ago
- 0 answers
Posted by Yug Agarwal 6 years, 3 months ago
- 0 answers
Posted by Sachin Kumar 6 years, 3 months ago
- 4 answers
S.....Sharma☺??? .. 6 years, 3 months ago
Santy Baralu 6 years, 3 months ago
Priya Dharshini 6 years, 3 months ago
Posted by Arya Pratik 6 years, 3 months ago
- 2 answers
Posted by Anjali Sharma 6 years, 3 months ago
- 1 answers
Posted by Kunal Mandal 6 years, 3 months ago
- 8 answers
Kumar Vishal Behera 6 years, 3 months ago
Mithlesh Prajapati 6 years, 3 months ago
Posted by Manish Purohit 6 years, 3 months ago
- 0 answers
Posted by Sangeeta Sakre 6 years, 3 months ago
- 1 answers
Sia ? 6 years, 3 months ago
You can check last year papers here : https://mycbseguide.com/cbse-question-papers.html
Posted by Pranav Goyal 6 years, 3 months ago
- 1 answers
Sia ? 6 years, 3 months ago
{tex}\vec a = 2\hat i + 4\hat j - 5\hat k{/tex}
{tex}\vec b = \lambda \hat i + 2\hat j + 3\hat k{/tex}
{tex}\vec a + \vec b = \left( {2 + \lambda } \right)\hat i + 6\hat j - 2\hat k{/tex}
Unit vector along
{tex}\vec a + \vec b = \frac{{\vec a + \vec b}}{{\left| {\vec a + \vec b} \right|}}{/tex}
{tex}= \frac{{\left( {2 + \lambda } \right)\hat i + 6\hat j - 2\hat k}}{{\sqrt {{{\left( {2 + \lambda } \right)}^2} + {{\left( 6 \right)}^2} + {{\left( { - 2} \right)}^2}} }}{/tex}
{tex}= \frac{{\left( {2 + \lambda } \right)\hat i + 6\hat j - 2\hat k}}{{\sqrt {{{\left( {2 + \lambda } \right)}^2} + 40} }}{/tex}
ATQ , {tex}\vec c.\left( {\vec a + \vec b} \right) = 1{/tex}
{tex}\left( {\hat i + \hat j + \hat k} \right).\left( {\frac{{\left( {2 + \lambda } \right)\hat i + 6\hat j - 2\hat k}}{{{{\left( {2 + \lambda } \right)}^2} + 40}}} \right) = 1{/tex}
{tex}\frac{{\left( {2 + \lambda } \right) + 6 - 2}}{{\sqrt {{{\left( {2 + \lambda } \right)}^2} + 40} }} = 1{/tex}
{tex}2 + \lambda + 4 = \sqrt {{{\left( {2 + \lambda } \right)}^2} + 40} {/tex}
Sq both sides,
{tex}{\lambda ^2} + 36 + 12\lambda = {\left( {2 + \lambda } \right)^2} + 40{/tex}
{tex}\lambda = 1{/tex}
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app