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  • 1 answers

S.....Sharma☺??? .. 6 years, 3 months ago

Aapko ncert ka wo chapter karene chahea jo jyada marks cover karte h or agar time bache to complete ncert question slve kare
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Rishabh Rathi 6 years, 3 months ago

Consider values given in radian

Rishabh Rathi 6 years, 3 months ago

Tan5-Tan5Tan3Tan2
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Rishabh Rathi 6 years, 3 months ago

x=1/4 Use arctan a + arctan b = arctan (a+b/1-ab) Compare the terms inside inverse. You will get a quadratic. Reject the answer which is negative since identy used above is for positive and ab<1.
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Sia ? 6 years, 3 months ago

Matrix form of given equations is AX = B

{tex}\Rightarrow \left[ {\begin{array}{*{20}{c}} 4&{ - 3} \\ 3&{ - 5} \end{array}} \right]\left[ {\begin{array}{*{20}{c}} x \\ y \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} 3 \\ 7 \end{array}} \right]{/tex}

Here {tex}A = \left[ {\begin{array}{*{20}{c}} 4&{ - 3} \\ 3&{ - 5} \end{array}} \right],X = \left[ {\begin{array}{*{20}{c}} x \\ y \end{array}} \right]{/tex} and {tex}B = \left[ {\begin{array}{*{20}{c}} 3 \\ 7 \end{array}} \right]{/tex}

{tex}\therefore \left| A \right| = \left| {\begin{array}{*{20}{c}} 4&{ - 3} \\ 3&{ - 5} \end{array}} \right| {/tex} = - 20 - (-9) = - 20 + 9 = - 11 {tex} \ne {/tex} 0

Therefore, solution is unique and {tex}X = {A^{ - 1}}B = \frac{1}{{\left| A \right|}}\left( {adj.A} \right)B{/tex}

{tex}\Rightarrow \left[ {\begin{array}{*{20}{c}} x \\ y \end{array}} \right] = \frac{1}{{ - 11}}\left[ {\begin{array}{*{20}{c}} { - 5}&3 \\ { - 3}&4 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} 3 \\ 7 \end{array}} \right]{/tex}

{tex}= \frac{1}{{ - 11}}\left[ {\begin{array}{*{20}{c}} { - 15 + 21} \\ { - 9 + 28} \end{array}} \right] = \frac{1}{{ - 11}}\left[ {\begin{array}{*{20}{c}} 6 \\ 9 \end{array}} \right]{/tex}

{tex}= \left[ {\begin{array}{*{20}{c}} {\frac{{ - 6}}{{11}}} \\ {\frac{{ - 19}}{{11}}} \end{array}} \right]{/tex}

Therefore, {tex}x = \frac{{ - 6}}{{11}}{/tex} and {tex}y = \frac{{ - 19}}{{11}}{/tex}

Manesh Tandel 6 years, 3 months ago

x=-0.5454 y=-1.727
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Anisha Sharma 6 years, 3 months ago

Question *

Anisha Sharma 6 years, 3 months ago

So...?? Please correct your wsn
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Abhi Bhardwaj 6 years, 3 months ago

Ohk
  • 1 answers

S.....Sharma☺??? .. 6 years, 3 months ago

Hume phadhna to fir bhi padega paper easy aayega ya hard ye to pata hum nahi laga sakte may be easy ho but mcq or 1 marks question solve karne ka lya hume detail se phadhna hoga
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Meenakshi Kureel 6 years, 3 months ago

Ok thxs

Rishabh Rathi 6 years, 3 months ago

Approximately 2.8
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Rishabh Rathi 6 years, 3 months ago

44
  • 2 answers

Sia ? 6 years, 3 months ago

You can refer to topper's answer sheets.

S.....Sharma☺??? .. 6 years, 3 months ago

Aap previous year question + ncert =rd sharma=que 100 marks
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Shivam Yadav 6 years, 3 months ago

No compart is not hard but if you think hard so it hard do ncert and sample papers

Priya Dharshini 6 years, 3 months ago

Yes some what hard but u can do it surely... dont think exam will be hard and all.... make sure that ur preparations are so hard that u can write all hard exams easily...

Anisha Sharma 6 years, 3 months ago

Yes compartment exam is harder than main exam.... And there is no sir and ma'am...... All are students here....... So please don't say sir
  • 2 answers

Priya Dharshini 6 years, 3 months ago

Do ncert questions and previous year question papers..

Prateek Dwivedi Dwivedi 6 years, 3 months ago

Sir pls tell compartment tips
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Gaurang Bansal 6 years, 3 months ago

Yes
  • 1 answers

Gaurav Seth 6 years, 3 months ago

 

Question: Two concentric circles of radii a and b(a>b)are given.Find the length of the chord of the larger circle which touches the smaller circle.

Explanation:

 

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S.....Sharma☺??? .. 6 years, 3 months ago

Go to maths and then cbse syllabus

S.....Sharma☺??? .. 6 years, 3 months ago

Aapko aapka answer ise app par mil jaayega
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Harsh Vardhan 6 years, 3 months ago

Write sinx in numerator sin(x+a-a) and expand it sin(a-b) take a=x+a and b=a take denominator on both differently
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Priya Dharshini 6 years, 3 months ago

Only five subjects are there in cbse for class 12th. If maths is ur one of the main subject then they will show the results for sure.

Charu Vatsal 6 years, 3 months ago

But it shouldn't be done like this, I have heard that if someone has an additional subject then the good marks among additional and another subject are counted in the result

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