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  • 1 answers

Aseem Mahajan 2 years, 5 months ago

<font face ="Times New Roman">$$A = \left[\begin{array}{cc}\rm -3 -5i & 2+4i \\ \rm 6+7i & 1+8i\end{array}\right]$$
$$A^T\left[\begin{array}{cc}\rm -3 -5i & 6+7i \\ \rm 2+4i & 1+8i\end{array}\right]$$
$$A^H = \left[\begin{array}{cc}\rm -3 +5i & 6-7i \\ \rm 2-4i & 1-8i\end{array}\right]$$
  • 1 answers

Aseem Mahajan 2 years, 5 months ago

<font face ="Times New Roman">Given:
$$\left[ \begin{array}{cc}\rm 3 & 0\\ \rm a-2 & 2 \end{array}\right]$$ = $$\left[ \begin{array}{cc}\rm 3 & 0\\ \rm 1 & 2 \end{array}\right]$$
For this equality condition,
a - 2 = 1
Hence , a = 3
  • 5 answers

Aseem Mahajan 2 years, 4 months ago

<font face ="Courier New" size ="2">for i in rabge

Aseem Mahajan 2 years, 4 months ago

<font face ="Courier New" size ="5">for i in rabge

Aseem Mahajan 2 years, 4 months ago

<font face ="Courier New" size ="12">for i in range

Aseem Mahajan 2 years, 4 months ago

<font face ="Courier New" size ="12">

Hitkar Miglani 2 years, 5 months ago

Ans = π^2 / 2
  • 3 answers

Anshu Yadav 2 years, 5 months ago

(√2-i)-i(1-√2i) =√2-i-i+i.i√2 =√2+i²√2-2i = -2i

Aseem Mahajan 2 years, 5 months ago

<font face ="Times New Roman">-2i

Sakshi Sonvane 2 years, 5 months ago

.
  • 1 answers

Aseem Mahajan 2 years, 4 months ago

<font face ="Courier New" size ="3">for i in range
  • 2 answers

Aseem Mahajan 2 years, 5 months ago

<font face ="Times New Roman">Incomplete answer. Tell complete one. It does not tell how question will solve.

T メ Rex 彡 Krishan 2 years, 5 months ago

Take x^4 as( x^2)^2
  • 3 answers

Aseem Mahajan 2 years, 5 months ago

<font face ="Times New Roman">Thanks, but to see correct question add course of jee main and check my correct question there.

Sanskriti Kumari 2 years, 5 months ago

We know, lim n 0 ^ sin(u) m =1 lim sin(- 1/x) u -> e (1/x) then I∞ 91 tx + 1/4 = y 94 lim y -> ∞ (sin y)/y which means y (Delta*in - ∞)/(∞) tim Since, range of sine function is [-1,1] lim as divided any by constant number in 0.

Aseem Mahajan 2 years, 5 months ago

This is the question:
$$\displaystyle \lim_{x \to 1}\left[\dfrac{a + sin(x-1) - ax}{x + sin(x-1) - 1}\right]^{\dfrac{1-x}{1-\sqrt{x}} = \dfrac{1}{4}$$
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  • 1 answers

Nishant Jha 2 years, 5 months ago

No
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Aseem Mahajan 2 years, 5 months ago

<font face ="Times New Roman">1/x + cotx
  • 2 answers

Nishant Jha 2 years, 5 months ago

Yes

Aseem Mahajan 2 years, 5 months ago

<font face ="Times New Roman">Yes
$$\left|\begin{array}{ccc}0 & 0 & 0 \\ 0 & 0 & 0\\ 0 & 0 & 0\end{array}\right|$$
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Aseem Mahajan 2 years, 5 months ago

<font face ="Times New Roman"> 2/7 , -3/7 , 6/7
  • 2 answers

Aseem Mahajan 2 years, 5 months ago

<font face ="Times New Roman">#Harshita Sharma that is for the session 2022-23. He is a student of 2021-22 , because for his badge board exams are going on.

Blueprint is same as the SQP released by cbse <a href="https://cbseacademic.nic.in/SQP_CLASSXII_2021-22.html">here

Harshita Sharma 2 years, 5 months ago

There is no term 1 and term 2 .. Now on wards there is only whole anual exam of 80 marks
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  • 1 answers

Bhumi Singh 2 years, 6 months ago

Tronometric formula

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