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Aseem Mahajan 3 years, 2 months ago
Tell ids here and i see than.
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Aseem Mahajan 3 years, 3 months ago
$$A^T\left[\begin{array}{cc}\rm -3 -5i & 6+7i \\ \rm 2+4i & 1+8i\end{array}\right]$$
$$A^H = \left[\begin{array}{cc}\rm -3 +5i & 6-7i \\ \rm 2-4i & 1-8i\end{array}\right]$$
Posted by Manav Sharma 3 years, 3 months ago
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Aseem Mahajan 3 years, 3 months ago
$$\left[ \begin{array}{cc}\rm 3 & 0\\ \rm a-2 & 2 \end{array}\right]$$ = $$\left[ \begin{array}{cc}\rm 3 & 0\\ \rm 1 & 2 \end{array}\right]$$
For this equality condition,
a - 2 = 1
Hence , a = 3
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