Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Baba Tushir 2 years, 3 months ago
- 1 answers
Preeti Dabral 2 years, 3 months ago
∫xlog2xdx
=∫(log2x)xdx
=(log2x)∫xdx−∫[ddxlog2x∫xdx]dx
[Applying product rule]
=(log2x)x22−∫12x.2.x22dx
=12x2log2x−12∫xdx
=12x2log2x−12x22+c
=x22log2x−x24+c
Posted by Subhodeep Mitra 2 years, 5 months ago
- 2 answers
Rashmi Ahuja 2 years, 5 months ago
Posted by Tanmaya Padhi 2 years, 5 months ago
- 1 answers
Posted by Pradhuman Yadav 2 years, 5 months ago
- 0 answers
Posted by Devendra Kumar 2 years, 3 months ago
- 1 answers
Preeti Dabral 2 years, 3 months ago
Given: y=sin−1(2x1+x2)
To simplify the given Inverse Trigonometric function,we put, x=tanθ
⇒y=sin−1(2tanθ1+tan2θ)=sin−1(sin2θ)=2θ
⇒y=2tan−1x
⇒dydx=2.11+x2=21+x2
Posted by Shivam Mandloi 2 years, 5 months ago
- 1 answers
Posted by Laksh Aggarwal 2 years, 5 months ago
- 0 answers
Posted by Gurkirat Kaur 2 years, 6 months ago
- 1 answers
Posted by Ajit Shrivastav 11 A 2 years, 3 months ago
- 1 answers
Preeti Dabral 2 years, 3 months ago
limx→2−f(x)=limx→2−2x+1
limh→0[2(2−h)+1] = 5
=limx→2+f(x)=limx→2+(3x−1)
=limh→03(2+h)−1 = 5
In given that question f(x) is continuous at x=2,therefore
limx→2−f(x)=f(2)=limx→2+f(x)
5 = k
⇒k=5
Posted by Shubhanshu Tiwari 2 years, 6 months ago
- 1 answers
Posted by Harshit Sharma 2 years, 6 months ago
- 1 answers
Posted by Piyush Kumar Mishra 2 years, 6 months ago
- 0 answers
Posted by Priya Rai 2 years, 6 months ago
- 0 answers
Posted by Hari Sharma 2 years, 6 months ago
- 0 answers
Posted by Bahima Saliha 2 years, 6 months ago
- 3 answers
Tec Om 2 years, 6 months ago
Posted by Aditya Yadav 2 years, 6 months ago
- 1 answers
Posted by Kaif Khan 2 years, 6 months ago
- 0 answers
Posted by Umashankar Umashankar 2 years, 6 months ago
- 0 answers
Posted by Umashankar Umashankar 2 years, 6 months ago
- 0 answers
Posted by Jagveer Singh 2 years, 6 months ago
- 0 answers
Posted by Kartik Gupta 2 years, 6 months ago
- 0 answers
Posted by Kaif Khan 2 years, 6 months ago
- 0 answers
Posted by Mini Lodhi 2 years, 6 months ago
- 1 answers
Posted by Priya Yadav 2 years, 6 months ago
- 1 answers
Posted by Waheguru Ji Ji 2 years, 7 months ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Preeti Dabral 2 years, 4 months ago
Now, C{x) = 160 - 0.08x
For maxima/minima, put C'(x) = 0
⇒ 160 = 0.08x
⇒ x = 2000
Now, we have C(0) = 5000000
C(2000) = 5160000 and C(4500) = 4910000
∴ Maximum value of C(x) would be ₹5160000
0Thank You