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  • 1 answers

Preeti Dabral 2 years, 4 months ago

  1. (c) Let C(x) be the maintenance cost function, then C(x) = 5000000 + 160x - 0.04x2
  2. (b) We have, C(x) = 5000000 + 160x - 0.04x2
    Now, C{x) = 160 - 0.08x
    For maxima/minima, put C'(x) = 0
    160 = 0.08x
    x = 2000
  3. (b) Clearly, from the given condition we can see that we only want critical points that are in the interval [0, 4500]
    Now, we have C(0) = 5000000
    C(2000) = 5160000 and C(4500) = 4910000
     Maximum value of C(x) would be ₹5160000
  4. (a) The complex must have 4500 apartments to minimise the maintenance cost.
  5. (a) The minimum maintenance cost for each apartment woud be ₹1091.11
  • 1 answers

Preeti Dabral 2 years, 3 months ago

xlog2xdx

=(log2x)xdx

=(log2x)xdx[ddxlog2xxdx]dx

[Applying product rule]

=(log2x)x2212x.2.x22dx

=12x2log2x12xdx

=12x2log2x12x22+c

=x22log2xx24+c

  • 2 answers

Dhairya Sharma 2 years, 5 months ago

Hii rashmi you are from which class

Rashmi Ahuja 2 years, 5 months ago

Root(1+cos x) =root(2cos² (x/2)) =√2.cos x/2 Ans= Integral of 1/√2 cos x/2 = Integral of sec (x/2)/√2 = (1/√2) log |sec x/2 + tan x/2| ÷ (1/2) = √2 log |sec x/2 + tan x/2|
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  • 1 answers

Preeti Dabral 2 years, 3 months ago

Given: y=sin1(2x1+x2)

To simplify the given Inverse Trigonometric function,we put, x=tanθ 

y=sin1(2tanθ1+tan2θ)=sin1(sin2θ)=2θ

y=2tan1x

dydx=2.11+x2=21+x2

  • 1 answers

Satinder Kaur Sidhu 2 years, 5 months ago

1/x
  • 0 answers
  • 1 answers

Karan Chauhan 2 years, 5 months ago

x³/3+x²/2+x+c
  • 1 answers

Preeti Dabral 2 years, 3 months ago

limx2f(x)=limx22x+1
limh0[2(2h)+1] = 5
=limx2+f(x)=limx2+(3x1)
=limh03(2+h)1 = 5
In given that question f(x) is continuous at x=2,therefore
limx2f(x)=f(2)=limx2+f(x)
5 = k 
k=5

  • 1 answers

The Thakur Shahab 2 years, 6 months ago

1
  • 1 answers

Pihu Agarwal 2 years, 5 months ago

1/4 log|sec4x+tan4x|-cos4x/4+c
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  • 3 answers

Manglam Pandey 2 years, 6 months ago

Cos^2x-sin^2x

Tec Om 2 years, 6 months ago

product rule lagao 1st d/dx of2nd +2nd d/dx of 1st then aa jayega -sin^2x +cosx^2 that is cos2x

Dhruv Shukla 2 years, 6 months ago

Cos2x
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  • 0 answers
  • 0 answers
  • 1 answers

Aryan Aryan 2 years, 6 months ago

Iska differentiation karna hai kya
  • 1 answers

S Abhishek Kumar 2 years, 6 months ago

all real number except 0
  • 1 answers

Waheguru Ji Ji 2 years, 7 months ago

Y
  • 0 answers

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