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Yogita Ingle 5 years, 4 months ago
- An oxidation-reduction (redox) reaction is a type of chemical reaction that involves a transfer of electrons between two species. An oxidation-reduction reaction is any chemical reaction in which the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron.
- The formation of hydrogen fluoride is an example of a redox reaction. We can break the reaction down to analyze the oxidation and reduction of reactants. The hydrogen is oxidized and loses two electrons, so each hydrogen becomes positive.
H2+2F→2HF
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Gaurav Seth 5 years, 4 months ago
The amorphous solids are called as super cooled liquid which allows molecules in the material to continue to move but in very very less large time and as it does not form a crystalline structure , or we can say they have a tendency to flow like liquids that's why they are called as pseudo solids or supercooled liquids.
Yogita Ingle 5 years, 4 months ago
The amorphous solids are called as super cooled liquid which allows molecules in the material to continue to move but in very very less large time and as it does not form a crystalline structure , or we can say they have a tendency to flow like liquids that's why they are called as pseudo solids or supercooled liquids.
Posted by Yash Bhadauria 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
The Order of reaction refers to the relationship between the rate of a chemical reaction and the concentration of the species taking part in it. In order to obtain the reaction order, the rate expression (or the rate equation) of the reaction in question must be obtained.
In order to determine the reaction order, the power-law form of the rate equation is generally used. The expression of this form of the rate law is given by r = k[A]x[B]y.
In the expression described above, ‘r’ refers to the rate of reaction, ‘k’ is the rate constant of the reaction, [A] and [B] are the concentrations of the reactants. The exponents of the reactant concentrations x and y are referred to as partial orders of the reaction. Therefore, the sum of all the partial orders of the reaction yields the overall order of the reaction.
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Yogita Ingle 5 years, 4 months ago
Methods of Preparation of haloalkanes
- By halogenations of alkanes in presence of light, catalyst or heat:

- By halogenations of alkenes with HX :

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Yogita Ingle 5 years, 4 months ago
Markovnikov proposed a rule called Markovnikov rule for the prediction of major product in the electrophilic addition of unsymmetrical alkenes. According to Markovnikov rule, the negative part of the adding molecule gets attached to that carbon atom which possesses a lesser number of hydrogen atoms.
Posted by Navdeep Kaur Thind 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
A volatile solute produces vapour at the boiling point of the solution. At the same temperature, they have higher vapour pressure than non-volatile solutes.
Examples: Alcohol, ether, mercury, and gasoline.
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Gaurav Seth 5 years, 4 months ago
Henry law states whenever solid is dissolved in liquid or gas is dissolved in liquid its solubility is determined by pressure and temperature. it states that partial pressure is directly proportional to mole fraction. ie . p=khx where kh is Henry law constant. Raoult law states that when two volatile liquid are mixed their vapour pressure is directly proportional to mole fraction ie p1 = p*1 x
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Yogita Ingle 5 years, 4 months ago
Melting point from nitrogen to arsenic increases & from arsenic it decreases upto bismuth because down the group as the size of the element increases the tendency of elements to form three covalent bonds increases (inert pair effect).Thus, there are weak forces of attraction between their atoms in solid state leading to lowering in melting point.
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Yogita Ingle 5 years, 4 months ago
Adsorption is a process which involves the accumulation of a substance in molecular species in higher concentration on the surface. If we look at Hydrogen, Nitrogen and Oxygen, these gases adsorb on activated charcoal. Meanwhile, we have to note that adsorption is different from absorption. The two processes involve totally different mechanisms.
For the adsorption process, two components are required,
- Adsorbate: Substance which is deposited on the surface of another substance. For example, H2, N2 and O2 gases.
- Adsorbent: Surface of a substance on which adsorbate adsorbs. For example, Charcoal, Silica gel, Alumina.
Posted by Simran Sandhu 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
Crystalline solids can be classified into different categories depending upon the type of constituent particles and the nature of attractive forces operating between them.
Atomic Solid: In these solids the constituent particles are atoms. These closely packed atoms are held up by London dispersion forces. Some examples are crystals of noble gases. Such solids are very soft, possess very low melting points and poor conductors of heat and electricity.
Molecular Solids: In these solids, the constituent particles which pack up together are molecules of the substance. These molecules may be non – polar (dipole moment = 0) such as etc. or they may be polar (dipole moment > 0) like etc.
Ionic Solids: In ionic solids, the constituent particles are ions of opposite charges. Each ion is surrounded by a definite number of ions of opposite charge.
Covalent Solids: In these types of solids the constituent particles are atoms of same or different elements connected to each other by covalent bond network.
Metallic Solids: In these type of solids, the constituent particles are metal atoms. The interparticle forces in these solids are metallic bonds. In the metallic crystals the metal atoms occupy the fixed positions but their valence electrons are mobile.
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Gaurav Seth 5 years, 4 months ago
Answer
(a) Molar mass of KI = 39 + 127 = 166 g mol - 1
20% (mass/mass) aqueous solution of KI means 20 g of KI is present in 100 g of solution.
That is,
20 g of KI is present in (100 - 20) g of water = 80 g of water
Therefore, molality of the solution = Moles of KI / Mass of water in kg
= 20/166 / 0.08 m
= 1.506 m
= 1.51 m (approximately)
(b) It is given that the density of the solution = 1.202 g mL - 1
∴Volume of 100 g solution = Mass / Density
= 100g / 1.202g mL-1
= 83.19 mL
= 83.19 × 10 - 3 L
Therefore, molarity of the solution = 20/166 mol / 83.19 × 10 - 3 L
= 1.45 M
(c) Moles of KI = 20/166 = 0.12 mol
Moles of water = 80/18 = 4.44 mol
Therefore, mole fraction of KI = Moles of KI / (Moles of KI + Moles of water)
= 0.12 / (0.12+4.44)
= 0.0263
1Thank You