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Yogita Ingle 4 years, 8 months ago
Denaturation of Proteins
• The most stable conformation of a protein at a given temperature and the pH is known as its native state.
• The loss of biological activity of proteins when a protein in its native form, is subjected to physical change like change in temperature or chemical change like change in pH, is called denaturation of protein.
• For example: (i) Coagulation of egg white on boiling, (ii) curdling of milk which is caused due to the formation of lactic acid by the lactobacillus bacteria present in milk.
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Posted by Piyush Barde 4 years, 9 months ago
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Ankit Baghel 4 years, 9 months ago
Yogita Ingle 4 years, 9 months ago
(i) Benzoic acid is a stronger acid than acetic acid due to the electron withdrawing effect of benzene ring which stabilizes the carboxylate anion while alkyl group destabilises the carboxylate anion due to electron donating nature.
(ii) Methanal is more reactive than ethanal towards Nucleophilic addition reaction due to steric and electronic reasons. Presence of methyl group in ethanal hinders the approach of nucleophile to carbonyl carbon than in methanal. Methyl group also reduces the electrophilicity of the carbonyl more effectively than in methanal.
Posted by Piyush Barde 4 years, 9 months ago
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Gaurav Seth 4 years, 9 months ago
Answer: 25%
Explanation: Isotonic solutions are those solutions which have the same osmotic pressure. If osmotic pressures are equal at the same temperature, concentrations must also be equal.
for non electrolytes such as urea
for electrolytes such as
= osmotic pressure
C= concentration
R= solution constant
T= temperature
i= vant hoff factor
For urea solution: 3 g of urea is dissolved in 100 ml of solution.
For solute A: 1.8 g of A is dissolved in 100 ml of solution.
As
0.25 0 0
Total moles after dissociation =
thus
Thus degree of dissociation is 25%.
Posted by Piyush Barde 4 years, 9 months ago
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Yogita Ingle 4 years, 9 months ago
In ZnO, Zn2 ions occupy the interstitial sites and electrons are trapped in the interstitial sites for neutralization. Crystals that show such type of defects are generally colored. Zinc oxide is white in color but on heating, it turns into yellowbecause it loses oxygen reversibly at high temperature.
Posted by Abhishek Joshi 4 years, 9 months ago
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Gaurav Seth 4 years, 9 months ago
a n s w e r
Aniline (ph−NH2) can be prepared from benzene using conc.H2SO4/conc.HNO3 followed by Sn/HCl as shown in the above image.
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ANSWER
Amines contains a lone pair of electrons on its nitrogen atom which is easily available for protonation. This is the cause of basic nature. Any other group which increases the electron density on nitrogen increases the basicity.
Posted by Rakesh Kumar 4 years, 9 months ago
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Yogita Ingle 4 years, 9 months ago
XeO3 is isostructural with BrO3- . (pyramidal structure)
Posted by Ritesh Paswan 4 years, 9 months ago
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Yogita Ingle 4 years, 9 months ago
Propanoyl chloride and propanoic acid can be differentiated by the chemical reactions given as below:
Propanoyl chloride reacts with few drops of water, to give hydrochloric acid and original carboxylic acid. On dipping blue litmus paper into it, it turns into red color.
On adding NaHCO3 , solution to each of them, propanoyl chloride will not react whereas propanoic acid will give brisk èfferevescence due to the evolution of CO2 .Read more on Sarthaks.com - https://www.sarthaks.com/919462/chemical-tests-distinguish-between-following-compounds-propanoyl-chloride-propanoic
Posted by Nikita Mittal 4 years, 9 months ago
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Posted by Mr. King 4 years, 9 months ago
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Gaurav Seth 4 years, 9 months ago
When the co-ordination compound is reacted with AgNO3 it liberates 2 moles of AgCl, which indicates 2 Cl- ions are outside the co-ordination sphere satisfying primary valence(+2).
- Remaining 6 H2O ligands will be inside the co-ordination sphere satisfying secondary valence (+6)
- Therefore, structural formula of the compound must be [Ni(H2O)6]Cl2.
Posted by Olina Shanglai 4 years, 9 months ago
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Gaurav Seth 4 years, 9 months ago
Q u e s t i o n : An element crystallizes in a fcc lattice with cell edge of 400 pm. The density of the element is 7 g cm-3. How many atoms are Present in 280 g of the element ?
A n s w e r :
Volume of the unit cell a3 = (400 pm)3
Yogita Ingle 4 years, 9 months ago
Step I. Calculation of mass of an atom of the elements
Let the mass of an atom of the element = m gram
Mass of the unit cell = 4×m=(4m)
Edge length (a)= 400 pm = 400pm ×10−10
Volume of the unit cell =(400×10−10cm)3=64×10−24cm3
Density of unit cell = 7 g cm−3
Density of unit cell =Mass of unit cellvolume of unit cell=Mass of unit cellvolume of unit cell
(7 g cm−3)=(4m)g/ (64×10−24cm3)
m=(7gcm−3)×(64×10−24cm3)/ 4=112×10−24g
Step II. Calculation of the number of atoms in 280 g of the element.
No. of atoms=Mass of the elementMass of one atom of the elementNo. of atoms=Mass of the elementMass of one atom of the element
=(280g)/(112×10−24g)=2.5×1024atoms
Posted by Niharika Singh 4 years, 9 months ago
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Gaurav Seth 4 years, 9 months ago
Due to smaller atomic size the density of lone pair electrons on N in NH3 is larger than that of P in PH3. So, NH3 is a stronger Lewis base than that of PH3.
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Yogita Ingle 4 years, 9 months ago
The radius ratio for AgBr is intermediate. Thus, it shows both frenkel and schottky defects.
The major defect in AgBr is the Frenkel defect. It has a rock salt structure i.e. CCP lattice of Br with atoms of Ag occupying all octahedral holes. Ag moves from octahedral to tetrahedral sites causing only cations to precipitate.
Schottky defect arise due to missing of ions from their lattice point and frenkel arise when the missing ions occupy interstitial sites.
in AgBr, Ag+ ion is small in size and when removed from lattice point they can occupy interstitial site and therefore show both frenkel and schottky defect. SCHOTTKY Defect in AgBr is exhibited due to precipitation of both Cations and Anions.
Posted by Hritik Aryan 4 years, 9 months ago
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Dinesh Kumar 4 years, 8 months ago
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