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  • 1 answers

Gaurav Seth 3 years, 11 months ago

a n s w e r

Aniline (ph−NH2​) can be prepared from benzene using conc.H2​SO4​/conc.HNO3​ followed by Sn/HCl as shown in the above image.

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  • 5 answers

Sneha Panwar 3 years, 11 months ago

Ankit Baghel can you pls post it here?????

Ankit Baghel 3 years, 11 months ago

Heyy plz you guys , if you can't help then don't discourage..... Be appreciate plz ?

Ankit Baghel 3 years, 11 months ago

If you have specific charts for named reactn and chapterwise reactn and distinguishing test ..... Then you can do it in 2-3 hours.... I have it but it unable to send it it will to you bcz of non-avaibility of options... U can do it bcz i had done whole chemistry in one day only. ......in this year's pre boards.

Sneha Panwar 3 years, 11 months ago

??

Prince Kumar 3 years, 11 months ago

You can revise Organic Chemistry in 1 Day if you have 72 Hours in Single Day.
  • 2 answers

Ankit Baghel 3 years, 11 months ago

Yess ...! Metallic character increase down the groupp.... So, tendency to lose electron increases .. Means +ve oxidation state is more stable down the group.

Atifa And Alveera Parveen 3 years, 11 months ago

Due to down the group matellic character increse.
  • 2 answers

Abhi Rana 3 years, 11 months ago

To determine basic strengths remove (OH)- ion from compound and check how much stable your carbocation is formed the more it is stable more basic strengths if OH group is not available in compound than remove( H+) more the stable carboanion is form more is acidic and lesser is basic strength

Jagdish Suthar 3 years, 11 months ago

When the effect like aromaticity resonance mesomeric hyperconjugation inductive are high then acidic strength increase then less acidic we call basic
  • 3 answers

Raja Yadav 3 years, 11 months ago

Two page answer is not a short question answer and this is the long question answer

Aditya Gupta 3 years, 11 months ago

Amines contains a lone pair of electrons on its nitrogen atom which is easily available for protonation. This is the cause of basic nature. Any other group which increases the electron density on nitrogen increases the basicity.

Gaurav Seth 3 years, 11 months ago

ANSWER
Amines contains a lone pair of electrons on its nitrogen atom which is easily available for protonation. This is the cause of basic nature. Any other group which increases the electron density on nitrogen increases the basicity.
 

  • 1 answers

Yogita Ingle 3 years, 11 months ago

XeO3 is isostructural with BrO3- . (pyramidal structure)  

  • 1 answers

Yogita Ingle 3 years, 11 months ago

Propanoyl chloride and propanoic acid can be differentiated by the chemical reactions given as below:

Propanoyl chloride reacts with few drops of water, to give hydrochloric acid and original carboxylic acid. On dipping blue litmus paper into it, it turns into red color.

On adding NaHCO3 , solution to each of them, propanoyl chloride will not react whereas propanoic acid will give brisk èfferevescence due to the evolution of CO2 .Read more on Sarthaks.com - https://www.sarthaks.com/919462/chemical-tests-distinguish-between-following-compounds-propanoyl-chloride-propanoic

  • 1 answers

Jeetu Thomas 3 years, 11 months ago

The reaction in which acidchlorid when treated with palladium in presence of Baso4 get hydrogenarated from aldyhide (This reaction is controlled)
  • 1 answers

Gaurav Seth 3 years, 11 months ago

 When the co-ordination compound is reacted with AgNO3 it liberates 2 moles of AgCl, which indicates 2 Cl- ions are outside the co-ordination sphere satisfying primary valence(+2).
- Remaining 6 H2O ligands will be inside the co-ordination sphere satisfying secondary valence (+6)
- Therefore, structural formula of the compound must be [Ni(H2O)6]Cl2.
 

  • 2 answers

Gaurav Seth 3 years, 11 months ago

Q u e s t i o n : An element crystallizes in a fcc lattice with cell edge of 400 pm.  The density of the element is 7 g cm-3. How many atoms are Present in 280 g of the element ?

A n s w e r :

Volume of the unit cell a3 = (400 pm)3 

Yogita Ingle 3 years, 11 months ago

 

Step I. Calculation of mass of an atom of the elements
Let the mass of an atom of the element = m gram
Mass of the unit cell = 4×m=(4m) 
Edge length (a)= 400 pm = 400pm ×10−10 
Volume of the unit cell =(400×10−10cm)3=64×10−24cm3
Density of unit cell = 7 g cm−3 
Density of unit cell =Mass of unit cellvolume of unit cell=Mass of unit cellvolume of unit cell
(7 g cm−3)=(4m)g/ (64×10−24cm3
m=(7gcm−3)×(64×10−24cm3)/ 4=112×10−24
Step II. Calculation of the number of atoms in 280 g of the element.
No. of atoms=Mass of the elementMass of one atom of the elementNo. of atoms=Mass of the elementMass of one atom of the element
=(280g)/(112×10−24g)=2.5×1024atoms

  • 1 answers

Gaurav Seth 3 years, 11 months ago

Due to smaller atomic size the density of lone pair electrons on N in NH3 is larger than that of P in PH3. So, NH3 is a stronger Lewis base than that of PH3.

  • 2 answers

Jassi Midha 3 years, 11 months ago

P and As act as ligads because they can form dπ-dπ bond ' d block elements are known as transition metals' with variable oxidation state so with having various oxidation state the act as ligand.

Vishal Tiwari 3 years, 11 months ago

Nahi malum
  • 2 answers

Jassi Midha 3 years, 11 months ago

For diagram see page no. 293 of ncert chemistry part II. the incoming nucleophile interact with alkyl halide causing the C-Cl bond to break while forming a new C-OH bond. Process take simultaneously in a single step. The configuration of carbon atom attack of nucleophile is much the same way an umbrella is turned inside out when caught in a strong wind while the leaving group is pushed away - called inversion of configuration.

Drishty Kamboj 3 years, 11 months ago

Can i ask if the ques is from syllabus?
  • 1 answers

Khushi Gupta 3 years, 11 months ago

Cl- is an neuclophile while cl2 is just stable with its octet...it shows no such character as electrophile or neuclophile
  • 2 answers

Student Of The Year 3 years, 11 months ago

Due to precipitation of both ion. Since Ag+ ion is small in size they leave own lattice site and occupied interstitial site, so it show both defect. Or, the size of cation and anion are intermediate.

Yogita Ingle 3 years, 11 months ago

The radius ratio for AgBr is intermediate. Thus, it shows both frenkel and schottky defects.

The major defect in AgBr is the Frenkel defect. It has a rock salt structure i.e. CCP lattice of Br with atoms of Ag occupying all octahedral holes. Ag moves from octahedral to tetrahedral sites causing only cations to precipitate.

Schottky defect arise due to missing of ions from their lattice point and frenkel arise when the missing ions occupy interstitial sites.

in AgBr, Ag+ ion is small in size  and when removed from lattice point they can occupy interstitial site  and therefore show both frenkel and schottky defect. SCHOTTKY Defect in AgBr is exhibited due to precipitation of both Cations and Anions.

  • 1 answers

Radhika Kaushal 3 years, 11 months ago

The electrical potential difference developed between metal and its ions is electrode potential.
  • 3 answers

Harsh Mishra 3 years, 11 months ago

This is what I always say to these teachers, but u know they're just copy machines. They don't care they just report..

Hritik Aryan 3 years, 11 months ago

Yogita Yaar google s copy nhi krna tha

Yogita Ingle 3 years, 11 months ago

The following expression is used to mathematically represent molar conductivity.

Λm = K / C

Where K is the specific conductivity and c is the concentration in mole per litre.

In general, the molar conductivity of an electrolytic solution is the conductance of the volume of the solution containing a unit mole of electrolyte that is placed between two electrodes of unit area cross-section or at a distance of one-centimeter apart.

The unit of molar conductivity is S⋅m2⋅mol-1.

  • 3 answers

Jassi Midha 3 years, 11 months ago

Deleted question of chapter 5 are: 7, 13,16,17,18,19,20,21,22,24. Because emulsion and enzymes are also deleted from syllabus

Drishty Kamboj 3 years, 11 months ago

Yeah whole of catalyst topic has been deleted and questions which are based on this topic too...

Tanya ?? 3 years, 11 months ago

Hanji catalysis pura delete ho gya h pr mujhe exercise k questions ka nhi pta konse konse dlt honge...
  • 2 answers

Drishty Kamboj 3 years, 11 months ago

Ac to ques M/10 means 0.1M sol now for 0.1moles per 1 l of sol,we have to calculate no. Of moles for 250 ml of sol ie 0.1/4 Let it be x(0.1/4 =x) This x is the no. Of moles of hcl in 250 ml of sol We have to calculate the mass of this x Mass of 1 mol of hcl =36.5 Mass of x=36.5*x

Yogita Ingle 3 years, 11 months ago

  • 2 answers

Drishty Kamboj 3 years, 11 months ago

Vant hoff factor has been deleted this year....i guess

Sonali Baral 3 years, 11 months ago

"i" is the van't hoff factor, then ΔTb​=iKb​×m (100.975−100)=i×0.52×164×101.23​×1000 i=123×0.520.975×164​=2.5 Now if x is the degree is dissociation, then  Ca(NO3​)2​⇋ Ca2++ 2NO3−​ 1                         0             0:       Initially  1−x                  x             2x:  At eqbm. ∴i=11−x+x+2x​=11+2x​=2.5⇒x=0.75 ∴ Percentage dissociation =75%
  • 1 answers

Yogita Ingle 3 years, 11 months ago

The reaction involved is,
Na2​CO3​ + HCl → NaCl + NaHCO3
Equivalent mass of Na2​CO3​= 106/1 ​= 106.

  • 2 answers

Drishty Kamboj 3 years, 11 months ago

Now can anyone answer why is Iodine a better leaving group if it has higher boiling point

K S 3 years, 11 months ago

As the size and mass of halogen atom increases,there is an increase in the magnitude of van der waal's forces due to which the boiling point increases down the group.
  • 2 answers

Tanya ?? 3 years, 11 months ago

At equilibrium.

Yogita Ingle 3 years, 11 months ago

At equilibrium

ECell​=0 

Therefore according to the formula, Δr​G = −nFECell​
Δr​G=0

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