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Posted by Jai Kishan Choudhary 6 years, 6 months ago
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Yogita Ingle 6 years, 6 months ago
- Sodium chloride or salt is used to clear snow on roads and is also used in ice creams i.e. to keep it solid. In both the cases, the salt works by lowering the melting or freezing point of water.
- Salt melts ice by lowering the freezing point of the water around the ice. The ice melts because we are introducing dissolved foreign particles into the water. The freezing point of water becomes lower and this is called freezing point depression. The ice is unable to re-freeze except at a much lower temperature.
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Yogita Ingle 6 years, 6 months ago
Evaporation causes cooling. This is based on the fact that when a liquid evaporates, it takes (or draws) the latent heat of vaporization from "another matter" which it touches. This "another mater looses" heat and gets cooled. This is how evaporation causes cooling.
E.g.- When perfume falls on our hand, our hand feels cool because perfume is a volatile liquid and gets evaporated rapidly taking away the latent heat of vaporization from our hand.
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Sia ? 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
Mathematical expression for Kohlrausch's law is
{tex}\Lambda _m^\infty{/tex} or {tex}{\mu ^\infty }{/tex} = Molar conductance at infinite dilution
{tex}= m\lambda _ + ^\infty + n\lambda _ - ^\infty{/tex}
Where m and n are number of ions formed.
Posted by Janhavi Bover 6 years, 6 months ago
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Gaurav Seth 6 years, 6 months ago
Lactic acid is a fairly common and simple example of optical isomerism. The (+) enantiomer of lactic acid is found in muscle. ... The positions of the hydroxyl groups on other chiral molecules can be compared with glyceraldehyde to see if they are the D-enantiomer or the L-enantiomer.
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Gaurav Seth 6 years, 6 months ago
They belong to cationic detergents. E.g., Cetyltrimethyl-ammonium bromide.
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Sia ? 6 years, 6 months ago
{tex}E_{(Cu^{2+}/Cu)}^\Theta=0.34V {/tex} and {tex}E_{(Ag^+/Ag)}^\Theta=0.80V {/tex}
Standard emf of Cu is less than Ag, therefore it is strong reducing agent and is oxidised. Therefore Cu acts as Anode and Ag acts as Cathode.
Half cell reactions are:
At Cathode (Reduction):
{tex}2Ag^+(aq)+2e^-\rightarrow2Ag(s){/tex}
At Anode (Oxidation):
{tex}Cu(s)\rightarrow Cu^{2+}(aq)+2e^- {/tex}
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Gullu Singh 6 years, 6 months ago
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