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  • 5 answers

Khuskaran Sidhu 6 years ago

Kappa is for specific Conductivity

Khuskaran Sidhu 6 years ago

Delta m (^m)

Jahnvi Sharma 6 years ago

Kappa(k) is the symbol

Diksha Mittal 6 years ago

Kappa(k)

Baibhav Binay 6 years ago

Kappa
  • 3 answers

Sivan Karthick 6 years ago

To check CHO group is present in compound or not

Jd Chouhan 6 years ago

R CHO+ Ag[(NH3)2]+1 = RCoo-

Leo Arockiasamy 6 years ago

Observation is silver mirror is obtained.
  • 1 answers

Dhruv Agrawal 6 years ago

Gabriel pthalimide synthesis
  • 0 answers
  • 2 answers

Pragati Gola 6 years ago

Water + Alcohol sol

Harshit Solanki 6 years ago

Solution in which water and ethanol are mixed to form solvent
  • 2 answers
Thank you ?

Yogita Ingle 6 years ago

Step 1: Preparation of sulphur dioxide:

SO2 is prepared by burning sulphur in the presence of excess air so that the product combines with oxygen which is helpful for the next stage.

S(s) + O2 (g) → SO2(g)

Step 2: Preparation of sulphur trioxide:

Sulphur trioxide is formed when sulphur dioxide reacts with oxygen in a ratio of 1:1 at a temperature of 400°C – 450°C and a pressure of 1-2 atm in the presence of N2O5 as a catalyst. This reaction is reversible in nature.

2SO2(g) + O2(g) ⇌ 2SO3(g)

Step 3: Preparation of concentrated sulphuric acid:

The sulphur trioxide formed is first made to react with concentrated sulphuric acid. Sulphur trioxide cannot be dissolved in water directly as it leads to the formation of fog. The product obtained after this reaction is known as oleum. The oleum obtained is then dissolved in water to obtain concentrated sulphuric acid.

H2SO4 + SO3(g) → H2S2O7(l)

H2S2O7(l) + H2O(l) → 2H2SO4

  • 1 answers

Yogita Ingle 6 years ago

 

CO2 is linear because carbon is sp-hybridised. CO2 is linear because carbon is sp-hybridised.

  • 2 answers

Shruti Kamal 6 years ago

No

Khuskaran Sidhu 6 years ago

But the revision of ur syllabus u do during pre-boards matters ?
  • 2 answers

Sayanipa Ghosh 6 years ago

I will not have to give my compartment exam

Shruti Kamal 6 years ago

Are you wondering that u appear in compartment , overall 3 months are left u can do much better in chemistry in these month,and there is no need to be appear in compartment
  • 1 answers

Sumit Sharma 6 years ago

Adding halogen and showing the electron leaving the 1 compound to other
  • 6 answers

Laxmi Sharma 6 years ago

Thanku everyone for your suggestion ??

Ravi Sinhmar 6 years ago

You can learn rxn by writing practice only

Rahul Sharma 6 years ago

Make a chart of naming formula and past on front of you

..... ... 6 years ago

Hlo

Mounish Varma 6 years ago

Practice can make u perfect

..... ... 6 years ago

First u learn important rxns.. Then mechanism U learn in different parts
  • 2 answers

Prafful Agrawal 6 years ago

Dear.. Cbse has removed solid state chapter this year..

..... ... 6 years ago

???
  • 1 answers

Abhimanyu Kaul 6 years ago

First draw the resonance structure of both . As we know that is resonance the negative charges goes to the alternate C atoms....so in case of o-amino phenol the NH2 shows +R effect and gives its electrons to the ring and the -ve charges goes to the C atom attached to OH grp and therefore electrons move to OH grp, it increases electron density on OH grp and therefore it is difficult to release H+ ion and hence less acidic While in case of m-amino phenol the the NH2 shows +R and in this case the electrons will not go to the C atom attached to OH grp ...else it will go to the next C atom ( as alternate C atoms will get -ve charge) ...and therefore electron density will not increase on OH grp and it will be easy to release H ion and hence more acidic I also had the same doubt before and i hope you got your doubt solved!
  • 1 answers

Yogita Ingle 6 years ago

Cannizzaro reaction: Aldehydes having no α-hydrogen atoms undergo self oxidation and reduction (disproportionation) reactions on treatment with a concentrated alkali. In such reactions, one molecule of aldehyde gets oxidised to form an acid and the other molecule of aldehyde gets reduced to form an alcohol.

For example, two molecules of formaldehyde, in the presence of concentrated NaOH, produce methanol and sodium formate.

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  • 2 answers

Amol Gùpta 6 years ago

Thanks

Yuvraj Singh 6 years ago

Hemoglobin , amylase , insulin
  • 1 answers

Yogita Ingle 6 years ago

<div>Л = CRT
or C = Л/RT
Л = 7.2 atm
R = 0.0821 L atm K-1 mol-1
T = 37°C = 37 + 273 = 310 K.
Molar concentration (C) = (7.2 atm)/(0.082L Latm K-1mol-1 ) x (310 K)
= 0.283 mol-1
= 0.283 M. Read more on Sarthaks.com - https://www.sarthaks.com/240928/molar-concentration-solute-particles-human-blood-osmotic-pressure-normal-temperature</div>
  • 2 answers

Yogita Ingle 6 years ago

Oxidation States of lanthanoids

  • The elements belonging to lanthanide series exhibit an oxidation state of +3. For example, Praseodymium (Pr) shows +3 oxidation state.
  • Some elements exhibit +2 oxidation states in their complexes in solutions. For example, Samarium (Sm), Europium (Eu), Thulium (Tm) and Ytterbium (Yb) show +2 oxidation state.
  • Some elements exhibit +4 oxidation states due to high stability of empty, half-filled or fully filled f-subshells.
  • Praseodymium (Pr), Neodymium (Nd), Terbium (Tb) and Dysprosium (Dy) exhibits +4 oxidation state in their oxides.
  • Cerium (Ce) shows both +3 as well as +4 state.

Akshat Nautiyal 6 years ago

+2,+3
  • 1 answers

Parth Gupta 6 years ago

Tollens react with aldehyde but doesnt react with ketpne
  • 1 answers
Charge present on any atom, molecule or ion. Ex. Oxidation state of Cu is 0, Cu^2+ is +2, Cl^1- is -1 and [Ag(NH3)2]^+ is+1 The oxi state of any atom in its elementary state is always zero (Cu→0)
  • 1 answers

Adi Kumar 6 years ago

Three methods of preparation of ethers

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