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  • 5 answers

Khuskaran Sidhu 6 years, 3 months ago

Kappa is for specific Conductivity

Khuskaran Sidhu 6 years, 3 months ago

Delta m (^m)

Jahnvi Sharma 6 years, 3 months ago

Kappa(k) is the symbol

Diksha Mittal 6 years, 3 months ago

Kappa(k)

Baibhav Binay 6 years, 3 months ago

Kappa
  • 3 answers

Sivan Karthick 6 years, 3 months ago

To check CHO group is present in compound or not

Jd Chouhan 6 years, 3 months ago

R CHO+ Ag[(NH3)2]+1 = RCoo-

Leo Arockiasamy 6 years, 3 months ago

Observation is silver mirror is obtained.
  • 1 answers

Dhruv Agrawal 6 years, 3 months ago

Gabriel pthalimide synthesis
  • 0 answers
  • 2 answers

Pragati Gola 6 years, 3 months ago

Water + Alcohol sol

Harshit Solanki 6 years, 3 months ago

Solution in which water and ethanol are mixed to form solvent
  • 2 answers

Anjana Narayanan A 6 years, 3 months ago

Thank you ?

Yogita Ingle 6 years, 3 months ago

Step 1: Preparation of sulphur dioxide:

SO2 is prepared by burning sulphur in the presence of excess air so that the product combines with oxygen which is helpful for the next stage.

S(s) + O2 (g) → SO2(g)

Step 2: Preparation of sulphur trioxide:

Sulphur trioxide is formed when sulphur dioxide reacts with oxygen in a ratio of 1:1 at a temperature of 400°C – 450°C and a pressure of 1-2 atm in the presence of N2O5 as a catalyst. This reaction is reversible in nature.

2SO2(g) + O2(g) ⇌ 2SO3(g)

Step 3: Preparation of concentrated sulphuric acid:

The sulphur trioxide formed is first made to react with concentrated sulphuric acid. Sulphur trioxide cannot be dissolved in water directly as it leads to the formation of fog. The product obtained after this reaction is known as oleum. The oleum obtained is then dissolved in water to obtain concentrated sulphuric acid.

H2SO4 + SO3(g) → H2S2O7(l)

H2S2O7(l) + H2O(l) → 2H2SO4

  • 2 answers

Ravi Sinhmar 6 years, 3 months ago

Yes

Greeshma Suresh 6 years, 3 months ago

Most probably
  • 1 answers

Yogita Ingle 6 years, 3 months ago

 

CO2 is linear because carbon is sp-hybridised. CO2 is linear because carbon is sp-hybridised.

  • 2 answers

Shruti Kamal 6 years, 3 months ago

No

Khuskaran Sidhu 6 years, 3 months ago

But the revision of ur syllabus u do during pre-boards matters ?
  • 2 answers

Sayanipa Ghosh 6 years, 3 months ago

I will not have to give my compartment exam

Shruti Kamal 6 years, 3 months ago

Are you wondering that u appear in compartment , overall 3 months are left u can do much better in chemistry in these month,and there is no need to be appear in compartment
  • 1 answers

Sumit Sharma 6 years, 3 months ago

Adding halogen and showing the electron leaving the 1 compound to other
  • 6 answers

Laxmi Sharma 6 years, 3 months ago

Thanku everyone for your suggestion ??

Ravi Sinhmar 6 years, 3 months ago

You can learn rxn by writing practice only

Rahul Sharma 6 years, 3 months ago

Make a chart of naming formula and past on front of you

..... ... 6 years, 3 months ago

Hlo

Mounish Varma 6 years, 3 months ago

Practice can make u perfect

..... ... 6 years, 3 months ago

First u learn important rxns.. Then mechanism U learn in different parts
  • 2 answers

Prafful Agrawal 6 years, 3 months ago

Dear.. Cbse has removed solid state chapter this year..

..... ... 6 years, 3 months ago

???
  • 1 answers

Abhimanyu Kaul 6 years, 3 months ago

First draw the resonance structure of both . As we know that is resonance the negative charges goes to the alternate C atoms....so in case of o-amino phenol the NH2 shows +R effect and gives its electrons to the ring and the -ve charges goes to the C atom attached to OH grp and therefore electrons move to OH grp, it increases electron density on OH grp and therefore it is difficult to release H+ ion and hence less acidic While in case of m-amino phenol the the NH2 shows +R and in this case the electrons will not go to the C atom attached to OH grp ...else it will go to the next C atom ( as alternate C atoms will get -ve charge) ...and therefore electron density will not increase on OH grp and it will be easy to release H ion and hence more acidic I also had the same doubt before and i hope you got your doubt solved!
  • 1 answers

Yogita Ingle 6 years, 3 months ago

Cannizzaro reaction: Aldehydes having no α-hydrogen atoms undergo self oxidation and reduction (disproportionation) reactions on treatment with a concentrated alkali. In such reactions, one molecule of aldehyde gets oxidised to form an acid and the other molecule of aldehyde gets reduced to form an alcohol.

For example, two molecules of formaldehyde, in the presence of concentrated NaOH, produce methanol and sodium formate.

  • 0 answers
  • 1 answers

Dev Arora 6 years, 3 months ago

Do ncert back excersice
  • 3 answers

Gurman Kaur 6 years, 3 months ago

Aa rha h

Deeya Singh 6 years, 3 months ago

Aa raha hai

Leo Arockiasamy 6 years, 3 months ago

Rha
  • 2 answers

Amol Gùpta 6 years, 3 months ago

Thanks

Yuvraj Singh 6 years, 3 months ago

Hemoglobin , amylase , insulin
  • 1 answers

Yogita Ingle 6 years, 3 months ago

<div>Л = CRT
or C = Л/RT
Л = 7.2 atm
R = 0.0821 L atm K-1 mol-1
T = 37°C = 37 + 273 = 310 K.
Molar concentration (C) = (7.2 atm)/(0.082L Latm K-1mol-1 ) x (310 K)
= 0.283 mol-1
= 0.283 M. Read more on Sarthaks.com - https://www.sarthaks.com/240928/molar-concentration-solute-particles-human-blood-osmotic-pressure-normal-temperature</div>
  • 0 answers
  • 2 answers

Deeya Singh 6 years, 3 months ago

It's 4

Priyanshu Verma 6 years, 3 months ago

5 hote h sayad yrr
  • 2 answers

Yogita Ingle 6 years, 3 months ago

Oxidation States of lanthanoids

  • The elements belonging to lanthanide series exhibit an oxidation state of +3. For example, Praseodymium (Pr) shows +3 oxidation state.
  • Some elements exhibit +2 oxidation states in their complexes in solutions. For example, Samarium (Sm), Europium (Eu), Thulium (Tm) and Ytterbium (Yb) show +2 oxidation state.
  • Some elements exhibit +4 oxidation states due to high stability of empty, half-filled or fully filled f-subshells.
  • Praseodymium (Pr), Neodymium (Nd), Terbium (Tb) and Dysprosium (Dy) exhibits +4 oxidation state in their oxides.
  • Cerium (Ce) shows both +3 as well as +4 state.

Akshat Nautiyal 6 years, 3 months ago

+2,+3
  • 1 answers

Parth Gupta 6 years, 3 months ago

Tollens react with aldehyde but doesnt react with ketpne
  • 1 answers

Anupam Chaurasiya 6 years, 3 months ago

Charge present on any atom, molecule or ion. Ex. Oxidation state of Cu is 0, Cu^2+ is +2, Cl^1- is -1 and [Ag(NH3)2]^+ is+1 The oxi state of any atom in its elementary state is always zero (Cu→0)
  • 1 answers

Adi Kumar 6 years, 3 months ago

Three methods of preparation of ethers

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