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  • 3 answers

Alok Mittal 2 years, 9 months ago

In simple we write only this Is because of resonance effect

Anjan Karthi 2 years, 10 months ago

Unlike those in alcohols, the -OH group in phenols are supported by a benzene ring that, through +R effect, provides greater electron density in the O atom. As a result, the oxygen atoms in phenols are more capable of stronger intermolecular hydrogen bonding with each other than alcohols, whose OH group is supported by alkyl group (-R effect). This, phenols have higher BP.

Harsh Sharma 2 years, 10 months ago

Loda bc
  • 1 answers

Yashi Kushwaha 2 years, 8 months ago

If you need oxidation number than it is 3 We consider Cr=x NH3 is neutral outside bracket we have 3 X+(0*6)=3 X+0=3 i.e X=3
  • 1 answers

Sushma Pandey 2 years, 10 months ago

Ph3C+ is most stable due to presence of three benzene rings which are resonance stabilised.although more compound are stable but this more srable
  • 1 answers

Preeti Dabral 2 years, 9 months ago

    1. Due to greater electronegativity of sp2 hybridised carbon to which carboxyl carbon is attached and greater resonance stabilization of carboxylate ion with the benzene ring, benzoic acid is a stronger acid than acetic acid.
    2. Methanal is more reactive towards nucleophilic addition reaction than ethanal because carbonyl carbon of methanal is more electrophilic than that of ethanol. Also, due to +I effect of methyl group in ethanal, reactivity of ethanal decreases.
  • 1 answers

Preeti Dabral 2 years, 9 months ago

The dual cell heat exchanger consists of two porous fluid zones, namely a primary zone and an auxiliary zone. The two zones are solved simultaneously and are coupled only through heat transfer.

  • 1 answers

Aniket . 2 years, 10 months ago

In physics
  • 3 answers

Akshatha E K 2 years, 10 months ago

Methyl

Ankush Dahiya 2 years, 10 months ago

Methyl group

Shalu Shrivastav 2 years, 10 months ago

Methyl group
  • 1 answers

Meemansha Srivastava 2 years, 11 months ago

As we go down the group the size of the atoms should increase. This trend is seen till 4d series. In 5d series the electrons fill in the penultimate shell i.e in the d subshell. The sheilding effect by the electrons in the d subshell is less than the attractive force between the electrons in the last subshell and the increasing nuclear charge. Thus the size of the atom reduces (This phenomenon is called as lanthanoid contraction). The expected increase in size of the 5d series is compensated by lanthanoid contraction and hence 4d and 5d series have almost the same size resulting them to have similar physical and chemical properties.
  • 1 answers

Kashu Verma 2 years, 10 months ago

Plz tell your question correctly 😃.
  • 2 answers

Anjan Karthi 2 years, 11 months ago

Molar mass of Ca(OH)2 = 40 + (1 + 16) × 2 = 40 + 34 = 74 g.// Therefore, Molarity = W/MV. V = W/M × Molarity = 29.6/2 × 74 = 0.2 L = 200 mL.//

Shubham Baba 2 years, 11 months ago

Which of the following is not correctly matched with its IUPAC name
  • 1 answers

Anshul Pratap Singh 2 years, 4 months ago

See ncert book 📚
  • 1 answers

Kashu Verma 2 years, 10 months ago

Solubility of H2S gas =0.195m 0.195 mole in 1kg of solvent= 1000g 1000/8=55.55moles Therefore, xH2S = 0.195/0.195+55.55=0.0035 Pressure at STP=0.987bar Applying Henry's law, PH2S=KH×XH2S KH=PH2S/XH2S= 0.987/0.0035=282bar...
  • 1 answers

Preeti Dabral 2 years, 9 months ago

{tex}\mathrm{H}_2 \mathrm{O} \rightarrow 2 \mathrm{H}^{+}+\frac{1}{2} \mathrm{O}_2+2 \mathrm{e}^{-}{/tex}

Oxidation of one mole of water will require 2×96500=1.93×105C.

  • 1 answers

Kanhaiya Saraswat 2 years, 11 months ago

Which show large negative deviation are of Maximum boiling Azeotrope
  • 4 answers

Akshatha E K 2 years, 10 months ago

Ethanal

Shalu Shrivastav 2 years, 10 months ago

Ethanal

Sachin Gupta 2 years, 11 months ago

Ethanal

Vishal Kaushik 2 years, 11 months ago

Methyl
  • 3 answers

Priyanshu Patel 2 years, 10 months ago

2 acetaldehyde

Ankush Dahiya 2 years, 10 months ago

Ethanal

Aniket . 2 years, 10 months ago

2 methal
  • 1 answers

Anjan Karthi 2 years, 11 months ago

(C2H5)2NH greater than (C2H5)3N greater than C2H5NH2.
  • 2 answers

Deeksha Yadav 2 years, 11 months ago

n is order of reaction

Deeksha Yadav 2 years, 11 months ago

R=kA ki power n K =R/A ki power n
  • 1 answers

Chinu Rana 2 years, 11 months ago

Galvanic cell
  • 1 answers

Preeti Dabral 2 years, 9 months ago

The relative stability of the +2 oxidation state increases on moving from top to bottom. This is because on moving from top to bottom, it becomes more and more difficult to remove the third electron from the d-orbital.

  • 3 answers

Naman Sharma 2 years, 11 months ago

EAN = atomic number - oxidation state × 2 coordination number

Mili Singh 2 years, 11 months ago

Effective Atomic Number

Anmol Tomar 2 years, 11 months ago

Jshshf
  • 1 answers

Preeti Dabral 2 years, 9 months ago

The boiling point of the solution is 273.41 k

 

GIVEN

Weight of urea = 6 grams

weight of Glucose = 9 grams.

Weight of water = 300 grams

 

TO FIND

The boiling point of the solution.

 

SoOLUTION

We can simply solve the given problem as follows-

 

To calculate the boiling point of the solution, we will apply the following formula -

 

∆Tₒ = Kb× b × i (eq 1)

 

Where,

∆Tₒ = boiling point elevation

Kb = ebullioscopic constant of the solvent ( kb = o.515 kg/mol)

b = molality of the solute

i = van't Hoff factor of solute ( since urea and glucose are non-ionic compounds, so, i= 1)

 

We know that,

 

Boiling point elevation is defined as :

 

ΔTₒ = T₁ - T ........(eq2)

 

where,

T₁ = boiling point of the solution

T = boiling point of the solvent (T = 273.15 k of water)

 

Now,

{tex}\begin{aligned} & \text { number of moles of urea }=\frac{\text { given weight of urea }}{\text { molar mass of urea }} \\ & = \\ & \frac{6}{60}=0.1 \text { moles } \\ & \text { number of moles of glucose }=\frac{\text { given weight of glucose }}{\text { molar mass of glucose }} \\ & =\frac{9}{180}=0.05 \text { moles } \\ & \text { Total moles of solute }=0.1+0.05=0.15 \text { moles } \\ & \text { molality of solute }(b)=\frac{\text { moles of solute }}{\text { mass of solvent in } \mathrm{kg}} \\ & b=\frac{0.15 \times 1000}{300} \\ & b=0.5 \mathrm{M} \end{aligned}{/tex}

putting the values in ( eq 1) we have

ΔTₒ = 0.512 × 0.5 × 1

ΔTₒ = 0.26 k

Now, putting the value of ΔTₒ in (eq 2)

ΔTₒ = T₁ - T

0.26 = T₁ - 273.15

T₁ = 273.15 + 0.26

T₁ = 273.41 k


Hence, The boiling point of the solution is 273.41 k

  • 1 answers

Neeraj Yadav 2 years, 11 months ago

What kr the chiral compound?give example
I
  • 1 answers

Kashu Verma 2 years, 10 months ago

What?????

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