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Intext 2.6

    • Posted by Jai Vignesh 1 year, 6 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Kashu Verma 1 year, 5 months ago

    Solubility of H2S gas =0.195m 0.195 mole in 1kg of solvent= 1000g 1000/8=55.55moles Therefore, xH2S = 0.195/0.195+55.55=0.0035 Pressure at STP=0.987bar Applying Henry's law, PH2S=KH×XH2S KH=PH2S/XH2S= 0.987/0.0035=282bar...

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