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  • 1 answers

Yashveer Sharma 1 year, 9 months ago

Hii
  • 0 answers
Cf
  • 0 answers
  • 2 answers

Aadyasha Giri 1 year, 9 months ago

Basically they will ask you questions from the project file that has been prepared by you... they will start questioning from that only further they will start asking for the topics from the chapter related to the project.

Akansha Rana 1 year, 10 months ago

From your books and project file by you . If he/she call in you group you know other one topic also And some question from lab manual that's it
  • 3 answers

Akhya Sahay 1 year, 9 months ago

Search on Youtube

Hishant Varshney 1 year, 10 months ago

Check in lab manual

Nrapendra Singh Kundoliya 1 year, 10 months ago

What is lanthanoid contraction
  • 1 answers

Anjan Karthi 1 year, 10 months ago

Molarity = W 2 × 1000 / M 2 × V = 9.8 × 1000 / (137 + 17 + 17) × 250 = 9.8 × 4 / 171 = 39.2 / 171 = 0.23 M. // Therefore, normality = Molarity × n-factor = 0.23 × 2 = 0.46 N. //
  • 2 answers

Yashveer Sharma 1 year, 9 months ago

Hi

Harshit Mishra 1 year, 9 months ago

Hii priya
  • 1 answers

Akk Mii 1 year, 10 months ago

are u taking about d2sp3?
  • 3 answers

Gurchetan Singh 1 year, 10 months ago

This equation defines the relation between the concentrations of an ion on either side of a membrane that it perfectly selective for that ion and the potential difference (voltage) that will be measured across that membrane under equilibrium conditions.

Urvashi Kalia 1 year, 10 months ago

E=E*cell-0.059/n log (anode pdt)/(cathode pdt)

Soumya Srivastava 1 year, 10 months ago

What is a solution
  • 1 answers

Preeti Dabral 1 year, 10 months ago

Cryolite is added to alumina as to lower the fusion temperature and make the mass good conductor of electricity.

  • 4 answers

Tanishka Sharma 1 year, 10 months ago

I don't know in which school you study

Yash Maheshwari 1 year, 10 months ago

Copy this link and you will get the structure in he form of image https://uploadnow.io/f/70w8G8n

Yash Maheshwari 1 year, 10 months ago

MJ170403 10 9 0 0 0 0 0 0 0 0999 V2000 -1.3272 0.5022 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -1.3158 1.3645 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -1.3272 -0.3227 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -2.1522 0.5022 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 0.3514 -0.3770 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 0.3891 1.5044 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 1.1292 0.5136 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -0.5022 0.5022 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -0.5361 1.4678 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 0.3785 0.5022 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 1 2 1 0 0 0 0 1 3 1 0 0 0 0 1 4 1 0 0 0 0 1 8 1 0 0 0 0 10 5 1 0 0 0 0 10 6 1 0 0 0 0 10 7 1 0 0 0 0 8 10 1 0 0 0 0 8 9 2 0 0 0 0 M END

Prashant Sher Yadavanshi 1 year, 10 months ago

Tanishaka Sharma ap mere school may padhti ho kya
  • 2 answers

Prashant Sher Yadavanshi 1 year, 10 months ago

Mujhe pat hay

Mukta Joshi 1 year, 10 months ago

Don't know
  • 0 answers
  • 1 answers

Anjan Karthi 1 year, 10 months ago

Electrolytic conductance is caused by the mobility of IONS in their AQUEOUS electrolytic solutions. But, electronic conductance is caused by the mobility of ELECTRONS within the lattices of METALS or other similar ELECTRONIC CONDUCTORS (like graphite).
  • 1 answers

Anjan Karthi 1 year, 10 months ago

The main reason for stability of carboxylate anion formed by acidic property of carboxylic acids is resonance. But, even under such stability there does exist a possibility that the carboxylic carbon have some residual deficit of negative charge (not actually positive charge) , and this may be caused by the +I effect of alkyl groups connected to the carbon. But, since formic acid has no alkyl group connected to the acid group, it is the stronger than acetic acid.
  • 4 answers

Ashutosh Mishra 1 year, 10 months ago

Hi

Hitanshu Mathur 1 year, 10 months ago

Hello

Anjan Karthi 1 year, 10 months ago

Chemically, an amino acid is a substituted methane molecule wherein three of the hydrogens around the central carbon are replaced by an amino group, an acid group and an alkyl group. Whether an amino acid is actually acidic, basic or neutral depends on the alkyl group. If the alkyl group has an amino substituent branch, the amino acid is basic, if the group has a - COOH substituent, the amino acid is acidic and if it has no other functional group, the amino acid is neutral. These amino acids undergo polymerisation to form heteropolymers known as proteins.

Sakshi Gupta 1 year, 10 months ago

Protein
  • 5 answers

Tanishka Sharma 1 year, 10 months ago

Alcohol which have OH group present and it has simple chain like structure and Phenols which have OH group in benzene

Nidhi Kumari 1 year, 10 months ago

OH group directly attach to the benzen ring known as phenol

Nidhi Kumari 1 year, 10 months ago

Alcohol which have OH group present and it has simple chain like structure

Alok Mittal 1 year, 10 months ago

Alcohols which have OH group in simple chain like structure And Phenols which have OH group in benzene

Yashi Kushwaha 1 year, 10 months ago

Alcohol has -OH GRP while phenols are benzene ring + -OH GROUP AT PARA POSITION
  • 1 answers

Preeti Dabral 1 year, 11 months ago

Amines are the derivative of amonia in which one two three replaced hydrogen of alkyl or aryl group

  • 1 answers

Anjan Karthi 1 year, 11 months ago

Using ascending paper chromatography
  • 3 answers

Tarni Jain 1 year, 11 months ago

Reducing sugar are those which can reduce tollen reagent and fehlings solution and non reducing are those which can'nt

Pranav Sharma 1 year, 11 months ago

Reducing sugar is carbohydrates with free aldehyde and ketone grp and can reduce tollen and fehling solution

Sameer Chauhan 1 year, 9 months ago

Reducing sugar are those sugar which reduces fehling's solution and tollen's reagent to metallic silver are called reducing sugar
  • 2 answers

Preeti Dabral 1 year, 11 months ago

  • First apply Hydroboration Oxidation.(B2H6/H2O2 OH-)
  • Give PCC (Pyridinium chlorochromate)
  • Now Give Grignard reagent(CH3MgBr), and then hydrolize(H3O+)
  • Now use t-BuO-K+ for a Hoffmann Elimination.
  • Now again Hydroboration oxidation.

You get the required product.

Anjan Karthi 1 year, 11 months ago

OR, we can do the conversion as follows too :- a) Anti Markovnikov addition of HBr. b) Nucleophilic substitution by KCN (we get butane nitrile). c) DIBAL-H addition to get pentanal from butane nitrile. d) Reduction to pentanol by LiAlH4
  • 1 answers

Preeti Dabral 1 year, 11 months ago

The low oxidation state chemistry of the seven lightest metallic elements is described, with an emphasis on the introduction of bulky ligands to provide sufficient kinetic stability to allow the synthesis of well-defined compounds, which are isolable under normal conditions of temperature and pressure.

  • 1 answers

Preeti Dabral 1 year, 11 months ago

Emulsifying agents act as surfactants that decrease the surface tension between the dispersed phase and the dispersion medium. Emulsifying agents stabilize the emulsion by forming an interfacial film between suspended particles and the medium. hence, stabilize the emulsion by adding the third component. For example, agar is an emulsifying agent used in food.

  • 1 answers

Ayan Khan 1 year, 11 months ago

jgdjkkk
  • 2 answers

Preeti Dabral 1 year, 11 months ago

To make the number of atoms of each element the same on both sides of the equation, multiply coefficients (the numbers in front of the formulas). The hydrogen and oxygen atoms are the easiest to balance last. Check your work by indicating the state of matter of the reactants and products.

Tushar Goswami 1 year, 11 months ago

Ji
  • 2 answers

Preeti Dabral 1 year, 11 months ago

Friedel Crafts alkylation reaction can be explained as the alkylation of an aromatic ring using an alkyl halide in presence of a strong Lewis acid which acts as a catalyst. In the following given reaction, AlCl3 is used as a catalyst and the aromatic ring taken is benzene.

Alok Mittal 1 year, 10 months ago

R-X + AgF ===> RF + AgX
  • 2 answers

Anjan Karthi 1 year, 11 months ago

It is Cr2+ (I AM SORRY, THE FIRST ANSWER I GAVE WAS WRONG.) When Cr 2+ gets oxidised, it becomes Cr 3+ which has a relatively more stable electronic configuration in complexes (3d3 ~ t2g3). So, it undergoes easy oxidation. So it can easily give away electrons and thus, is a strong reducing agent.

Anjan Karthi 1 year, 11 months ago

Fe3+
  • 1 answers

Sakshi Raj 1 year, 11 months ago

when aldehyde and ketone is reduced with hydrazine followed by heating with KOH in ethelene glycol form corresponding hydrocarbon(N2H2).

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