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Ask QuestionPosted by Aadya Singh 5 years ago
- 5 answers
Aseem Mahajan 5 years ago
<svg width="600" height="600"> <g transform="translate(100,100)"> <text id="TextElement" x="0" y="0" style="font-family:Verdana;font-size:24; visibility:hidden"> It's SVG! <set attributeName="visibility" attributeType="CSS" to="visible" begin="1s" dur="5s" fill="freeze" /> <animateMotion path="M 0 0 L 100 100" begin="1s" dur="5s" fill="freeze" /> <animateTransform attributeName="transform" attributeType="XML" type="rotate" from="-30" to="0" begin="1s" dur="5s" fill="freeze" /> <animateTransform attributeName="transform" attributeType="XML" type="scale" from="1" to="3" additive="sum" begin="1s" dur="5s" fill="freeze" /> </text> </g> Sorry, your browser does not support inline SVG. </svg> <svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink"> <rect x="10" y="10" height="110" width="110" style="stroke:#ff0000; fill: #0000ff"> <animateTransform attributeName="transform" begin="0s" dur="20s" type="rotate" from="0 60 60" to="360 60 60" repeatCount="indefinite" /> </rect> </svg>
Posted by Aseem Mahajan 5 years ago
- 3 answers
Aseem Mahajan 5 years ago
<svg width="50%" height="150px"> <g id="R1" transform="translate(250 250)"> <ellipse rx="100" ry="0" opacity=".3"> <animateTransform attributeName="transform" type="rotate" dur="7s" from="0" to="360" repeatCount="indefinite" /> <animate attributeName="cx" dur="8s" values="-20; 220; -20" repeatCount="indefinite" /> <animate attributeName="ry" dur="3s" values="10; 60; 10" repeatCount="indefinite" /> </ellipse> </g> <use xlink:href="#R1" transform="rotate(72 390 150)" /> <use xlink:href="#R1" transform="rotate(144 390 150)" /> <use xlink:href="#R1" transform="rotate(216 390 150)" /> <use xlink:href="#R1" transform="rotate(288 390 150)" /> </svg>
Posted by Priyanshu Bharti 5 years ago
- 3 answers
</a>Posted by Aadya Singh 5 years ago
- 3 answers
Aseem Mahajan 5 years ago
Aseem Mahajan 5 years ago
Aseem Mahajan 5 years ago
Posted by Aadya Singh 5 years ago
- 5 answers
Aseem Mahajan 5 years ago
Aseem Mahajan 5 years ago
<svg> <g> <circle cx="10" cy="10" r="10" fill="blue"></circle> <animateMotion path="M 0 0 V 130 H 280 Z" dur="4s" repeatCount="indefinite" /> </g> </svg>
Posted by Vivek Chavan 5 years ago
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Posted by Aseem Mahajan 5 years ago
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Posted by Royal Thakur ? 5 years ago
- 2 answers
Aseem Mahajan 5 years ago
Posted by Royal Thakur ? 5 years ago
- 3 answers
Aseem Mahajan 5 years ago
$$R = \sqrt{A^2 + B^2 + 2AB cos\theta}$$
Direction : $$tan \theta = \dfrac{Acos \theta}{B + A sin \theta}$$
Posted by Lakshy Sheokand 5 years ago
- 3 answers
Posted by Paavni Agarwal 5 years ago
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Aseem Mahajan 5 years ago
$$v = \int a dt$$
$$ v = \int 2t + 3t^2 $$
$$v = t^2 + t^3 + C_1$$
Now displacement :
$$x = \int v dt $$
$$x = \int t^2 + t^3 + C_1 \\ x = \dfrac{t^3}{3} + \dfrac{t^4}{4} + C_1 x + C_2$$
Posted by Anshika Mishra 5 years ago
- 1 answers
Meghna Thapar 5 years ago
Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases. Gravity is what holds our world together. However, gravity isn't the same everywhere on Earth. Gravity is slightly stronger over places with more mass underground than over places with less mass.
Posted by ? Kirtika 5 years ago
- 1 answers
Yogita Ingle 5 years ago
The dimension of thermal conductivity is M1L1T−3Θ−1, expressed in terms of the dimensions mass (M), length (L), time (T), and temperature (Θ).
Posted by Sajid Md 5 years ago
- 2 answers
Meghna Thapar 5 years ago
In physics and mathematics, the dimension of a mathematical space (or object) is informally defined as the minimum number of coordinates needed to specify any point within it. ... The concept of dimension is not restricted to physical objects. Dimensions are used in predicting unknown formulae by just studying how a certain body depends on base quantities and up to which extent. It makes measurement and study of physical quantities easier. We are able to identify or observe a quantity just because of its dimensions.
Posted by Royal Thakur ? 5 years ago
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? Kirtika 5 years ago
Priyanshu Bharti 5 years ago
Posted by Sridevi .V 5 years ago
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Posted by Aseem Mahajan 5 years ago
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Aseem Mahajan 5 years ago
Posted by Madhav Sharma 5 years ago
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Posted by Ritesh Singh 5 years ago
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Aseem Mahajan 5 years ago
a = $$\frac{d}{dt} 12t - 5$$
a = 12 m/s³ at every time means it >s constant
Posted by Aseem Mahajan 5 years ago
- 3 answers
Aseem Mahajan 5 years ago
Aseem Mahajan 5 years ago
Posted by ? ? 5 years ago
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Posted by Aseem Mahajan 5 years ago
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? ? 5 years ago
Aseem Mahajan 5 years ago
Posted by Aadya Singh 5 years ago
- 4 answers
Yogita Ingle 5 years ago
Newton’s laws of motion imply the relationship between an object’s motion and the forces acting on it. In the first law, we come to understand that an object will not change its motion unless a force acts on it. The second law states that the force on an object is equal to its mass times its acceleration. And, finally, the third law states that for every action, there is an equal and opposite reaction.
Posted by Aseem Mahajan 5 years ago
- 5 answers
Aseem Mahajan 5 years ago
Posted by Aadya Singh 5 years ago
- 5 answers
Aseem Mahajan 5 years ago
Aadya Singh 5 years ago
yhaa pe to khush lag rhee... Phir brainly pe hamesha rote kyu the?? ????
Posted by Aseem Mahajan 5 years ago
- 5 answers
Posted by Aadya Singh 5 years ago
- 5 answers
Posted by Aadya Singh 5 years ago
- 2 answers
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Aadya Singh 5 years ago
1Thank You